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Category: Algebra

x-1-4-x-2-3-x-3-2-

Question Number 87093 by M±th+et£s last updated on 02/Apr/20 $$\lfloor\frac{{x}−\mathrm{1}}{\mathrm{4}}\rfloor+\lfloor\frac{{x}−\mathrm{2}}{\mathrm{3}}\rfloor=\lfloor\frac{{x}−\mathrm{3}}{\mathrm{2}}\rfloor \\ $$ Commented by M±th+et£s last updated on 02/Apr/20 $${slove}\:{the}\:{equation} \\ $$ Commented by MJS…

Solve-for-real-numbers-1-x-1-2-x-2-3-x-3-4-x-4-2x-2-5x-4-

Question Number 152626 by mathdanisur last updated on 30/Aug/21 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\frac{\mathrm{1}}{\mathrm{x}-\mathrm{1}}\:+\:\frac{\mathrm{2}}{\mathrm{x}-\mathrm{2}}\:+\:\frac{\mathrm{3}}{\mathrm{x}-\mathrm{3}}\:+\:\frac{\mathrm{4}}{\mathrm{x}-\mathrm{4}}\:=\:\mathrm{2x}^{\mathrm{2}} -\mathrm{5x}-\mathrm{4} \\ $$ Answered by MJS_new last updated on 30/Aug/21 $${x}=\mathrm{0} \\ $$$${x}=\frac{\mathrm{5}}{\mathrm{2}}…

Question-152596

Question Number 152596 by liberty last updated on 30/Aug/21 Answered by som(math1967) last updated on 30/Aug/21 $$\boldsymbol{{let}}\:\frac{\mathrm{3}\boldsymbol{{x}}+\boldsymbol{{y}}}{\mathrm{4}\boldsymbol{{y}}+\mathrm{3}}=\frac{\mathrm{4}\boldsymbol{{y}}+\mathrm{1}}{\mathrm{9}}=\frac{\mathrm{11}}{\mathrm{3}\boldsymbol{{x}}+\boldsymbol{{y}}}=\boldsymbol{{k}} \\ $$$$\left[\because\boldsymbol{{a}}=\boldsymbol{{b}}=\boldsymbol{{c}}\right] \\ $$$$\mathrm{3}\boldsymbol{{x}}+\boldsymbol{{y}}=\boldsymbol{{k}}\left(\mathrm{4}\boldsymbol{{y}}+\mathrm{3}\right) \\ $$$$\mathrm{4}\boldsymbol{{y}}+\mathrm{1}=\mathrm{9}\boldsymbol{{k}} \\ $$$$\mathrm{11}=\boldsymbol{{k}}\left(\mathrm{3}\boldsymbol{{x}}+\boldsymbol{{y}}\right)…

what-are-the-roots-of-the-system-of-equation-x-y-y-x-1-4-3-and-x-y-xy-5-

Question Number 87050 by jagoll last updated on 02/Apr/20 $$\mathrm{what}\:\mathrm{are}\:\mathrm{the}\:\mathrm{roots}\:\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{system}\:\mathrm{of}\:\mathrm{equation}\:\frac{\mathrm{x}}{\mathrm{y}}+\frac{\mathrm{y}}{\mathrm{x}+\mathrm{1}}\:=\:\frac{\mathrm{4}}{\mathrm{3}} \\ $$$$\mathrm{and}\:\mathrm{x}+\mathrm{y}\:+\:\mathrm{xy}\:=\:\mathrm{5}\:? \\ $$ Commented by john santu last updated on 02/Apr/20 $$\Rightarrow{x}+{y}+{xy}+\mathrm{1}\:=\:\mathrm{6}\:\Rightarrow{x}\left({y}+\mathrm{1}\right)=\mathrm{5}−{y}…