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Category: Algebra

Question-151609

Question Number 151609 by mathdanisur last updated on 22/Aug/21 Answered by ghimisi last updated on 22/Aug/21 logxy(1+xy)2logx+y2(x+y2+1)ln(1+xy)lnxyln(1+x+y2)lnx+y2()$${f}\left({t}\right)=\frac{{ln}\left(\mathrm{1}+{t}\right)}{{lnt}},{f}:\left(\mathrm{1};\infty\right)\rightarrow{R} \

Question-151596

Question Number 151596 by mathdanisur last updated on 22/Aug/21 Answered by dumitrel last updated on 22/Aug/21 (a+b+c)2cbs3(a+b+c)a+b+c3(a+b+c)(ab+bc+ac)2cbs3(ab+bc+ac)ab+bc+ac3(ab+bc+ac$$\Rightarrow\left(\sqrt{{a}}+\sqrt{{b}}+\sqrt{{c}}\right)\left(\sqrt{{ab}}+\sqrt{{bc}}+\sqrt{{ac}}\leqslant\sqrt{\mathrm{3}\left({a}+{b}+{b}\right)\centerdot\mathrm{3}\left({ab}+{bc}+{ac}\right)}=\right.…

Question-151573

Question Number 151573 by amin96 last updated on 22/Aug/21 Answered by Olaf_Thorendsen last updated on 22/Aug/21 Sn=n1k=01(3k+1)(3k+2)(3k+3)$$\mathrm{S}_{{n}} \:=\:\underset{{k}=\mathrm{0}} {\overset{{n}−\mathrm{1}} {\sum}}\left(\frac{\mathrm{1}/\mathrm{2}}{\mathrm{3}{k}+\mathrm{1}}−\frac{\mathrm{1}}{\mathrm{3}{k}+\mathrm{2}}+\frac{\mathrm{1}/\mathrm{2}}{\mathrm{3}{k}+\mathrm{3}}\right)…