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Category: Algebra

Question-12368

Question Number 12368 by sin (x) last updated on 20/Apr/17 Answered by mrW1 last updated on 22/Apr/17 $${EF}×\mathrm{cot}\:\mathrm{55}+{EF}×\mathrm{cot}\:\mathrm{35}+\mathrm{4}=\mathrm{10} \\ $$$${EF}×\mathrm{tan}\:\:\mathrm{35}+{EF}×\mathrm{tan}\:\:\mathrm{55}=\mathrm{6} \\ $$$${EF}=\frac{\mathrm{6}}{\mathrm{tan}\:\mathrm{35}+\mathrm{tan}\:\mathrm{55}}=\mathrm{2}.\mathrm{819}\approx\mathrm{3} \\ $$$$\Rightarrow{Answer}\:\boldsymbol{{A}} \\…

Find-matrix-rank-47-67-35-201-155-26-98-23-294-86-16-428-1-1284-53-

Question Number 143436 by mathdanisur last updated on 14/Jun/21 $${Find}\:{matrix}\:{rank}=? \\ $$$$\begin{pmatrix}{\mathrm{47}}&{−\mathrm{67}}&{\mathrm{35}}&{\mathrm{201}}&{\mathrm{155}}\\{\mathrm{26}}&{\mathrm{98}}&{\mathrm{23}}&{−\mathrm{294}}&{\mathrm{86}}\\{\mathrm{16}}&{−\mathrm{428}}&{\mathrm{1}}&{\mathrm{1284}}&{\mathrm{53}}\end{pmatrix} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

2-3-2-5-2-3-2-5-10-2-3-Can-you-solve-this-without-solving-them-manually-

Question Number 12361 by Joel576 last updated on 20/Apr/17 $$\left(\sqrt{\mathrm{2}}\:+\sqrt{\mathrm{3}}\:+\mathrm{2}\:+\:\sqrt{\mathrm{5}}\right)\left(−\sqrt{\mathrm{2}}\:+\:\sqrt{\mathrm{3}}\:+\:\mathrm{2}\:−\:\sqrt{\mathrm{5}}\right)\left(\sqrt{\mathrm{10}}\:+\:\mathrm{2}\sqrt{\mathrm{3}}\right) \\ $$$$ \\ $$$$\mathrm{Can}\:\mathrm{you}\:\mathrm{solve}\:\mathrm{this}\:\mathrm{without}\:\mathrm{solving}\:\mathrm{them}\:\mathrm{manually}? \\ $$ Answered by ajfour last updated on 20/Apr/17 $$\left({a}+{b}+{c}+{d}\right)\left({b}+{c}−{a}−{d}\right)\left({ad}+{bc}\right) \\…

Question-12359

Question Number 12359 by sin (x) last updated on 20/Apr/17 Answered by ajfour last updated on 20/Apr/17 $${for}\:{given}\:{range}\:{of}\:\boldsymbol{{a}}\:{and}\:\boldsymbol{{b}}, \\ $$$$\left(\boldsymbol{{a}}^{\mathrm{4}} +\boldsymbol{{b}}^{\mathrm{3}} \right)_{\boldsymbol{{max}}} \:=\:\mathrm{1}−\frac{\mathrm{1}}{\mathrm{8}}=\:\frac{\mathrm{7}}{\mathrm{8}} \\ $$$$\left(\boldsymbol{{a}}^{\mathrm{4}}…

if-f-x-is-polynomial-satisfying-f-x-f-1-x-2f-x-2f-1-x-5-and-f-2-14-then-f-3-

Question Number 143427 by bramlexs22 last updated on 14/Jun/21 $${if}\:{f}\left({x}\right)\:{is}\:{polynomial}\:{satisfying} \\ $$$${f}\left({x}\right){f}\left(\frac{\mathrm{1}}{{x}}\right)−\mathrm{2}{f}\left({x}\right)+\mathrm{2}{f}\left(\frac{\mathrm{1}}{{x}}\right)=\mathrm{5} \\ $$$${and}\:{f}\left(\mathrm{2}\right)=\mathrm{14}\:{then}\:{f}\left(\mathrm{3}\right)=? \\ $$ Answered by qaz last updated on 14/Jun/21 $$\begin{cases}{\mathrm{f}\left(\mathrm{x}\right)\mathrm{f}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)−\mathrm{2f}\left(\mathrm{x}\right)+\mathrm{2f}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)=\mathrm{5}…….\left(\mathrm{1}\right)}\\{\mathrm{f}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)\mathrm{f}\left(\mathrm{x}\right)−\mathrm{2f}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)+\mathrm{2f}\left(\mathrm{x}\right)=\mathrm{5}…….\left(\mathrm{2}\right)}\end{cases} \\…

solve-for-x-1-x-a-x-b-x-b-x-c-x-c-x-a-d-a-b-c-d-R-try-for-a-4-b-3-c-2-d-1-2-x-a-2-x-a-x-a-x-a-2-a-2-a-1-3-x-a-2-x-2-a-x-2-a-x-a-2-a-2-a-

Question Number 77885 by behi83417@gmail.com last updated on 11/Jan/20 $$\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\::\:\boldsymbol{\mathrm{x}} \\ $$$$\mathrm{1}.\sqrt{\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{a}}\right)\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{b}}\right)}+\sqrt{\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{b}}\right)\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{c}}\right)}+\sqrt{\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{c}}\right)\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{a}}\right)}=\boldsymbol{\mathrm{d}} \\ $$$$\left[\boldsymbol{\mathrm{a}},\boldsymbol{\mathrm{b}},\boldsymbol{\mathrm{c}},\boldsymbol{\mathrm{d}}\in\boldsymbol{\mathrm{R}}\right. \\ $$$$\left.\mathrm{try}\:\mathrm{for}:\:\:\mathrm{a}=\mathrm{4},\mathrm{b}=\mathrm{3},\mathrm{c}=\mathrm{2},\mathrm{d}=\mathrm{1}\right] \\ $$$$\mathrm{2}.\:\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{a}}^{\mathrm{2}} \right)\sqrt{\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{a}}}+\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{a}}\right)\sqrt{\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{a}}^{\mathrm{2}} }=\boldsymbol{\mathrm{a}}^{\mathrm{2}} +\boldsymbol{\mathrm{a}}+\mathrm{1} \\ $$$$\mathrm{3}.\:\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{a}}^{\mathrm{2}} \right)\sqrt{\boldsymbol{\mathrm{x}}^{\mathrm{2}} −\boldsymbol{\mathrm{a}}}+\left(\boldsymbol{\mathrm{x}}^{\mathrm{2}}…

Question-143418

Question Number 143418 by help last updated on 14/Jun/21 Answered by physicstutes last updated on 14/Jun/21 $$\mathrm{3}.\mathrm{1}\:{y}\:=\:\mathrm{cos}^{\mathrm{2}} {x}^{\mathrm{2}} +\left(\mathrm{3}−\sqrt{{x}}\right)^{\mathrm{30}} −\mathrm{2}^{{x}} \\ $$$$\mathrm{Let}\:{y}_{\mathrm{1}} \:=\:\mathrm{cos}^{\mathrm{2}} {x}^{\mathrm{2}} ,\:\:{y}_{\mathrm{1}}…