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Category: Algebra

Turevlenebilir-bir-f-fonksiyonu-icin-f-x-y-f-x-f-y-2xy-ve-f-0-3-old-gore-f-2-czm-f-x-y-f-x-f-y-2xy-y-yi-sabit-kabul-edersek-f-x-y-f-x-2y-x-0-y-2-icn-f-2-f-0-2-2-f-2-3-4-1-

Question Number 11914 by ahmet last updated on 04/Apr/17 Turevlenebilirbirffonksiyonuicinf(x+y)=f(x)+f(y)+2xyvef(0)=3old.goref(2)=?czmf(x+y)=f(x)+f(y)+2xyyyisabitkabuledersekf(x+y)=f(x)+2yx=0,y=2icn$${f}'\left(\mathrm{2}\right)={f}'\left(\mathrm{0}\right)+\mathrm{2}.\mathrm{2} \

7cos-2-x-sin-2-x-3-2cos-2-x-sin-2-x-czm-7cos-2-x-1-cos-2-x-3-2cos-2-x-sin-2-x-6cos-2-x-2-2cos-2-x-1-cos-2-x-6cos-2-x-2-3cos-2-x-1-2-3cos-2-x-1-3cos-2-x-1-2-

Question Number 11901 by ahmet last updated on 04/Apr/17 7cos2x+sin2x32cos2xsin2x=?czm7cos2x+1cos2x32cos2xsin2x$$\frac{\mathrm{6}{cos}^{\mathrm{2}} {x}−\mathrm{2}}{\mathrm{2}{cos}^{\mathrm{2}} {x}−\left(\mathrm{1}−{cos}^{\mathrm{2}} {x}\right)}=\frac{\mathrm{6}{cos}^{\mathrm{2}}…