Category: Algebra

Question Number 86000 by oustmuchiya@gmail.com last updated on 26/Mar/20 $$solvetheequation{\mathrm{x}}^{\frac{1}{3}}=4$$ Answered by TANMAY PANACEA. last updated on 26/Mar/20 $$\left({x}^{\frac{\mathrm{1}}{\mathrm{3}}} \right)^{\mathrm{3}} =\mathrm{4}^{\mathrm{3}} \…

Question Number 151531 by bekzodjumayev last updated on 21/Aug/21 Commented by bekzodjumayev last updated on 21/Aug/21 $$Pleasehelp$$ Terms of Service Privacy Policy Contact:…

Question Number 151490 by mathdanisur last updated on 21/Aug/21 $$\{\begin{array}{l}{\mathrm{a}}^2=2\mathrm{a}+\mathrm{b}\\ {\mathrm{b}}^2=\mathrm{a}+2\mathrm{b}\end{array}\mathrm{and}\mathrm{a}\ne \mathrm{b}\mathrm{find}\sqrt{{\mathrm{a}}^2+{\mathrm{b}}^2+1}$$ Answered by iloveisrael last updated on 21/Aug/21 $$\Rightarrow{a}^{\mathrm{2}} +{b}^{\mathrm{2}}…

Question Number 151475 by mathdanisur last updated on 21/Aug/21 $$\mathrm{if}\mathbf{x}\in \mathbb{R}\mathrm{prove}\mathrm{that}:$$$${\mathrm{x}}^6-\mathrm{x}+1>0$$ Answered by dumitrel last updated on 21/Aug/21 $${I}.\:{if}\:{x}\leqslant\mathrm{0}\nRightarrow−{x}\geqslant\mathrm{0};\:{x}^{\mathrm{6}} +\mathrm{1}>\mathrm{0}\Rightarrow \…

Question Number 151460 by mathdanisur last updated on 21/Aug/21 $$\mathrm{if}\mathrm{f}\left(\mathrm{x}\right)={\mathrm{x}}^2-2\mathrm{x}+2$$$$\mathrm{and}\mathrm{g}\left(\mathrm{x}\right)=\sqrt{\mathrm{x}}+1$$$$\mathrm{find}\left[\mathrm{f}o\mathrm{g}\right]\left(\mathrm{x}\right)=?$$ Answered by puissant last updated on 21/Aug/21 $${f}\left({x}\right)={x}^{\mathrm{2}}…