Question Number 17576 by chux last updated on 07/Jul/17 $$\mathrm{solve}\:\mathrm{the}\:\mathrm{equation} \\ $$$$ \\ $$$$\mathrm{x}^{\mathrm{y}} =\mathrm{y}^{\mathrm{x}} …….\left(\mathrm{1}\right) \\ $$$$ \\ $$$$\mathrm{x}^{\mathrm{2}} =\mathrm{y}^{\mathrm{3}} …….\left(\mathrm{2}\right) \\ $$ Answered…
Question Number 17575 by tawa tawa last updated on 07/Jul/17 Commented by tawa tawa last updated on 08/Jul/17 $$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{Any}\:\mathrm{mathematical}\:\mathrm{prove}\:??? \\ $$ Commented by prakash jain…
Question Number 148630 by mathdanisur last updated on 29/Jul/21 Answered by mr W last updated on 30/Jul/21 $$\angle{C}=\mathrm{60}−\mathrm{20}=\mathrm{40}° \\ $$$$\angle{A}=\mathrm{180}−\mathrm{20}−\mathrm{60}=\mathrm{100}° \\ $$$${say}\:{AB}={a} \\ $$$$\frac{{AF}}{\mathrm{sin}\:\mathrm{20}}=\frac{{BF}}{\mathrm{sin}\:\mathrm{100}}=\frac{{AB}}{\mathrm{sin}\:\mathrm{60}}=\frac{\mathrm{2}{a}}{\:\sqrt{\mathrm{3}}} \\…
Question Number 148599 by mathdanisur last updated on 29/Jul/21 $${f}\::\:\mathbb{Z}\:\rightarrow\:\mathbb{Z} \\ $$$${f}\left({x}\right)\:=\:\mathrm{2}\:\centerdot\:{f}\left({x}\:-\:\mathrm{1}\right) \\ $$$${f}\left(\mathrm{5}\right)\:=\:\mathrm{4} \\ $$$${find}\:\:\:{f}\left(\mathrm{30}\right)\:=\:? \\ $$ Answered by Olaf_Thorendsen last updated on 29/Jul/21…
Question Number 148594 by mathdanisur last updated on 29/Jul/21 $${Solve}\:{for}\:{equation}: \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} \:=\:{xy}+{xz}+{yz}\:\:\:\Rightarrow\:\:{x};{y};{z}=? \\ $$ Commented by Rasheed.Sindhi last updated on 29/Jul/21 $${One}\:{general}\:{solution}:…
Question Number 83050 by TawaTawa1 last updated on 27/Feb/20 Commented by TawaTawa1 last updated on 27/Feb/20 $$\mathrm{A}\:\mathrm{uniform}\:\mathrm{beam}\:\mathrm{6}.\mathrm{0m}\:\mathrm{long}\:\mathrm{and}\:\mathrm{weighing}\:\:\mathrm{4kg}\:\:\:… \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 148573 by mathdanisur last updated on 29/Jul/21 $${log}_{\sqrt{\boldsymbol{{x}}}} \:\frac{{x}}{{y}}\:=\:{A}\:\:\Rightarrow\:\:{log}_{\sqrt{\boldsymbol{{y}}}} \:\frac{{y}}{{x}}\:=\:? \\ $$ Answered by Ar Brandon last updated on 29/Jul/21 $${A}=\mathrm{log}_{\sqrt{{x}}} \frac{{x}}{{y}}=\mathrm{log}_{\sqrt{{x}}} {x}−\mathrm{log}_{\sqrt{{x}}}…
Question Number 148550 by mathdanisur last updated on 29/Jul/21 $$\boldsymbol{{A}}\left(\mathrm{0};\mathrm{0}\right)\:\:;\:\:\boldsymbol{{B}}\left(−\mathrm{2};\mathrm{4}\right)\:\:{and}\:\:\boldsymbol{{C}}\left(−\mathrm{6};\mathrm{14}\right) \\ $$$${if}\:{the}\:{triangle}\:{has}\:{vertices},\:{find}\:{the} \\ $$$${lenght}\:{of}\:{the}\:{median}\:{drawn}\:{from} \\ $$$${the}\:{vertx}\:\boldsymbol{{C}} \\ $$ Commented by MJS_new last updated on 29/Jul/21…
Question Number 148546 by mathdanisur last updated on 29/Jul/21 $$\underset{\boldsymbol{{x}}\rightarrow\mathrm{0}} {{lim}}\:\frac{\sqrt{{x}\:+\:\mathrm{4}}\:-\:\mathrm{2}}{{sinx}}\:=\:? \\ $$ Commented by EDWIN88 last updated on 29/Jul/21 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{2}\sqrt{\mathrm{1}+\frac{{x}}{\mathrm{4}}}−\mathrm{2}}{\mathrm{sin}\:{x}}\:= \\ $$$$\:\mathrm{2}×\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{1}+\frac{{x}}{\mathrm{4}}}−\mathrm{1}}{\mathrm{sin}\:{x}}\:=…