Question Number 82191 by jagoll last updated on 19/Feb/20 $${find}\:{the}\:{solution} \\ $$$$\sqrt{{x}^{\mathrm{2}} −\mathrm{3}{x}−\mathrm{4}\:}\:\:>\:\:{x}−\mathrm{2}\: \\ $$ Commented by arkanmath7@gmail.com last updated on 19/Feb/20 $${x}^{\mathrm{2}} −\mathrm{3}{x}−\mathrm{4}\:\:\:>\:\:{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{4}…
Question Number 16632 by tawa tawa last updated on 24/Jun/17 $$\mathrm{e}^{\mathrm{xy}} \:+\:\mathrm{y}^{\mathrm{2}} \:=\:\mathrm{sin}\left(\mathrm{x}\:+\:\mathrm{y}\right) \\ $$$$\mathrm{Express}\:\mathrm{the}\:\mathrm{variable}\:\mathrm{y}\:\mathrm{interms}\:\mathrm{of}\:\mathrm{x}\:\mathrm{only}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 147697 by mathdanisur last updated on 22/Jul/21 $${f}\left(\mathrm{0}\right)+{f}\left(\mathrm{1}\right)+{f}\left(\mathrm{2}\right)+…+{f}\left({n}\right)={n}!−{n}\centerdot{a} \\ $$$${f}\left(\mathrm{16}\right)=\mathrm{15}\centerdot\left(\mathrm{15}!−\mathrm{1}\right) \\ $$$${find}\:\:\boldsymbol{{a}}=? \\ $$ Answered by Olaf_Thorendsen last updated on 22/Jul/21 $$\underset{{k}=\mathrm{0}} {\overset{{n}}…
Question Number 147699 by mathdanisur last updated on 22/Jul/21 $$\boldsymbol{{a}}^{\mathrm{2}} \:=\:\mathrm{36}^{\mathrm{7}} \:+\:\mathrm{9}^{\boldsymbol{{b}}} \:+\:\mathrm{6}^{\mathrm{8}} \:\:;\:\:\boldsymbol{{a}}\in\mathbb{Z} \\ $$$${find}\:\:\boldsymbol{{b}}=? \\ $$ Answered by Olaf_Thorendsen last updated on 22/Jul/21…
Question Number 147689 by mathdanisur last updated on 22/Jul/21 $$\left(\mathrm{234}\right)_{\mathrm{5}} \:\centerdot\:\left(\mathrm{23}\right)_{\mathrm{5}} \:=\:\left({x}\right)_{\mathrm{5}} \:\:\Rightarrow\:\:\boldsymbol{{x}}=? \\ $$ Answered by Olaf_Thorendsen last updated on 22/Jul/21 $$\left(\mathrm{234}\right)_{\mathrm{5}} .\left(\mathrm{23}\right)_{\mathrm{5}} \\…
Question Number 82149 by TawaTawa last updated on 18/Feb/20 $$\mathrm{Evaluate}\:\mathrm{the}\:\mathrm{greatest}\:\mathrm{coefficient}\:\mathrm{of}\:\:\:\:\left(\mathrm{7}\:−\:\mathrm{5x}\right)^{−\:\mathrm{3}} \\ $$ Commented by TawaTawa last updated on 18/Feb/20 $$\mathrm{Please}\:\mathrm{working}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{appreciate}. \\ $$ Answered by mr…
Question Number 147673 by mnjuly1970 last updated on 22/Jul/21 Answered by Rasheed.Sindhi last updated on 22/Jul/21 $$\sqrt[{\mathrm{3}}]{{x}}+\sqrt[{\mathrm{3}}]{{x}−\mathrm{2}}=\sqrt[{\mathrm{3}}]{{x}−\mathrm{1}} \\ $$$$\left(\sqrt[{\mathrm{3}}]{{x}}+\sqrt[{\mathrm{3}}]{{x}−\mathrm{2}}\right)^{\mathrm{3}} =\left(\sqrt[{\mathrm{3}}]{{x}−\mathrm{1}}\right)^{\mathrm{3}} \\ $$$${x}+{x}−\mathrm{2}+\mathrm{3}\sqrt[{\mathrm{3}}]{{x}}\sqrt[{\mathrm{3}}]{{x}−\mathrm{2}}\left(\sqrt[{\mathrm{3}}]{{x}}+\sqrt[{\mathrm{3}}]{{x}−\mathrm{2}}\right)={x}−\mathrm{1} \\ $$$$\mathrm{3}\sqrt[{\mathrm{3}}]{{x}}\sqrt[{\mathrm{3}}]{{x}−\mathrm{2}}\left(\sqrt[{\mathrm{3}}]{{x}−\mathrm{1}}\right)=−{x}+\mathrm{1} \\…
Question Number 16600 by tawa tawa last updated on 24/Jun/17 $$\mathrm{Solve}\:\mathrm{simultaneously} \\ $$$$\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{2}} \:=\:\mathrm{61}\:\:\:\:\:\:\:\:\:…………..\:\mathrm{equation}\:\left(\mathrm{i}\right) \\ $$$$\mathrm{x}^{\mathrm{3}} \:−\:\mathrm{y}^{\mathrm{3}} \:=\:\mathrm{91}\:\:\:\:\:\:\:\:\:…………..\:\mathrm{equation}\:\left(\mathrm{ii}\right) \\ $$ Commented by prakash jain…
Question Number 82130 by TawaTawa last updated on 18/Feb/20 $$\mathrm{In}\:\mathrm{an}\:\mathrm{arrangement}\:\mathrm{of}\:\mathrm{the}\:\mathrm{word}\:\:\mathrm{VIOLENT},\:\mathrm{find}\:\mathrm{the}\:\mathrm{chances} \\ $$$$\mathrm{that}\:\mathrm{the}\:\mathrm{vowels}\:\:\:\mathrm{I},\:\mathrm{O},\:\mathrm{E}\:\:\:\mathrm{occupy}\:\mathrm{the}\:\mathrm{odd}\:\mathrm{positions}. \\ $$ Commented by mr W last updated on 18/Feb/20 $${we}\:{have}\:\mathrm{4}\:{odd}\:{positions}:\:\mathrm{1},\:\mathrm{3},\:\mathrm{5},\:\mathrm{7} \\ $$$${we}\:{have}\:\mathrm{3}\:{even}\:{positions}:\:\mathrm{2},\:\mathrm{4},\:\mathrm{6}…
Question Number 147661 by mathdanisur last updated on 22/Jul/21 $$\mathrm{41}^{\mathrm{3}} \:+\:\mathrm{42}^{\mathrm{3}} \:+\:\mathrm{43}^{\mathrm{3}} \:+\:…\:+\:\mathrm{59}^{\mathrm{3}} \\ $$$${Find}\:{the}\:{last}\:{three}\:{digits}\:{of}\:{the} \\ $$$${number} \\ $$ Answered by nimnim last updated on…