Question Number 148314 by Tawa11 last updated on 27/Jul/21 $$\mathrm{solve}:\:\:\:\:\:\:\mathrm{x}^{\mathrm{x}} \:\:\:=\:\:\:\frac{\mathrm{1}}{\mathrm{4}} \\ $$$$\mathrm{How}\:\mathrm{can}\:\mathrm{we}\:\mathrm{get}\:\mathrm{the}\:\mathrm{complex}\:\mathrm{solution} \\ $$ Commented by Tawa11 last updated on 27/Jul/21 $$\mathrm{what}\:\mathrm{is}\:\:\:\:\:\:\mathrm{W}_{\mathrm{n}} \left(−\:\mathrm{ln}\:\mathrm{4}\right) \\…
Question Number 148300 by mathdanisur last updated on 26/Jul/21 $${lg}^{\mathrm{2}} \left(\mathrm{10}{x}\right)\:+\:{lg}\left(\mathrm{10}{x}\right)\:=\:\mathrm{6}\:-\:{lg}\left({x}\right) \\ $$$${x}\:=\:? \\ $$ Answered by Olaf_Thorendsen last updated on 26/Jul/21 $$\mathrm{lg}^{\mathrm{2}} \left(\mathrm{10}{x}\right)+\mathrm{lg}\left(\mathrm{10}{x}\right)\:=\:\mathrm{6}−\mathrm{lg}\left({x}\right) \\…
Question Number 148301 by mathdanisur last updated on 26/Jul/21 $${Solve}\:{for}\:{equation}: \\ $$$$\mathrm{4}{sin}^{\mathrm{2}} \left({x}\right)\:+\:{sin}\left(\mathrm{2}{x}\right)\:=\:\mathrm{2} \\ $$ Answered by mr W last updated on 27/Jul/21 $$\mathrm{2}\left(\mathrm{1}−\mathrm{cos}\:\mathrm{2}{x}\right)+\mathrm{sin}\:\mathrm{2}{x}=\mathrm{2} \\…
Question Number 148289 by saly last updated on 26/Jul/21 Commented by saly last updated on 26/Jul/21 $$\:{hepl}\:{me} \\ $$ Answered by mr W last updated…
Question Number 148278 by mathdanisur last updated on 26/Jul/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 148268 by mathdanisur last updated on 26/Jul/21 Answered by Olaf_Thorendsen last updated on 26/Jul/21 $${z}^{\mathrm{4}} −\mathrm{3}{z}^{\mathrm{2}} +\mathrm{1}\:=\:\sqrt{\frac{\mathrm{4}}{\mathrm{4}−{z}^{\mathrm{2}} }−\mathrm{1}}\:\:\:\left(\mathrm{1}\right) \\ $$$$\mathrm{Let}\:{w}\:=\:{z}^{\mathrm{2}} \\ $$$$\left(\mathrm{1}\right)\::\:{w}^{\mathrm{2}} −\mathrm{3}{w}+\mathrm{1}\:=\:\sqrt{\frac{\mathrm{4}}{\mathrm{4}−{w}}−\mathrm{1}}…
Question Number 148262 by mathdanisur last updated on 26/Jul/21 $${if}\:\:{x}>−\mathrm{1}\:\:;\:\:\left[{q}\right]={n}\geqslant\mathrm{2}\:\:;\:\:\left[\ast\right]-{GIF}\:\:{then}: \\ $$$$\left(\mathrm{1}+{x}\right)^{\boldsymbol{{q}}} \:\geqslant\:\left(\mathrm{1}+{nx}\right)\left(\mathrm{1}+\left({q}-{n}\right){x}\right)\:\geqslant\:\mathrm{1}+{qx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 148249 by mnjuly1970 last updated on 26/Jul/21 Commented by Kamel last updated on 26/Jul/21 $$ \\ $$$$\Omega_{{n}} =\int_{\mathrm{0}} ^{+\infty} \frac{{cos}\left(\pi{x}\right)}{\left({x}^{\mathrm{2}} +\mathrm{1}^{\mathrm{2}} \right)\left({x}^{\mathrm{2}} +\mathrm{2}^{\mathrm{2}}…
Question Number 82701 by jagoll last updated on 23/Feb/20 $$\mathrm{2}{f}\left({x}−\mathrm{1}\right)\:+\mathrm{3}{f}\left({x}+\mathrm{1}\right)\overset{\:} {\:}=\:\mathrm{3}{x}^{\mathrm{2}} −\mathrm{5}{x} \\ $$$${find}\:{f}\left({x}\right) \\ $$ Answered by TANMAY PANACEA last updated on 23/Feb/20 $${f}\left({x}\right)={ax}^{\mathrm{2}}…
Question Number 148229 by iloveisrael last updated on 26/Jul/21 Commented by nimnim last updated on 26/Jul/21 $$\:\:\:\:\:\:\:\:\:{x}+\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}+\frac{\mathrm{1}}{{x}−\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}}=\mathrm{20} \\ $$$$\Rightarrow\frac{{x}^{\mathrm{2}} −\left({x}^{\mathrm{2}} −\mathrm{1}\right)+\mathrm{1}}{{x}−\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}}×\frac{{x}+\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}}{{x}+\sqrt{{x}^{\mathrm{2}}…