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Question Number 19592 by ajfour last updated on 13/Aug/17 Commented by Tinkutara last updated on 13/Aug/17 $${z}_{{F}} \:=\:\frac{{ab}^{\mathrm{2}} }{{a}^{\mathrm{2}} \:+\:{b}^{\mathrm{2}} }\:+\:{i}\frac{{a}^{\mathrm{2}} {b}}{{a}^{\mathrm{2}} \:+\:{b}^{\mathrm{2}} } \…
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