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Question Number 11228 by uni last updated on 17/Mar/17 Answered by mrW1 last updated on 17/Mar/17 $$\left(_{\mathrm{2}} ^{\mathrm{6}} \right)×\left(_{\mathrm{1}} ^{\mathrm{4}} \right)+\left(_{\mathrm{2}} ^{\mathrm{4}} \right)×\left(_{\mathrm{1}} ^{\mathrm{6}} \right)=\frac{\mathrm{6}×\mathrm{5}}{\mathrm{2}}×\mathrm{4}+\frac{\mathrm{4}×\mathrm{3}}{\mathrm{2}}×\mathrm{6}=\mathrm{96}…
Question Number 11212 by uni last updated on 17/Mar/17 Answered by mrW1 last updated on 17/Mar/17 $$\mathrm{2}{x}=\mathrm{25}−\mathrm{5}{y}=\mathrm{5}\left(\mathrm{5}−{y}\right) \\ $$$${x}=\frac{\mathrm{5}\left(\mathrm{5}−{y}\right)}{\mathrm{2}} \\ $$$$\mathrm{5}−{y}\:{must}\:{be}\:{even}: \\ $$$$\Rightarrow\mathrm{5}−{y}=\mathrm{2}{k},\:{k}\in\mathbb{N} \\ $$$${y}=\mathrm{5}−\mathrm{2}{k}>\mathrm{0}…
Question Number 11214 by uni last updated on 17/Mar/17 Answered by FilupS last updated on 17/Mar/17 $${a}+\frac{{b}}{{a}}=\mathrm{4}\:\:\Rightarrow\:\:{b}={a}\left(\mathrm{4}−{a}\right) \\ $$$$\because{a}\in\mathbb{Z}\:\:\mathrm{and}\:\:\mathrm{RHS}\in\mathbb{Z},\:\therefore{b}\in\mathbb{Z} \\ $$$$\: \\ $$$$\therefore{a}=\frac{{b}}{\mathrm{4}−{a}} \\ $$$$\because{a}\in\mathbb{Z},\:\:\:\frac{{b}}{\mathrm{4}−{a}}\in\mathbb{Z},\:\:\:\:\:\therefore\left(\mathrm{4}−{a}\right)\:\mathrm{is}\:\mathrm{a}\:\mathrm{factor}…
Question Number 11206 by uni last updated on 16/Mar/17 Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 16/Mar/17 $${AD}.{AC}=\mathrm{6}×\mathrm{24}=\mathrm{144} \\ $$$${AD}^{\mathrm{2}} +{AC}^{\mathrm{2}} =\mathrm{24}^{\mathrm{2}} =\mathrm{576} \\ $$$$\left({AD}+{AC}\right)^{\mathrm{2}} =\mathrm{576}+\mathrm{2}×\mathrm{144}=\mathrm{6}×\mathrm{144}\Rightarrow…
Question Number 11203 by FilupS last updated on 16/Mar/17 $${f}\left({x}\right)=\left(\frac{{x}}{{x}+\mathrm{1}}−\frac{{x}}{{x}−\mathrm{1}}\right)^{−\mathrm{1}} =−\frac{\left({x}+\mathrm{1}\right)\left({x}−\mathrm{1}\right)}{\mathrm{2}{x}} \\ $$$${g}\left({x}\right)=−\frac{\mathrm{1}}{\mathrm{2}}{x} \\ $$$$\: \\ $$$$\mathrm{why}\:\mathrm{is}\:{f}\left({x}\right)\approx{g}\left({x}\right)? \\ $$ Answered by mrW1 last updated on…
Question Number 76725 by Rio Michael last updated on 29/Dec/19 $$\mathrm{To}\:\mathrm{prove}\:\mathrm{that}\:\mathrm{x}^{\mathrm{2}} >\mathrm{y}^{\mathrm{2}} ,\:\mathrm{it}\:\mathrm{is}\:\mathrm{sufficient}\:\mathrm{to}\: \\ $$$$\mathrm{prove}\:\mathrm{that}\: \\ $$$$\mathrm{A}.\:\mathrm{x}\:>\:\mathrm{y} \\ $$$$\mathrm{B}.\:\mathrm{x}^{\mathrm{3}} >\mathrm{y}^{\mathrm{3}} \\ $$$$\mathrm{C}.\:\mid\mathrm{x}\mid\:>\:\mid\mathrm{y}\mid \\ $$$$\mathrm{D}.\:\mathrm{x}\:>\:\mathrm{3y} \\…
Question Number 76721 by Rio Michael last updated on 29/Dec/19 $$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{mean}\:\mathrm{value}\:\mathrm{of}\:\frac{\mathrm{1}}{\mathrm{1}+\mathrm{4x}^{\mathrm{2}\:} }\:\:\mathrm{for}\:\:\mathrm{0}\leqslant\mathrm{x}\leqslant\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Answered by MJS last updated on 30/Dec/19 $$\mathrm{mean}\:\left({f}\left({x}\right)\right)\:\mathrm{with}\:{a}\leqslant{x}\leqslant{b} \\ $$$$\frac{\mathrm{1}}{{b}−{a}}\underset{{a}} {\overset{{b}}…
Question Number 76714 by peter frank last updated on 29/Dec/19 $${If}\:{y}=\sqrt{\mathrm{tan}\:{x}+\sqrt{\mathrm{tan}\:{x}+\sqrt{\mathrm{tan}\:{x}+….\infty}}}\: \\ $$$${prove}\:{that} \\ $$$$\frac{{dy}}{{dx}}=\frac{\mathrm{sec}\:^{\mathrm{2}} {x}}{\mathrm{2}{y}−\mathrm{1}} \\ $$ Answered by mind is power last updated…
Question Number 76713 by peter frank last updated on 29/Dec/19 $${If}\:\mathrm{cos}\:{y}={x}\mathrm{cos}\:\left({a}+{y}\right),{show} \\ $$$${that}\:\frac{{dy}}{{dx}}=\frac{\mathrm{cos}\:^{\mathrm{2}} \left({a}+{y}\right)}{\mathrm{sin}\:{a}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com