Question Number 79852 by Pratah last updated on 28/Jan/20 Commented by MJS last updated on 28/Jan/20 $$\mathrm{Sir}\:\mathrm{Pratah},\:\mathrm{how}\:\mathrm{old}\:\mathrm{are}\:\mathrm{you}?\:\mathrm{this}\:\mathrm{can}\:\mathrm{be} \\ $$$$\mathrm{solved}\:\mathrm{by}\:\mathrm{any}\:\mathrm{13}\:\mathrm{years}\:\mathrm{old}\:\mathrm{student} \\ $$ Answered by key of…
Question Number 145383 by mathdanisur last updated on 04/Jul/21 $${if}\:\:{a};{b};{c}\in\mathbb{R}^{+} \\ $$$${find}\:\:\left(\sqrt[{\mathrm{3}}]{{abc}}\:+\:\frac{\mathrm{1}}{{a}}\:+\:\frac{\mathrm{1}}{\mathrm{2}{b}}\:+\:\frac{\mathrm{1}}{\mathrm{4}{c}}\right)_{\boldsymbol{{min}}} =\:? \\ $$ Answered by mnjuly1970 last updated on 04/Jul/21 $$\:\mathrm{A}\:\geqslant\:\sqrt[{\mathrm{3}}]{{abc}}\:+\mathrm{3}\sqrt[{\mathrm{3}}]{\frac{\mathrm{1}}{\mathrm{8}{abc}}} \\ $$$$\:\:\:\:\:\:=\sqrt[{\mathrm{3}}]{{abc}}\:+\frac{\mathrm{3}}{\mathrm{2}}\sqrt[{\mathrm{3}}]{\frac{\mathrm{1}}{{abc}}}\:\overset{{am}−{gm}}…
Question Number 79826 by Pratah last updated on 28/Jan/20 Commented by Pratah last updated on 28/Jan/20 $$\mathrm{please}\:\:\mathrm{solution}.\:\:\mathrm{help} \\ $$ Commented by mr W last updated…
Question Number 145344 by mathdanisur last updated on 04/Jul/21 $$\boldsymbol{{z}}^{\mathrm{4}} \:=\:\mathrm{49}\:-\:\mathrm{20}\sqrt{\mathrm{6}}\:\:\Rightarrow\:\boldsymbol{{z}}=? \\ $$ Answered by liberty last updated on 04/Jul/21 $$\:{z}^{\mathrm{2}} \:=\:\sqrt{\mathrm{49}−\mathrm{2}\sqrt{\mathrm{600}}}\:=\sqrt{\left(\mathrm{25}+\mathrm{24}\right)−\mathrm{2}\sqrt{\mathrm{25}×\mathrm{24}}} \\ $$$${z}^{\mathrm{2}} \:=\:\sqrt{\mathrm{25}}−\sqrt{\mathrm{24}}\:=\:\mathrm{5}−\mathrm{2}\sqrt{\mathrm{6}}\:…
Question Number 79807 by Pratah last updated on 28/Jan/20 Commented by Pratah last updated on 28/Jan/20 $$\mathrm{thanks}\:\mathrm{sir} \\ $$ Commented by john santu last updated…
Question Number 145337 by physicstutes last updated on 04/Jul/21 $$\mathrm{The}\:\mathrm{Area}\:\mathrm{of}\:\mathrm{a}\:\mathrm{square},{A}\left({t}\right),\mathrm{is}\:\mathrm{increased}\:\mathrm{at}\:\mathrm{a}\:\mathrm{rate} \\ $$$$\mathrm{equal}\:\mathrm{to}\:\mathrm{its}\:\mathrm{perimeter}\:,{A}\left({t}\right)\:\mathrm{satisfies}\:\mathrm{the}\:\mathrm{differential} \\ $$$$\mathrm{equation}\:\frac{{dA}}{{dt}}= \\ $$$$\mathrm{A}.\:\mathrm{4}{A}\:\:\:\:\:\:\:\:\:\mathrm{B}.\:\mathrm{2}{A}\:\:\:\:\:\:\:\:\:\mathrm{C}.−\mathrm{4}\sqrt{{A}}\:\:\:\:\:\:\:\:\mathrm{D}.\:\mathrm{4}\sqrt{{A}} \\ $$ Answered by gsk2684 last updated on 06/Jul/21…
Question Number 145336 by physicstutes last updated on 04/Jul/21 $$\mathrm{Which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{linear}\:\mathrm{diophantine}\:\mathrm{equations}\:\mathrm{has} \\ $$$$\mathrm{positive}\:\mathrm{solutions}, \\ $$$$\mathrm{A}.\:{x}+\:\mathrm{5}{y}\:=\:\mathrm{7} \\ $$$$\mathrm{B}.\:{x}+\mathrm{5}{y}\:=\:\mathrm{3} \\ $$$$\mathrm{B}.\:{x}\:+\:\mathrm{5}{y}\:=\:\mathrm{2} \\ $$$$\mathrm{C}.\:{x}+\:\mathrm{5}{y}\:=\:\mathrm{1} \\ $$ Commented by Rasheed.Sindhi…
Question Number 145324 by mathdanisur last updated on 04/Jul/21 $$\int\:\frac{{dx}}{\mathrm{1}\:+\:{x}^{\mathrm{6}} }\:=\:? \\ $$ Answered by Olaf_Thorendsen last updated on 04/Jul/21 $$\frac{\mathrm{1}}{\mathrm{6}}\mathrm{atan}\left(\frac{{x}}{\mathrm{1}−{x}^{\mathrm{2}} }\right)+\frac{\mathrm{1}}{\mathrm{3}}\mathrm{atan}{x}+\frac{\sqrt{\mathrm{3}}}{\mathrm{12}}\mathrm{ln}\mid\frac{{x}^{\mathrm{2}} +\sqrt{\mathrm{3}}{x}+\mathrm{1}}{{x}^{\mathrm{2}} −\sqrt{\mathrm{3}}{x}+\mathrm{1}}\mid+\mathrm{C} \\…
Question Number 79792 by mr W last updated on 28/Jan/20 $${JUST}\:{FOR}\:{FUN} \\ $$$$ \\ $$$$\frac{\mathrm{1}}{\mathrm{2}},\:\frac{\mathrm{2}}{\mathrm{3}},\:\mathrm{1},\:\frac{\mathrm{8}}{\mathrm{5}},\:\frac{\mathrm{8}}{\mathrm{3}},\:? \\ $$$${what}\:{do}\:{you}\:{think}\:{is}\:{the}\:{next}\:{number}\:? \\ $$$${why}? \\ $$ Commented by jagoll last…
Question Number 14245 by Ruth1 last updated on 30/May/17 $$\mathrm{pls}\:\mathrm{no};\:\mathrm{6},\mathrm{7},\mathrm{10},\mathrm{11},\mathrm{and}\:\mathrm{13} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com