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Question Number 144767 by mnjuly1970 last updated on 29/Jun/21 Answered by Rasheed.Sindhi last updated on 29/Jun/21 $$\left({x}^{\mathrm{3}} −\frac{\mathrm{2}}{{x}^{\mathrm{2}} }\right)^{{m}} ={a}_{\mathrm{0}} +{a}_{\mathrm{1}} {x}+{a}_{\mathrm{2}} {x}^{\mathrm{2}} +…+{a}_{{n}} {x}^{{n}}…