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Category: Algebra

lim-x-7-x-a-4-x-7-b-find-a-b-

Question Number 146505 by mathdanisur last updated on 13/Jul/21 $$\underset{{x}\rightarrow\mathrm{7}} {{lim}}\:\frac{\sqrt{{x}\:-\:{a}}\:-\:\mathrm{4}}{{x}\:-\:\mathrm{7}}\:=\:{b}\:\:{find}\:\:{a}\centerdot{b}=? \\ $$ Answered by ajfour last updated on 13/Jul/21 $${i}\:{just}\:{dunno}\:\:{but}\:{letsee}\:{whtits} \\ $$$${bout}.. \\ $$$${if}\:{limit}\:{has}\:{to}\:{exist},\:{i}.{e}.…

if-4a-7b-2c-and-dcm-a-b-c-3-find-a-b-c-

Question Number 146470 by mathdanisur last updated on 13/Jul/21 $${if}\:\:\:\mathrm{4}{a}=\mathrm{7}{b}=\mathrm{2}{c}\:\:{and}\:\:\:\boldsymbol{{dcm}}\left({a};{b};{c}\right)=\mathrm{3} \\ $$$${find}\:\:\:{a}+{b}+{c}=? \\ $$ Answered by Rasheed.Sindhi last updated on 13/Jul/21 $${if}\:\:\:\mathrm{4}{a}=\mathrm{7}{b}=\mathrm{2}{c}\:\:{and}\:\:\:\boldsymbol{{gcd}}\left({a},{b},{c}\right)=\mathrm{3} \\ $$$${a}+{b}+{c}=? \\…

Question-80930

Question Number 80930 by peter frank last updated on 08/Feb/20 Commented by jagoll last updated on 08/Feb/20 $$\Rightarrow\left(\mathrm{1}\right)\:{a}+{b}+\mathrm{2}\:=\:\mathrm{0}\:,\:{a}+{b}\:=\:−\mathrm{2} \\ $$$$\Rightarrow\left(\mathrm{2}\right)\:{y}'\:=\:\mathrm{3}{ax}^{\mathrm{2}} +\mathrm{2}{bx} \\ $$$$\Rightarrow{y}\:''\:=\:\mathrm{6}{ax}\:+\mathrm{2}{b}\:=\:\mathrm{0}\:{for}\:{x}\:=\:\mathrm{1} \\ $$$$\mathrm{2}{b}\:=\:−\mathrm{6}{a}\:\Rightarrow{b}\:=\:−\mathrm{3}{a}\:\wedge\:{a}+{b}\:=−\mathrm{2}…

arccos-cos-9-

Question Number 146465 by mathdanisur last updated on 13/Jul/21 $${arccos}\left({cos}\:\mathrm{9}\right)\:=\:? \\ $$ Answered by gsk2684 last updated on 13/Jul/21 $$\mathrm{5}\frac{\Pi}{\mathrm{2}}<\mathrm{9}<\:\mathrm{3}\Pi \\ $$$$\left(\mathrm{5}\frac{\Pi}{\mathrm{2}}−\mathrm{2}\Pi\right)<\left(\mathrm{9}−\mathrm{2}\Pi\right)<\left(\mathrm{3}\Pi−\mathrm{2}\Pi\right) \\ $$$$\frac{\Pi}{\mathrm{2}}<\left(\mathrm{9}−\mathrm{2}\Pi\right)<\Pi \\…

if-3-2-1-2-i-find-z-11-

Question Number 146467 by mathdanisur last updated on 13/Jul/21 $${if}\:\:\:\:\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\:+\:\frac{\mathrm{1}}{\mathrm{2}}\:\boldsymbol{{i}}\:\:\:\:{find}\:\:\:\boldsymbol{{z}}^{\mathrm{11}} \:=\:? \\ $$ Answered by gsk2684 last updated on 13/Jul/21 $${z}^{\mathrm{11}} \:=\:\left({cis}\:\frac{\Pi}{\mathrm{6}}\right)^{\mathrm{11}} =\:{cis}\left(\frac{\mathrm{11}\Pi}{\mathrm{6}}\right) \\ $$$$={cis}\left(\mathrm{2}\Pi−\frac{\Pi}{\mathrm{6}}\right)…