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Question Number 145801 by mathdanisur last updated on 08/Jul/21 Answered by ajfour last updated on 08/Jul/21 $${xy}+{tz}={a} \\ $$$${solving}\:{for}\:{x},{y}\:{in}\:{terms}\:{of} \\ $$$${t},{z}\:{from}\:\mathrm{2}{nd}\:{and}\:\mathrm{3}{rd}\:{eqs}. \\ $$$${x}=\frac{{bz}−{ct}}{{z}^{\mathrm{2}} −{t}^{\mathrm{2}} }\:\:;\:\:{y}=\frac{{bt}−{cz}}{{t}^{\mathrm{2}}…
Question Number 80262 by Power last updated on 01/Feb/20 Commented by MJS last updated on 01/Feb/20 $$\mathrm{are}\:\mathrm{there}\:\mathrm{prime}\:\mathrm{un}−\mathrm{integers}?!? \\ $$ Commented by mind is power last…
Question Number 80261 by Power last updated on 01/Feb/20 Commented by MJS last updated on 01/Feb/20 $$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{obvious}\:\mathrm{maximum}\:\mathrm{of} \\ $$$$\frac{\mathrm{1}}{{x}^{\mathrm{2}} +\mathrm{2}}\:\mathrm{with}\:{x}>\mathrm{0}?\:\mathrm{this}\:\mathrm{is}\:\mathrm{clear}\:\mathrm{as}\:\mathrm{anything} \\ $$$$\mathrm{might}\:\mathrm{be}. \\ $$ Terms…
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Question Number 80243 by mr W last updated on 01/Feb/20 $${if}\:{x}+\frac{\mathrm{1}}{{x}}={a}\:\left({a}\in\mathbb{R}\right) \\ $$$${find}\:{x}^{{n}} +\frac{\mathrm{1}}{{x}^{{n}} }=? \\ $$$$\left({n}\in\mathbb{N}\right) \\ $$ Commented by TawaTawa last updated on…
Question Number 145772 by mathdanisur last updated on 07/Jul/21 $${a};{b};{c}>\mathrm{0}\:;\:{a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} =\mathrm{2}\:{prove}: \\ $$$$\left({a}^{\mathrm{6}} +{b}^{\mathrm{6}} +{c}^{\mathrm{6}} \right)^{\mathrm{3}} \:\geqslant\:\left({a}^{\mathrm{5}} +{b}^{\mathrm{5}} +{c}^{\mathrm{5}} \right)^{\mathrm{4}} \\ $$ Terms…
Question Number 145774 by Engr_Jidda last updated on 08/Jul/21 $${find}\:{the}\:{area}\:{bounded}\:{by}\:{y}=\mathrm{2}{x},\:{y}=\frac{{x}}{\mathrm{2}}\:{and}?{xy}=\mathrm{2} \\ $$ Answered by ArielVyny last updated on 08/Jul/21 $$\forall{x}\in\mathbb{R}\:\mathrm{2}{x}\geqslant\frac{{x}}{\mathrm{2}}\:\:{A}=\int\left(\mathrm{2}{x}−\frac{{x}}{\mathrm{2}}\right){dx}=\mathrm{2}\frac{\mathrm{1}}{\mathrm{2}}{x}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{1}}{\mathrm{2}}{x}^{\mathrm{2}} \\ $$$${A}={x}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{4}}{x}^{\mathrm{2}} =\frac{\mathrm{3}}{\mathrm{4}}{x}^{\mathrm{2}}…
Question Number 145769 by Engr_Jidda last updated on 07/Jul/21 $${find}\:{x}\:{if}\:\:\mathrm{2}^{{x}} +\mathrm{2}^{\mathrm{3}{x}} =\mathrm{16} \\ $$ Commented by 7770 last updated on 08/Jul/21 $$\mathrm{2}^{\boldsymbol{{x}}} +\mathrm{2}^{\mathrm{3}\boldsymbol{{x}}} =\mathrm{16} \\…