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Category: Algebra

Find-1-03-200-

Question Number 208187 by hardmath last updated on 07/Jun/24 Find:1,03200=? Answered by Ghisom last updated on 07/Jun/24 $$=\mathrm{10}^{\mathrm{200log}\:\mathrm{1}.\mathrm{03}} \approx\mathrm{10}^{\mathrm{200}×.\mathrm{012837}} \approx\mathrm{10}^{\mathrm{2}.\mathrm{5675}} \approx\mathrm{369}.\mathrm{36} \

Question-208199

Question Number 208199 by efronzo1 last updated on 07/Jun/24 Answered by Frix last updated on 07/Jun/24 y=18+3xx2isasemicirclewithr=92x+3+6xhasthemaximum(3232)Wehave2solutionsfor0m<324and$$\mathrm{exactly}\:\mathrm{one}\:\mathrm{solution}\:\mathrm{at}\:{m}=\frac{\mathrm{3}\sqrt{\mathrm{2}}}{\mathrm{4}} \

Solve-for-x-x-2-x-2-1-x-2-x-2-1-x-2-2-x-2-1-x-2-3-x-2-1-x-2-100-1-

Question Number 208164 by Fridunatjan08 last updated on 06/Jun/24 Solveforx:$${x}^{\mathrm{2}} +{x}^{\mathrm{2}} \left(\mathrm{1}−{x}^{\mathrm{2}} \right)+{x}^{\mathrm{2}} \left(\mathrm{1}−{x}^{\mathrm{2}} \right)^{\mathrm{2}} +{x}^{\mathrm{2}} \left(\mathrm{1}−{x}^{\mathrm{2}} \right)^{\mathrm{3}} +…+{x}^{\mathrm{2}} \left(\mathrm{1}−{x}^{\mathrm{2}} \right)^{\mathrm{100}} =\mathrm{1} \

Question-208135

Question Number 208135 by efronzo1 last updated on 06/Jun/24 Answered by A5T last updated on 06/Jun/24 $${r}^{{n}+\mathrm{2}} ={r}^{{n}+\mathrm{1}} +\frac{{r}^{{n}} }{\mathrm{2}}\Rightarrow{r}^{\mathrm{2}} ={r}+\frac{\mathrm{1}}{\mathrm{2}}\Rightarrow{r}=\frac{\mathrm{1}\underset{−} {+}\sqrt{\mathrm{3}}}{\mathrm{2}}…