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Category: Algebra

4a-b-60-2-a-b-6-a-b-

Question Number 10213 by konen last updated on 30/Jan/17 $$\mathrm{4a}−\mathrm{b}=\mathrm{60} \\ $$$$\mathrm{2}\sqrt{\mathrm{a}}−\sqrt{\mathrm{b}}=\mathrm{6} \\ $$$$\Rightarrow\mathrm{a}+\mathrm{b}=? \\ $$ Answered by nume1114 last updated on 30/Jan/17 $$\:\:\:\:\:\left(\mathrm{2}\sqrt{{a}}−\sqrt{{b}}\right)\left(\mathrm{2}\sqrt{{a}}+\sqrt{{b}}\right)=\mathrm{4}{a}−{b} \\…

without-solving-for-x-in-f-x-0-show-me-a-different-way-to-find-the-roots-of-f-x-x-2-x-1-

Question Number 10211 by FilupSmith last updated on 30/Jan/17 $$\mathrm{without}\:\mathrm{solving}\:\mathrm{for}\:{x}\:\mathrm{in}\:{f}\left({x}\right)=\mathrm{0}, \\ $$$$\mathrm{show}\:\mathrm{me}\:\mathrm{a}\:\mathrm{different}\:\mathrm{way}\:\mathrm{to}\:\mathrm{find}\:\mathrm{the} \\ $$$$\mathrm{roots}\:\mathrm{of}\:{f}\left({x}\right)={x}^{\mathrm{2}} −{x}−\mathrm{1} \\ $$ Commented by prakash jain last updated on 30/Jan/17…

x-y-12-x-y-16-x-y-y-x-

Question Number 10212 by konen last updated on 30/Jan/17 $$\mathrm{x}+\mathrm{y}=\mathrm{12} \\ $$$$\mathrm{x}×\mathrm{y}=\mathrm{16} \\ $$$$\Rightarrow\sqrt{\frac{\mathrm{x}}{\mathrm{y}}}−\sqrt{\frac{\mathrm{y}}{\mathrm{x}}}\:=? \\ $$ Answered by ridwan balatif last updated on 30/Jan/17 $$\mathrm{x}+\mathrm{y}=\mathrm{12}\rightarrow\mathrm{x}=\mathrm{12}−\mathrm{y}…\left(\ast\right)…

3-49-3-49-3-49-x-4-4-4-4-y-x-2-y-

Question Number 10206 by konen last updated on 30/Jan/17 $$\:^{\mathrm{3}} \sqrt{\mathrm{49}+^{\mathrm{3}} \sqrt{\mathrm{49}+^{\mathrm{3}} \sqrt{\mathrm{49}….}\:}}\:=\mathrm{x} \\ $$$$\sqrt{\mathrm{4}\sqrt{\mathrm{4}\sqrt{\mathrm{4}\sqrt{\mathrm{4}….}}}}\:=\mathrm{y} \\ $$$$\Rightarrow\mathrm{x}^{\mathrm{2}} −\mathrm{y}=? \\ $$ Answered by FilupSmith last updated…

3-x-2-3-8x-16-16-x-

Question Number 10197 by konen last updated on 29/Jan/17 $$\:^{\mathrm{3}} \sqrt{\mathrm{x}−\mathrm{2}}+^{\mathrm{3}} \sqrt{\mathrm{8x}−\mathrm{16}}=\mathrm{16}\Rightarrow\mathrm{x}=? \\ $$ Answered by sandy_suhendra last updated on 29/Jan/17 $$\sqrt[{\mathrm{3}}]{\mathrm{x}−\mathrm{2}}\:\:+\:\sqrt[{\mathrm{3}}]{\mathrm{8}\left(\mathrm{x}−\mathrm{2}\right)}\:=\:\mathrm{16} \\ $$$$\sqrt[{\mathrm{3}}]{\mathrm{x}−\mathrm{2}}\:+\:\mathrm{2}\sqrt[{\mathrm{3}}]{\mathrm{x}−\mathrm{2}}\:=\:\mathrm{16} \\…