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Category: Algebra

25-

Question Number 14491 by kailash2177mahto@gmail.com last updated on 01/Jun/17 $$\sqrt{\mathrm{25}} \\ $$$$ \\ $$ Answered by FilupS last updated on 01/Jun/17 $$\mathrm{25}=\left(\pm\mathrm{5}\right)^{\mathrm{2}} \\ $$$$\sqrt{\mathrm{25}}=\sqrt{\left(\pm\mathrm{5}\right)^{\mathrm{2}} }=\pm\mathrm{5}…

lim-n-sin-2-pi-n-2-n-

Question Number 145531 by mathdanisur last updated on 05/Jul/21 $$\underset{{n}\rightarrow\infty} {{lim}sin}^{\mathrm{2}} \pi\:\sqrt{{n}^{\mathrm{2}} +{n}}\:=\:? \\ $$ Answered by Olaf_Thorendsen last updated on 05/Jul/21 $$\mathrm{sin}^{\mathrm{2}} \pi\sqrt{{n}^{\mathrm{2}} +{n}}\:=\:\mathrm{sin}^{\mathrm{2}}…

Question-145525

Question Number 145525 by mathdanisur last updated on 05/Jul/21 Answered by Olaf_Thorendsen last updated on 05/Jul/21 $${f}\left({x}+\mathrm{2}\right)+\mathrm{10}{f}\left({x}\right)\:=\:\mathrm{7}{f}\left({x}+\mathrm{1}\right) \\ $$$${f}\left({x}+\mathrm{2}\right)−\mathrm{7}{f}\left({x}+\mathrm{1}\right)+\mathrm{10}{f}\left({x}\right)\:=\:\mathrm{0} \\ $$$${r}^{\mathrm{2}} −\mathrm{7}{r}+\mathrm{10}\:=\:\mathrm{0} \\ $$$$\left({r}−\mathrm{2}\right)\left({r}−\mathrm{5}\right)\:=\:\mathrm{0} \\…