Question Number 149292 by mathdanisur last updated on 04/Aug/21 $${if}\:\:\:{sin}\mathrm{2}\boldsymbol{\alpha}\:=\:-\:\frac{\mathrm{1}}{\mathrm{3}} \\ $$$${find}\:\:\:\mathrm{3}{tg}^{\mathrm{2}} \left(\frac{\mathrm{3}\boldsymbol{\pi}}{\mathrm{4}}\:-\:\boldsymbol{\alpha}\right)\:=\:? \\ $$ Answered by Ar Brandon last updated on 04/Aug/21 $$\mathrm{sin2}\alpha=−\frac{\mathrm{1}}{\mathrm{3}} \\…
Question Number 149291 by mathdanisur last updated on 04/Aug/21 $${f}\left({x}\right)\:=\:\mathrm{2}{sinx}^{\mathrm{2}} −{cos}^{\mathrm{2}} {x}−\mathrm{2} \\ $$$${f}\:^{'} \left({x}\right)\:=\:? \\ $$ Answered by nimnim last updated on 04/Aug/21 $${f}\:'\left({x}\right)=\mathrm{4}{x}.{cosx}^{\mathrm{2}}…
Question Number 149268 by Samimsultani last updated on 04/Aug/21 Answered by dkenechukwu04 last updated on 04/Aug/21 $$\mathrm{Let}\:\mathrm{2}+\frac{\mathrm{3}}{\mathrm{2}+\frac{\mathrm{3}}{\mathrm{2}+\frac{\mathrm{3}}{\mathrm{2}+…}}}={x} \\ $$$$\mathrm{5}+\frac{\mathrm{2}}{{x}}=\mathrm{5}+\frac{\mathrm{2}}{\mathrm{2}+\frac{\mathrm{3}}{{x}}} \\ $$$$\mathrm{5}+\frac{\mathrm{2}}{{x}}=\mathrm{5}+\frac{\mathrm{2}{x}}{\mathrm{2}{x}+\mathrm{3}} \\ $$$$\frac{\mathrm{5}{x}+\mathrm{2}}{{x}}=\frac{\mathrm{12}{x}+\mathrm{15}}{\mathrm{2}{x}+\mathrm{3}} \\ $$$$\mathrm{10}{x}^{\mathrm{2}}…
Question Number 149271 by Samimsultani last updated on 04/Aug/21 Answered by fred last updated on 04/Aug/21 $${x}^{{x}^{\mathrm{4}} } =\mathrm{4} \\ $$$${x}=\mathrm{4}^{\frac{\mathrm{1}}{\mathrm{4}}} \\ $$ Answered by…
Question Number 149266 by mathdanisur last updated on 04/Aug/21 $${Solve}\:{for}\:{natural}\:{numbers}: \\ $$$${x}^{\mathrm{2}} \:+\:{y}^{\mathrm{2}} \:+{x}\:+\:{y}\:=\:\mathrm{3}{xy} \\ $$ Answered by nimnim last updated on 04/Aug/21 $$\Rightarrow\left({x}+{y}\right)^{\mathrm{2}} +\left({x}+{y}\right)=\mathrm{5}{xy}…
Question Number 83721 by mr W last updated on 05/Mar/20 Commented by MJS last updated on 05/Mar/20 $$−\mathrm{3} \\ $$ Commented by john santu last…
Question Number 149237 by mathdanisur last updated on 03/Aug/21 Answered by Mokmokhi last updated on 04/Aug/21 $$\mathrm{9} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 149240 by john_santu last updated on 04/Aug/21 $$\:\:\mathrm{solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{number}\: \\ $$$$\:\mathrm{x}^{\mathrm{4}} −\mathrm{3x}^{\mathrm{2}} +\mathrm{1}\:=\sqrt{\frac{\mathrm{4}}{\mathrm{4}−\mathrm{x}^{\mathrm{2}} }\:−\mathrm{1}} \\ $$$$\:\: \\ $$ Answered by MJS_new last updated on…
Question Number 149238 by ajfour last updated on 04/Aug/21 $${z}^{\mathrm{3}} −{z}={c} \\ $$$${z}^{\mathrm{4}} −{z}^{\mathrm{2}} ={cz} \\ $$$${let}\:\:{z}={x}+{q} \\ $$$${x}^{\mathrm{4}} +\mathrm{4}{qx}^{\mathrm{3}} +\mathrm{6}{q}^{\mathrm{2}} {x}^{\mathrm{2}} +\mathrm{4}{q}^{\mathrm{3}} {x}+{q}^{\mathrm{4}} \\…
Question Number 149234 by mathdanisur last updated on 03/Aug/21 $$\frac{{x}}{\mathrm{2}}\:+\:{log}_{\mathrm{2}} \left({x}\:+\:\mathrm{12}\right)\:=\:\mathrm{6} \\ $$$$\Rightarrow\:\boldsymbol{{x}}\:=\:? \\ $$ Answered by JDamian last updated on 03/Aug/21 $$\mathrm{4} \\ $$…