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Category: Algebra

Question-77451

Question Number 77451 by BK last updated on 06/Jan/20 Commented by MJS last updated on 06/Jan/20 $$\mathrm{anyway}\:\mathrm{the}\:\mathrm{question}\:\mathrm{is}\:\mathrm{stupid}.\:\mathrm{there}\:\mathrm{is}\:\mathrm{only} \\ $$$$\mathrm{one}\:\mathrm{power}\:\mathrm{of}\:\mathrm{7}\:\mathrm{in}\:\mathrm{50}! \\ $$ Answered by mr W…

Turevlenebilir-bir-f-fonksiyonu-icin-f-x-y-f-x-f-y-2xy-ve-f-0-3-old-gore-f-2-czm-f-x-y-f-x-f-y-2xy-y-yi-sabit-kabul-edersek-f-x-y-f-x-2y-x-0-y-2-icn-f-2-f-0-2-2-f-2-3-4-1-

Question Number 11914 by ahmet last updated on 04/Apr/17 $${Turevlenebilir}\:{bir}\:{f}\:{fonksiyonu}\:{icin} \\ $$$${f}\left({x}+{y}\right)={f}\left({x}\right)+{f}\left({y}\right)+\mathrm{2}{xy}\:{ve}\:{f}'\left(\mathrm{0}\right)=−\mathrm{3} \\ $$$${old}.{gore}\:{f}'\left(\mathrm{2}\right)=? \\ $$$${czm}\because\:\:{f}\left({x}+{y}\right)={f}\left({x}\right)+{f}\left({y}\right)+\mathrm{2}{xy} \\ $$$${y}\:{yi}\:{sabit}\:{kabul}\:{edersek} \\ $$$${f}'\left({x}+{y}\right)={f}'\left({x}\right)+\mathrm{2}{y} \\ $$$${x}=\mathrm{0},{y}=\mathrm{2}\:{icn} \\ $$$${f}'\left(\mathrm{2}\right)={f}'\left(\mathrm{0}\right)+\mathrm{2}.\mathrm{2} \\…

Question-142986

Question Number 142986 by mnjuly1970 last updated on 08/Jun/21 Commented by MJS_new last updated on 08/Jun/21 $$\mathrm{if}\:{y}={x}\:\mathrm{the}\:\mathrm{expression}\:\mathrm{is}\:\mathrm{constantly}\:\:\sqrt[{\mathrm{3}}]{\mathrm{4}} \\ $$ Commented by mnjuly1970 last updated on…

7cos-2-x-sin-2-x-3-2cos-2-x-sin-2-x-czm-7cos-2-x-1-cos-2-x-3-2cos-2-x-sin-2-x-6cos-2-x-2-2cos-2-x-1-cos-2-x-6cos-2-x-2-3cos-2-x-1-2-3cos-2-x-1-3cos-2-x-1-2-

Question Number 11901 by ahmet last updated on 04/Apr/17 $$\frac{\mathrm{7}{cos}^{\mathrm{2}} {x}+{sin}^{\mathrm{2}} {x}−\mathrm{3}}{\mathrm{2}{cos}^{\mathrm{2}} {x}−{sin}^{\mathrm{2}} {x}}=? \\ $$$${czm}\because\:\:\frac{\mathrm{7}{cos}^{\mathrm{2}} {x}+\mathrm{1}−{cos}^{\mathrm{2}} {x}−\mathrm{3}}{\mathrm{2}{cos}^{\mathrm{2}} {x}−{sin}^{\mathrm{2}} {x}} \\ $$$$\frac{\mathrm{6}{cos}^{\mathrm{2}} {x}−\mathrm{2}}{\mathrm{2}{cos}^{\mathrm{2}} {x}−\left(\mathrm{1}−{cos}^{\mathrm{2}} {x}\right)}=\frac{\mathrm{6}{cos}^{\mathrm{2}}…

Given-p-lt-x-lt-q-is-solution-set-inequality-1-2-x-2-2x-2-3x-gt-2-for-x-1-find-the-value-of-5p-3q-

Question Number 142968 by bramlexs22 last updated on 08/Jun/21 $${Given}\:{p}<{x}<{q}\:{is}\:{solution}\:{set} \\ $$$${inequality}\:\mathrm{1}+\mathrm{2}^{{x}} +\mathrm{2}^{\mathrm{2}{x}} +\mathrm{2}^{\mathrm{3}{x}} +…>\mathrm{2} \\ $$$${for}\:{x}\neq\mathrm{1}.\:{find}\:{the}\:{value}\:{of}\: \\ $$$$\mathrm{5}{p}−\mathrm{3}{q}\:. \\ $$ Answered by mr W…

Question-77412

Question Number 77412 by BK last updated on 06/Jan/20 Commented by Tony Lin last updated on 06/Jan/20 $$\zeta\left({s}\right)=\frac{\mathrm{1}}{\mathrm{1}^{{s}} }+\frac{\mathrm{1}}{\mathrm{2}^{{s}} }+\frac{\mathrm{1}}{\mathrm{3}^{{s}} }+\centerdot\centerdot\centerdot+\frac{\mathrm{1}}{{n}^{{s}} } \\ $$$$\zeta\left(\mathrm{2}\right)=\frac{\mathrm{1}}{\mathrm{1}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}}…