Menu Close

Category: Algebra

Find-lim-n-1-n-2n-n-

Question Number 205885 by hardmath last updated on 01/Apr/24 Find:limnn(2nn)=? Answered by MM42 last updated on 03/Apr/24 (2nn)=(2n)(2n1)(2n2)(n+3)(n+2)(n+1)n(n1)(n2)3×2×1a=n(2nn)$$\Rightarrow{lna}=\frac{\mathrm{1}}{{n}}\left[{ln}\left(\mathrm{2}\right)+{ln}\left(\mathrm{2}+\frac{\mathrm{1}}{{n}−\mathrm{1}}\right)+{ln}\left(\mathrm{2}+\frac{\mathrm{2}}{{n}−\mathrm{2}}\right)+…+{ln}\left(\mathrm{2}+\frac{{n}−\mathrm{3}}{\mathrm{3}}\right)\left(\mathrm{2}+\frac{{n}−\mathrm{2}}{\mathrm{2}}\right)\left(\mathrm{2}+\frac{{n}−\mathrm{1}}{\mathrm{1}}\right)\right.…