Question Number 200729 by mnjuly1970 last updated on 22/Nov/23 $$ \\ $$$$\:\:\:{if}\:\:\:\:{a}<{b}<\mathrm{0}\:\:\: \\ $$$$\:\:\:{and}\:\:\sqrt{\:{a}^{\mathrm{4}} +\mathrm{2}{a}^{\mathrm{2}} {b}^{\mathrm{2}} +{b}^{\mathrm{4}} }\:+\sqrt{{a}^{\mathrm{4}} −\mathrm{2}{a}^{\mathrm{2}} {b}^{\mathrm{2}} +{b}^{\mathrm{4}} }\:=\:? \\ $$$$ \\…
Question Number 200716 by hardmath last updated on 22/Nov/23 $$\mathrm{1}.\: \\ $$$$\frac{{a}}{\mathrm{8}}\:+\:\frac{{b}}{\mathrm{5}}\:=\:\mathrm{6}\:\:\:\Rightarrow\:\:\:\left({a}+{b}\right)_{\boldsymbol{{max}}} \:=\:? \\ $$ Answered by AST last updated on 22/Nov/23 $$\mathrm{5}{a}+\mathrm{8}{b}=\mathrm{240}\Rightarrow{a}=\frac{\mathrm{240}−\mathrm{8}{b}}{\mathrm{5}} \\ $$$${remains}\:{to}\:{find}\:\left({a}+{b}\right)_{{max}}…
Question Number 200723 by hardmath last updated on 22/Nov/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 200717 by hardmath last updated on 22/Nov/23 $$\mathrm{2}. \\ $$$${A}\:=\:\mathrm{12}\:−\:\mathrm{2}{x} \\ $$$${B}\:=\:\mathrm{3}\:+\:\mathrm{2}{x} \\ $$$$\left({A}\centerdot{B}\right)_{\boldsymbol{{min}}} \:=\:? \\ $$ Answered by AST last updated on…
Question Number 200718 by hardmath last updated on 22/Nov/23 $$\mathrm{3}. \\ $$$$\mathrm{1}+\mathrm{3}+\mathrm{5}+\mathrm{7}+…+\left(\mathrm{2}{n}+\mathrm{1}\right)\:=\:? \\ $$ Answered by AST last updated on 22/Nov/23 $$\mathrm{2}+\mathrm{4}+..+\mathrm{2}{n}=\mathrm{2}\left(\mathrm{1}+\mathrm{2}+\mathrm{3}+…+{n}\right)={n}^{\mathrm{2}} +{n} \\ $$$$\mathrm{1}+\mathrm{2}+\mathrm{3}+…+\mathrm{2}{n}+\mathrm{1}=\left(\mathrm{2}{n}+\mathrm{1}\right)\left({n}+\mathrm{1}\right)…
Question Number 200565 by hardmath last updated on 20/Nov/23 $$\mathrm{sin}^{\mathrm{10}} \mathrm{x}\:\:+\:\:\mathrm{cos}^{\mathrm{10}} \mathrm{x}\:\:=\:\:\frac{\mathrm{29}}{\mathrm{16}}\:\mathrm{cos}^{\mathrm{4}} \mathrm{2x} \\ $$$$\mathrm{find}:\:\:\:\mathrm{x}\:=\:? \\ $$ Commented by Harnada last updated on 21/Nov/23 $${Q}\mathrm{200565}…
Question Number 200594 by cherokeesay last updated on 20/Nov/23 Answered by Frix last updated on 21/Nov/23 $$\mathrm{Obviously}\:{x}=\mathrm{3}\:\mathrm{is}\:\mathrm{a}\:\mathrm{solution}. \\ $$$$\mathrm{Then}\:\mathrm{you}\:\mathrm{must}\:\mathrm{approximate}…\:\mathrm{I}\:\mathrm{found} \\ $$$${x}\approx.\mathrm{211793616} \\ $$$${x}\approx−\mathrm{2}.\mathrm{80610974} \\ $$…
Question Number 200589 by Ikbal last updated on 20/Nov/23 Answered by Frix last updated on 20/Nov/23 $$\mathrm{First}\:\mathrm{try}\:\mathrm{factors}\:\mathrm{of}\:\pm\mathrm{40}\:\Rightarrow \\ $$$${x}^{\mathrm{4}} −\mathrm{3}{x}^{\mathrm{2}} −\mathrm{42}{x}−\mathrm{40}= \\ $$$$=\left({x}+\mathrm{1}\right)\left({x}−\mathrm{4}\right)\left({x}^{\mathrm{2}} +\mathrm{3}{x}+\mathrm{10}\right) \\…
Question Number 200498 by mr W last updated on 19/Nov/23 $${solve}\:{for}\:{x}\in{R} \\ $$$$\sqrt{{x}−\frac{\mathrm{1}}{{x}}}+\sqrt{\mathrm{1}−\frac{\mathrm{1}}{{x}}}={x} \\ $$ Commented by BaliramKumar last updated on 19/Nov/23 $$\mathrm{Q}.\:\mathrm{192958} \\ $$…
Question Number 200472 by Mingma last updated on 19/Nov/23 Terms of Service Privacy Policy Contact: info@tinkutara.com