Question Number 82561 by jagoll last updated on 22/Feb/20 $${a}\:{polynomial}\:{gives}\:{a}\:{remainder} \\ $$$${of}\:−{x}−\mathrm{1}\:{when}\:{divided}\:{by}\:{x}^{\mathrm{2}.} \\ $$$${and}\:\:{a}\:{remainder}\:{of}\:−\mathrm{1}\:{when}\: \\ $$$${divided}\:{by}\:{x}−\mathrm{1}\:.\:{what}\:{is}\:{the}\: \\ $$$${remainder}\:{when}\:{the}\:{polynomial} \\ $$$${divided}\:{by}\:{x}^{\mathrm{2}} \left({x}−\mathrm{1}\right)\:? \\ $$ Answered by…
Question Number 17019 by tawa tawa last updated on 29/Jun/17 $$\underset{\mathrm{r}\:=\:\mathrm{1}} {\overset{\mathrm{3}} {\sum}}\:\mathrm{2r}\:−\:\mathrm{1}\:\:=\:\:? \\ $$ Answered by arnabpapu550@gmail.com last updated on 29/Jun/17 $$=\left(\mathrm{2}×\mathrm{1}−\mathrm{1}\right)+\left(\mathrm{2}×\mathrm{2}−\mathrm{1}\right)+\left(\mathrm{2}×\mathrm{3}−\mathrm{1}\right) \\ $$$$=\mathrm{1}+\mathrm{3}+\mathrm{5}=\mathrm{9}…
Question Number 17018 by tawa tawa last updated on 29/Jun/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{cube}\:\mathrm{root}\:\mathrm{of}:\:\:\:\mathrm{55}\:+\:\mathrm{63}\:\sqrt{\mathrm{2}} \\ $$ Commented by prakash jain last updated on 29/Jun/17 $$\left({a}+{b}\sqrt{\mathrm{2}}\right)^{\mathrm{3}} =\mathrm{55}+\mathrm{63}\sqrt{\mathrm{2}} \\ $$$${a}^{\mathrm{3}}…
Question Number 148090 by mathdanisur last updated on 25/Jul/21 Commented by Rasheed.Sindhi last updated on 25/Jul/21 $$\angle{B}=\mathrm{75}°×\mathrm{2}=\mathrm{150}° \\ $$ Commented by mathdanisur last updated on…
Question Number 148077 by mathdanisur last updated on 25/Jul/21 $$\int\:\frac{{cos}^{\boldsymbol{{n}}} {x}}{{sinx}}\:{dx}\:=\:? \\ $$ Answered by Olaf_Thorendsen last updated on 26/Jul/21 $$\mathrm{I}_{{n}} \left({x}\right)\:=\:\int\frac{\mathrm{cos}^{{n}} {x}}{\mathrm{sin}{x}}\:{dx} \\ $$$$…
Question Number 16990 by 1234Hello last updated on 29/Jun/17 $$\mathrm{If}\:\mathrm{for}\:\mathrm{positive}\:\mathrm{integers}\:{a}\:\mathrm{and}\:{b}, \\ $$$${a}\:+\:{b}\:=\:\frac{{a}}{{b}}\:+\:\frac{{b}}{{a}},\:\mathrm{find}\:{a}^{\mathrm{2}} \:+\:{b}^{\mathrm{2}} . \\ $$ Commented by RasheedSoomro last updated on 29/Jun/17 $${a}\:+\:{b}\:=\:\frac{{a}}{{b}}\:+\:\frac{{b}}{{a}} \\…
Question Number 82519 by peter frank last updated on 22/Feb/20 Commented by mathmax by abdo last updated on 23/Feb/20 $${A}_{\theta} =\sum_{{n}=\mathrm{0}} ^{\infty} \:\frac{\left(−\mathrm{1}\right)^{{n}} }{\mathrm{2}^{{n}} }{cos}\left({n}\theta\right)\:\:=\sum_{{n}=\mathrm{0}}…
Question Number 16969 by tawa tawa last updated on 28/Jun/17 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 148043 by mathdanisur last updated on 25/Jul/21 $$\frac{\left(\mathrm{2}\:−\:\sqrt{\mathrm{2}}\right)^{\mathrm{8}} \:\centerdot\:\left(\mathrm{6}\:+\:\mathrm{4}\sqrt{\mathrm{2}}\right)^{\mathrm{8}} }{\left(\mathrm{2}\:+\:\sqrt{\mathrm{2}}\right)^{\mathrm{8}} }\:=\:? \\ $$ Answered by iloveisrael last updated on 25/Jul/21 $$\left[\:\frac{\left(\mathrm{2}−\sqrt{\mathrm{2}}\right)\left(\mathrm{6}+\mathrm{4}\sqrt{\mathrm{2}}\right)}{\mathrm{2}+\sqrt{\mathrm{2}}}\:\right]^{\mathrm{8}} \: \\…
Question Number 148042 by mathdanisur last updated on 25/Jul/21 $$\sqrt{\mathrm{17}\:−\:\mathrm{4}\sqrt{\mathrm{15}}}\:−\:\sqrt[{\mathrm{4}}]{\mathrm{144}}\:=\:? \\ $$ Answered by Olaf_Thorendsen last updated on 25/Jul/21 $$\mathrm{X}\:=\:\sqrt{\mathrm{17}−\mathrm{4}\sqrt{\mathrm{15}}}−\sqrt[{\mathrm{4}}]{\mathrm{144}} \\ $$$$\mathrm{X}\:=\:\sqrt{\left(\mathrm{2}\sqrt{\mathrm{3}}−\sqrt{\mathrm{5}}\right)^{\mathrm{2}} }−\sqrt[{\mathrm{4}}]{\mathrm{12}^{\mathrm{2}} } \\…