Category: Algebra

Question Number 131309 by shaker last updated on 03/Feb/21 Answered by Ar Brandon last updated on 03/Feb/21 $${\mathrm{z}}^5+\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}\mathrm{i}=0\Rightarrow {\mathrm{z}}^5+{\mathrm{e}}^{\frac{\pi }{4}\mathrm{i}}=0$$$$\mathrm{z}^{\mathrm{5}} =−\mathrm{e}^{\frac{\pi}{\mathrm{4}}\mathrm{i}} =\mathrm{e}^{\frac{\pi}{\mathrm{4}}\mathrm{i}+\left(\mathrm{2k}+\mathrm{1}\right)\pi\mathrm{i}}…

Question Number 65745 by KanhAshish last updated on 03/Aug/19 Commented by KanhAshish last updated on 03/Aug/19 $$15\mathrm{and}16\mathrm{both}\mathrm{solution}??$$ Terms of Service Privacy Policy Contact:…

Question Number 65724 by bshahid010@gmail.com last updated on 02/Aug/19 Answered by mr W last updated on 03/Aug/19 $$S=\sin x+\cos x+\frac{1}{\sin x}+\frac{1}{\cos x}+\frac{\sin x}{\cos x}+\frac{\cos x}{\sin x}$$$$=\sin x+\cos x+\frac{\sin x+\cos x}{\sin x\cos x}+\frac{1}{\sin x\cos x}$$$$=\sin x+\cos x+\frac{\sin x+\cos x+1}{\sin x\cos x}$$$${let}\:\mathrm{sin}\:{x}+\mathrm{cos}\:{x}={t} \…

Question Number 65680 by bshahid010@gmail.com last updated on 01/Aug/19 Answered by mr W last updated on 02/Aug/19 Commented by mr W last updated on 02/Aug/19…

Question Number 131218 by shaker last updated on 02/Feb/21 Answered by mathmax by abdo last updated on 02/Feb/21 $$\mathrm{I}\:=\int_{−\mathrm{2}} ^{\mathrm{2}} \:\frac{\sqrt{\mathrm{4}−\mathrm{x}^{\mathrm{2}} }}{\mathrm{4}^{\mathrm{x}} \:+\mathrm{1}}\:\Rightarrow\mathrm{I}\:=_{\mathrm{x}=−\mathrm{t}} \:\:\:\int_{−\mathrm{2}} ^{\mathrm{2}}…