Category: Algebra

Question Number 149122 by mathdanisur last updated on 03/Aug/21 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 83554 by Power last updated on 03/Mar/20 Answered by MJS last updated on 03/Mar/20 $$x^4+4x^3-8x+\frac{17}{5}=0$$$$\mathrm{let}x=t-1$$$${t}^{\mathrm{4}} −\mathrm{6}{t}^{\mathrm{2}} +\frac{\mathrm{42}}{\mathrm{5}}=\mathrm{0}…

Question Number 83542 by Power last updated on 03/Mar/20 Answered by john santu last updated on 03/Mar/20 $$\mathrm{f}\left(\mathrm{x}\right)=\frac{1}{1+2^{2\mathrm{x}-1}}$$$$\mathrm{f}\left(\frac{1}{2001}\right)=\frac{1}{1+2^{\frac{2}{2001}-1}}$$$$\mathrm{f}\left(\frac{\mathrm{2}}{\mathrm{2001}}\right)\:=\:\frac{\mathrm{1}}{\mathrm{1}+\mathrm{2}^{\frac{\mathrm{2}}{\mathrm{2001}}−\mathrm{1}} }…

Question Number 149060 by mathdanisur last updated on 02/Aug/21 $$if4z\sqrt{z}-11\sqrt{z}=5$$$$find2z-\sqrt{z}=?$$ Answered by bramlexs22 last updated on 02/Aug/21 $$\Rightarrow \sqrt{\mathrm{z}}=\mathrm{u}$$$$\Rightarrow\mathrm{4z}\sqrt{\mathrm{z}}−\sqrt{\mathrm{z}}\:=\:\mathrm{5}+\mathrm{10}\sqrt{\mathrm{z}} \…

Question Number 83512 by jagoll last updated on 03/Mar/20 $$\mathrm{find}\mathrm{the}\mathrm{solution}$$$$\frac{{4\mathrm{x}}^2}{{(1-\sqrt{2\mathrm{x}+1})}^2}<2\mathrm{x}+9$$ Answered by john santu last updated on 03/Mar/20 $$\left(\mathrm{1}\right)\:\mathrm{2x}\:+\mathrm{9}\:>\:\mathrm{0}\:\Rightarrow\:\mathrm{x}\:>\:−\frac{\mathrm{9}}{\mathrm{2}}…