Question Number 148042 by mathdanisur last updated on 25/Jul/21 $$\sqrt{\mathrm{17}\:−\:\mathrm{4}\sqrt{\mathrm{15}}}\:−\:\sqrt[{\mathrm{4}}]{\mathrm{144}}\:=\:? \\ $$ Answered by Olaf_Thorendsen last updated on 25/Jul/21 $$\mathrm{X}\:=\:\sqrt{\mathrm{17}−\mathrm{4}\sqrt{\mathrm{15}}}−\sqrt[{\mathrm{4}}]{\mathrm{144}} \\ $$$$\mathrm{X}\:=\:\sqrt{\left(\mathrm{2}\sqrt{\mathrm{3}}−\sqrt{\mathrm{5}}\right)^{\mathrm{2}} }−\sqrt[{\mathrm{4}}]{\mathrm{12}^{\mathrm{2}} } \\…
Question Number 148035 by mathdanisur last updated on 25/Jul/21 $${if}\:\:\:{f}\left({g}\left({x}\right)\right)\:=\:\mathrm{2}{x}\:-\:\mathrm{5}\:\:{and}\:\:{f}\left({x}\right)\:=\:{x}\:+\:\mathrm{2} \\ $$$${find}\:\:\:{g}\left({x}\right)\:=\:? \\ $$ Commented by prakash jain last updated on 25/Jul/21 $${f}\left({x}\right)={x}+\mathrm{2} \\ $$$${f}\left({g}\left({x}\right)\right)={g}\left({x}\right)+\mathrm{2}…
Question Number 148027 by mathdanisur last updated on 25/Jul/21 $${if}\:\:\:\mathrm{2}{x}^{\mathrm{3}} \:+\:\mathrm{3}{y}^{\mathrm{3}} \:=\:\mathrm{200}\:\:\Rightarrow\:\:\left({x}^{\mathrm{2}} {y}^{\mathrm{2}} \right)_{\boldsymbol{{max}}} \:=\:? \\ $$ Commented by mr W last updated on 25/Jul/21…
Question Number 82489 by niroj last updated on 21/Feb/20 $$ \\ $$$$\: \\ $$$$\mathrm{If}\:\mathrm{a}^{\mathrm{b}} =\mathrm{b}^{\mathrm{a}} \:\mathrm{and}\:\mathrm{a}=\mathrm{2b}\:\mathrm{then}\:\mathrm{find}\:\mathrm{the} \\ $$$$\:\mathrm{value}\:\mathrm{of}\:\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} \:. \\ $$ Answered by mind…
Question Number 148015 by mnjuly1970 last updated on 25/Jul/21 $$\:\:\:\:\:\:\:\:……..\:{mathematics}……. \\ $$$$\:\:\:\:\:\:\:\mathrm{5}\:\left(\mathrm{11}\right)^{\:{x}} \:\overset{\mathrm{13}} {\equiv}\:\mathrm{3}^{\:{x}} \:\:\:\:\:\left(\:{x}\:\in\:\mathbb{N}\:\right)\:\:\: \\ $$$$\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:{find}\:{values}\:{of}\:\:\:\:::\:\:\:\:{x}\:=\:? \\ $$$$ \\ $$ Commented by…
Question Number 16935 by Tinkutara last updated on 28/Jun/17 $$\mathrm{A}\:\mathrm{two}-\mathrm{digit}\:\mathrm{number}\:\mathrm{has}\:\mathrm{the}\:\mathrm{property} \\ $$$$\mathrm{that}\:\mathrm{the}\:\mathrm{square}\:\mathrm{of}\:\mathrm{its}\:\mathrm{tens}\:\mathrm{digit}\:\mathrm{plus} \\ $$$$\mathrm{ten}\:\mathrm{times}\:\mathrm{its}\:\mathrm{units}\:\mathrm{digit}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{square}\:\mathrm{of}\:\mathrm{its}\:\mathrm{units}\:\mathrm{digit}\:\mathrm{plus}\:\mathrm{ten}\:\mathrm{times} \\ $$$$\mathrm{its}\:\mathrm{tens}\:\mathrm{digit}.\:\mathrm{Find}\:\mathrm{all}\:\mathrm{two}\:\mathrm{digit} \\ $$$$\mathrm{numbers}\:\mathrm{which}\:\mathrm{have}\:\mathrm{this}\:\mathrm{property},\:\mathrm{and} \\ $$$$\mathrm{are}\:\mathrm{prime}\:\mathrm{numbers}. \\ $$ Answered…
Question Number 147999 by iloveisrael last updated on 25/Jul/21 Answered by Canebulok last updated on 25/Jul/21 $$\: \\ $$$$\boldsymbol{{Solution}}: \\ $$$$\Rightarrow\:\mathrm{16}\centerdot\left(\mathrm{2}{x}\right)^{\frac{\mathrm{1}}{\left(\frac{{x}}{\mathrm{2}}\right)}} \:=\:\left(\mathrm{8}{x}\right)^{\frac{\mathrm{1}}{\mathrm{2}}} \\ $$$$\: \\…
Question Number 147980 by mathdanisur last updated on 24/Jul/21 $${f}\left({x}\right)\:=\:\mathrm{4}{x}^{\mathrm{4}} \:-\:\mathrm{2}{x}^{\mathrm{2}} \:+\:\mathrm{17} \\ $$$${Find}\:{the}\:{maximum}\:{point}\:{of}\:{the} \\ $$$${function} \\ $$ Answered by iloveisrael last updated on 25/Jul/21…
Question Number 16909 by tawa tawa last updated on 28/Jun/17 $$\sqrt{\mathrm{x}^{\mathrm{x}^{\mathrm{6}} } }\:=\:\mathrm{729}\:,\:\:\:\:\mathrm{Find}\:\mathrm{x} \\ $$ Answered by mrW1 last updated on 28/Jun/17 $$\sqrt{\mathrm{x}^{\mathrm{x}^{\mathrm{6}} } }\:=\:\mathrm{729}…
Question Number 147979 by mathdanisur last updated on 24/Jul/21 $${y}\:=\:{x}^{\mathrm{3}} \:\:;\:\:{y}\:=\:\mathrm{0}\:\:{and}\:\:{x}\:=\:{a} \\ $$$${Find}\:\:\boldsymbol{{a}}\:\:{if}\:{the}\:{area}\:{of}\:{the}\:{figure} \\ $$$${bounded}\:{by}\:{straight}\:{lines}\:{is}\:\:\mathrm{64} \\ $$ Answered by iloveisrael last updated on 25/Jul/21 $$\mathrm{If}\:\mathrm{a}>\mathrm{0}\:\Rightarrow\mathrm{64}=\int_{\mathrm{0}}…