Question Number 18798 by chernoaguero@gmail.com last updated on 29/Jul/17 Answered by behi.8.3.4.1.7@gmail.com last updated on 30/Jul/17 $$\frac{{x}+{a}}{{x}+{b}}={t},\frac{{x}−{a}}{{x}−{b}}={s}\Rightarrow\frac{{x}^{\mathrm{2}} −{a}^{\mathrm{2}} }{{x}^{\mathrm{2}} −{b}^{\mathrm{2}} }={ts},\frac{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }{{ab}}={m} \\ $$$$\Rightarrow{t}^{\mathrm{2}}…
Question Number 149870 by mathdanisur last updated on 07/Aug/21 $$\mathrm{if}\:\:\:\mathrm{x};\mathrm{y};\mathrm{z};\mathrm{m};\mathrm{n}\in\mathbb{R}^{+} \:\:\mathrm{then}: \\ $$$$\underset{\boldsymbol{\mathrm{cyc}}} {\sum}\:\frac{\mathrm{b}^{−\mathrm{1}} }{\left(\mathrm{m}\sqrt{\mathrm{x}}\:+\:\mathrm{n}\sqrt{\mathrm{y}}\right)^{\mathrm{2}} }\:\geqslant\:\frac{\mathrm{3}}{\left(\mathrm{m}\:+\:\mathrm{n}\right)^{\mathrm{2}} } \\ $$ Commented by mathdanisur last updated on…
Question Number 84328 by sahnaz last updated on 11/Mar/20 $$\frac{\mathrm{3}}{\mathrm{7}}×\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\left[\frac{\mathrm{u}−\mathrm{1}}{\mathrm{u}+\mathrm{1}}\right]−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\left[\mathrm{u}^{\mathrm{2}} −\mathrm{1}\right] \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 149852 by Tawa11 last updated on 07/Aug/21 What angle is subtended at the centre of the Earth by an arc of the equator…
Question Number 18779 by chux last updated on 29/Jul/17 $$\mathrm{If}\:\:\frac{\mathrm{1}}{\mathrm{2x}}+\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{1}}{\mathrm{2x}}+\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{1}}{\mathrm{2x}}+\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{1}}{\mathrm{2x}}+……=\mathrm{y}\right.\right.\right. \\ $$$$\mathrm{what}\:\mathrm{does}\:\mathrm{x}\:\mathrm{equals}? \\ $$$$ \\ $$$$\left.\mathrm{a}\right)\mathrm{1}/\mathrm{2} \\ $$$$\left.\mathrm{b}\right)\mathrm{2}/\mathrm{4} \\ $$$$\left.\mathrm{c}\right)\mathrm{1} \\ $$$$\left.\mathrm{d}\right)\mathrm{1}/\mathrm{4} \\ $$ Commented…
Question Number 149854 by mathdanisur last updated on 07/Aug/21 Commented by mr W last updated on 08/Aug/21 $${i}\:{gave}\:{an}\:{answer}.\:{you}\:{didn}'{t}\:{agree}, \\ $$$${but}\:{gave}\:{an}\:{other}\:{answer}\:{which} \\ $$$${is}\:{in}\:{fact}\:{the}\:{same}\:{as}\:{my}\:{answer}. \\ $$ Commented…
Question Number 84315 by redmiiuser last updated on 11/Mar/20 $$\int{xy}\:{dx} \\ $$ Answered by M±th+et£s last updated on 11/Mar/20 $$\frac{{y}}{\mathrm{2}}\:{x}^{\mathrm{2}} +{c} \\ $$ Terms of…
Question Number 84293 by M±th+et£s last updated on 11/Mar/20 $${solve}\:{in}\:{R} \\ $$$${x}^{\left[{x}\right]} +{x}^{\mathrm{2}−\left[{x}\right]} ={x}^{\mathrm{2}} +\mathrm{1} \\ $$ Answered by TANMAY PANACEA last updated on 12/Mar/20…
Question Number 149817 by ajfour last updated on 07/Aug/21 $$\:\:\:{x}^{\mathrm{3}} −{x}={c} \\ $$$$\:\:{let}\:\:{x}={t}+{h} \\ $$$${t}^{\mathrm{3}} +\mathrm{3}{ht}^{\mathrm{2}} +\left(\mathrm{3}{h}^{\mathrm{2}} −\mathrm{1}\right){t}+{h}^{\mathrm{3}} −{h}−{c}=\mathrm{0} \\ $$$${let}\:\:{t}\left({t}^{\mathrm{2}} +\mathrm{3}{h}^{\mathrm{2}} −\mathrm{1}\right)={p} \\ $$$$\mathrm{3}{ht}^{\mathrm{2}}…
Question Number 149813 by mathdanisur last updated on 07/Aug/21 $$\int\left(−\mathrm{1}\right)^{\left[\boldsymbol{\mathrm{x}}\right]} \:\mathrm{dx}\:=\:? \\ $$ Commented by DonQuichote last updated on 07/Aug/21 $${deal}:\:{you}\:{show}\:{me}\:{your}\:{solution}\:{idea}\:{first} \\ $$$${then}\:{I}'{ll}\:{show}\:{you}\:{mine} \\ $$…