Question Number 18640 by 99 last updated on 26/Jul/17 Commented by 99 last updated on 26/Jul/17 $${please}\:{solve}\:{question}\:{no}.\mathrm{6}\:.{please}… \\ $$ Answered by Tinkutara last updated on…
Question Number 18606 by 99 last updated on 25/Jul/17 $$\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{3}}{\mathrm{3}×\mathrm{7}}+\frac{\mathrm{5}}{\mathrm{3}×\mathrm{7}×\mathrm{11}}+\frac{\mathrm{7}}{\mathrm{3}×\mathrm{7}×\mathrm{11}×\mathrm{15}}+…{n}\: \\ $$$$\:{terms} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 149675 by mathdanisur last updated on 06/Aug/21 $$\underset{\boldsymbol{\mathrm{n}}\rightarrow\infty} {\mathrm{lim}}\sqrt[{\boldsymbol{\mathrm{n}}}]{\underset{\:\mathrm{0}} {\overset{\:\infty} {\int}}\:\frac{\mathrm{dx}}{\left(\mathrm{x}^{\mathrm{2}} \:+\:\frac{\mathrm{1}}{\mathrm{4}}\right)^{\boldsymbol{\mathrm{n}}+\mathrm{1}} }}\:=\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 149670 by EDWIN88 last updated on 06/Aug/21 $$\:\:\:{Solve}\:{the}\:{equation}\: \\ $$$$\:\:{x}=\sqrt{{a}−\sqrt{{a}+{x}}\:}\:{where}\:{a}>\mathrm{0}\:{is}\: \\ $$$$\:{a}\:{parameter}. \\ $$ Answered by MJS_new last updated on 06/Aug/21 $$\mathrm{for}\:{a},\:{x}\:\in\mathbb{R} \\…
Question Number 84126 by Roland Mbunwe last updated on 09/Mar/20 $$\int\frac{\mathrm{5}−{x}}{\mathrm{1}+\sqrt{\left({x}−\mathrm{4}\right)}}\boldsymbol{{dx}} \\ $$ Answered by MJS last updated on 09/Mar/20 $$−\int\frac{{x}−\mathrm{5}}{\mathrm{1}+\sqrt{{x}−\mathrm{4}}}{dx}=\int\left(\mathrm{1}−\sqrt{{x}−\mathrm{4}}\right){dx}= \\ $$$$={x}−\frac{\mathrm{2}}{\mathrm{3}}\left({x}−\mathrm{4}\right)^{\frac{\mathrm{3}}{\mathrm{2}}} +{C} \\…
Question Number 84109 by Power last updated on 09/Mar/20 Commented by mahdi last updated on 09/Mar/20 $$\frac{\mathrm{1}}{\mathrm{1}}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{5}}+…+\frac{\mathrm{1}}{\mathrm{2x}+\mathrm{1}}\approx\mathrm{ln}\left(\frac{\mathrm{2x}+\mathrm{1}}{\:\sqrt{\mathrm{x}}}\right)+\mathrm{0}.\mathrm{28861} \\ $$ Commented by mathmax by abdo last…
Question Number 149636 by SLVR last updated on 06/Aug/21 Answered by mr W last updated on 06/Aug/21 $${Q}\mathrm{1} \\ $$$${x}\:{is}\:{integer},\:{then}\:{x}^{\mathrm{2}} \:{also}\:{integer}. \\ $$$$\left[{x}^{\mathrm{2}} \right]={x}^{\mathrm{2}} ={x}+\mathrm{1}\:{which}\:{has}\:{no}\:{solution}.…
Question Number 149638 by Samimsultani last updated on 06/Aug/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 149621 by mathdanisur last updated on 06/Aug/21 $$\mathrm{if}\:\:\:\mathrm{2}^{\boldsymbol{{x}}} =\mathrm{3}^{\boldsymbol{{y}}} =\mathrm{7}^{\boldsymbol{{z}}} =\sqrt[{\mathrm{3}}]{\mathrm{42}} \\ $$$$\mathrm{find}\:\:\:\frac{\mathrm{1}}{{x}}+\frac{\mathrm{1}}{{y}}+\frac{\mathrm{1}}{{z}}=? \\ $$ Answered by iloveisrael last updated on 06/Aug/21 $$\:\mathrm{If}\:\mathrm{2}^{\mathrm{x}}…
Question Number 149599 by muvvakarthik last updated on 06/Aug/21 Terms of Service Privacy Policy Contact: info@tinkutara.com