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Category: Algebra

x-3-7x-6-0-prove-that-x-2-3-1-

Question Number 75913 by ajfour last updated on 21/Dec/19 $${x}^{\mathrm{3}} −\mathrm{7}{x}+\mathrm{6}=\mathrm{0} \\ $$$${prove}\:{that}\:{x}=\mathrm{2},−\mathrm{3},\mathrm{1}\:. \\ $$ Commented by TawaTawa last updated on 21/Dec/19 $$\mathrm{Sir},\:\mathrm{please}\:\mathrm{solve}\:\mathrm{it},\:\mathrm{i}\:\mathrm{want}\:\mathrm{to}\:\mathrm{learn}\:\mathrm{your}\:\mathrm{approach}. \\ $$…

show-that-3-3h-g-and-use-the-similar-expression-to-to-deduce-that-3-3h-g-

Question Number 10352 by j.masanja06@gmail.com last updated on 05/Feb/17 $$\mathrm{show}\:\mathrm{that}\:\alpha^{\mathrm{3}} =−\mathrm{3h}\alpha−\mathrm{g}\:\:\:\mathrm{and}\:\:\mathrm{use}\:\mathrm{the}\: \\ $$$$\mathrm{similar}\:\mathrm{expression}\:\mathrm{to}\:\:\alpha,\gamma\:\:\mathrm{to}\:\mathrm{deduce}\: \\ $$$$\mathrm{that}\:\alpha^{\mathrm{3}} =−\mathrm{3h}\Sigma\alpha\:−\mathrm{g} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

show-that-4-3h-2-g-and-deduce-that-4-3h-2-g-and-find-2-3-4-in-term-of-g-and-h-

Question Number 10353 by j.masanja06@gmail.com last updated on 05/Feb/17 $$\mathrm{show}\:\mathrm{that}\:\alpha^{\mathrm{4}} =−\mathrm{3h}\alpha^{\mathrm{2}} −\mathrm{g}\alpha\:\mathrm{and}\:\mathrm{deduce} \\ $$$$\mathrm{that}\:\Sigma\alpha^{\mathrm{4}} =−\mathrm{3h}\Sigma\alpha^{\mathrm{2}} −\mathrm{g}\Sigma\alpha\:\mathrm{and}\:\mathrm{find}\: \\ $$$$\Sigma\alpha^{\mathrm{2}} ,\Sigma\alpha^{\mathrm{3}} ,\Sigma\alpha^{\mathrm{4}} \:\:\mathrm{in}\:\mathrm{term}\:\mathrm{of}\:\mathrm{g}\:\mathrm{and}\:\mathrm{h}. \\ $$ Terms of…

If-a-4-b-4-c-4-d-4-16-Prove-that-a-5-b-5-c-5-d-5-32-

Question Number 75883 by TawaTawa last updated on 19/Dec/19 $$\mathrm{If}\:\:\:\:\mathrm{a}^{\mathrm{4}} \:+\:\mathrm{b}^{\mathrm{4}} \:+\:\mathrm{c}^{\mathrm{4}} \:+\:\mathrm{d}^{\mathrm{4}} \:\:\:=\:\:\:\mathrm{16} \\ $$$$\mathrm{Prove}\:\mathrm{that},\:\:\:\:\:\:\:\:\mathrm{a}^{\mathrm{5}} \:+\:\mathrm{b}^{\mathrm{5}} \:+\:\mathrm{c}^{\mathrm{5}} \:+\:\mathrm{d}^{\mathrm{5}} \:\:\:\leqslant\:\:\:\mathrm{32} \\ $$ Commented by prakash…

A-1-2-3-n-2-B-15-16-n-A-B-42-n-

Question Number 10347 by konen last updated on 04/Feb/17 $$\mathrm{A}=\mathrm{1}+\mathrm{2}+\mathrm{3}+…+\mathrm{n}−\mathrm{2} \\ $$$$\mathrm{B}=\mathrm{15}+\mathrm{16}+…..+\mathrm{n} \\ $$$$\mathrm{A}−\mathrm{B}=\mathrm{42}\Rightarrow\mathrm{n}=? \\ $$ Answered by mrW1 last updated on 05/Feb/17 $${A}=\underset{{k}=\mathrm{1}} {\overset{{n}−\mathrm{2}}…

A-1-2-2-4-3-6-14-28-B-1-3-2-3-14-29-B-

Question Number 10340 by konen last updated on 04/Feb/17 $$\mathrm{A}=\mathrm{1}×\mathrm{2}\:+\mathrm{2}×\mathrm{4}\:+\mathrm{3}×\mathrm{6}+…+\mathrm{14}×\mathrm{28} \\ $$$$\mathrm{B}=\mathrm{1}×\mathrm{3}\:+\mathrm{2}×\mathrm{3}\:+…+\mathrm{14}×\mathrm{29} \\ $$$$\Rightarrow\mathrm{B}=? \\ $$ Commented by mrW1 last updated on 04/Feb/17 $${the}\:{definition}\:{of}\:{B}\:{is}\:{not}\:{clear}. \\…

A-1-2-2-3-3-4-10-11-B-3-8-6-12-9-16-30-44-A-B-

Question Number 10339 by konen last updated on 04/Feb/17 $$\mathrm{A}=\mathrm{1}×\mathrm{2}\:+\:\mathrm{2}×\mathrm{3}\:+\mathrm{3}×\mathrm{4}+…+\mathrm{10}×\mathrm{11} \\ $$$$\mathrm{B}=\mathrm{3}×\mathrm{8}\:+\mathrm{6}×\mathrm{12}\:+\mathrm{9}×\mathrm{16}+…+\mathrm{30}×\mathrm{44} \\ $$$$\Rightarrow\frac{\mathrm{A}}{\mathrm{B}}=? \\ $$ Answered by mrW1 last updated on 04/Feb/17 $${a}_{{n}} ={n}×\left({n}+\mathrm{1}\right)…

Question-10324

Question Number 10324 by amir last updated on 04/Feb/17 Answered by mrW1 last updated on 04/Feb/17 $${y}=\frac{\mathrm{1}}{{x}} \\ $$$${slope}\:{of}\:{tangent}\:{line}: \\ $$$${m}_{{t}} \left({x}\right)=\mathrm{tan}\:\theta={y}'\left({x}\right)=−\frac{\mathrm{1}}{{x}^{\mathrm{2}} } \\ $$$${let}\:{B}\left({t},{s}\right)\:{be}\:{a}\:{point}\:{on}\:{the}\:{curve}\:…

Question-10323

Question Number 10323 by amir last updated on 04/Feb/17 Answered by mrW1 last updated on 04/Feb/17 $${there}\:{are}\:\mathrm{4}\:{circles}\:{which}\:{tangent} \\ $$$${the}\:{curve}\:{and}\:{the}\:{both}\:{coordinate}\:{axes}. \\ $$$${they}\:{tangent}\:{the}\:{curve}\:{at}\:{point}\:\left(\mathrm{1},\mathrm{1}\right) \\ $$$${as}\:{well}\:{as}\:{at}\:{point}\left(−\mathrm{1},−\mathrm{1}\right). \\ $$$$…