Category: Algebra

Question Number 155653 by mathdanisur last updated on 03/Oct/21 $$\mathrm{if}\mathrm{a};\mathrm{b};\mathrm{c}⩾0\mathrm{and}\mathrm{a}+\mathrm{b}+\mathrm{c}=1\mathrm{prove}\mathrm{that}$$$$18\mathrm{\Sigma }\mathrm{ab}+45\mathrm{\Sigma }{\mathrm{a}}^2\mathrm{b}⩽11$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 90103 by A8;15: last updated on 21/Apr/20 Commented by john santu last updated on 21/Apr/20 $$translate$$ Terms of Service Privacy Policy…

Question Number 90097 by jagoll last updated on 21/Apr/20 $${\left(\sqrt{3+\sqrt{8}}\right)}^{\mathrm{x}}+{\left(\sqrt{3-\sqrt{8}}\right)}^{\mathrm{x}}=6$$ Commented by john santu last updated on 21/Apr/20 $$(3+\sqrt{8})(3-\sqrt{8})=1$$$$\mathrm{3}−\sqrt{\mathrm{8}}\:=\:\frac{\mathrm{1}}{\mathrm{3}+\sqrt{\mathrm{8}}}\:…

Question Number 155621 by mathdanisur last updated on 02/Oct/21 Answered by ghimisi last updated on 03/Oct/21 $$\frac{a+b+c}{6}=1\Rightarrow$$$${\left(\frac{a+d}{a}\right)}^{\frac{a}{6}}{\left(\frac{b+e}{b}\right)}^{\frac{b}{6}}{\left(\frac{c+f}{c}\right)}^{\frac{c}{6}}⩽\frac{a}{6}\cdot \frac{a+d}{a}+\frac{b}{6}\cdot \frac{b+e}{b}+\frac{c}{6}\cdot \frac{c+f}{c}=2\Rightarrow$$$$\left(\frac{{a}+{d}}{{a}}\right)^{{a}} \left(\frac{{b}+{c}}{{b}}\right)^{{b}}…

Question Number 90086 by I want to learn more last updated on 21/Apr/20 Commented by I want to learn more last updated on 21/Apr/20 $$\mathrm{Ohh},\:\:\mathrm{i}\:\mathrm{grab}…