Menu Close

Category: Algebra

Question-84820

Question Number 84820 by Power last updated on 16/Mar/20 Answered by MJS last updated on 16/Mar/20 supereasy2x5=tx=12t2+52t0$$\sqrt{\frac{\mathrm{1}}{\mathrm{2}}{t}^{\mathrm{2}} +\frac{\mathrm{5}}{\mathrm{2}}−\mathrm{2}+{t}}+\sqrt{\frac{\mathrm{1}}{\mathrm{2}}{t}^{\mathrm{2}} +\frac{\mathrm{5}}{\mathrm{2}}+\mathrm{2}+\mathrm{3}{t}}=\mathrm{7}\sqrt{\mathrm{2}} \