Question Number 76009 by Rio Michael last updated on 22/Dec/19 $${hiw}\:{do}\:{i}\:{solve} \\ $$$$\mathrm{2}^{{x}} \:=\:\mathrm{4}{x}? \\ $$ Answered by mr W last updated on 22/Dec/19 $$\mathrm{2}^{{x}}…
Question Number 10470 by ABD last updated on 13/Feb/17 Answered by sandy_suhendra last updated on 13/Feb/17 $$\mathrm{squares}\:\mathrm{1}×\mathrm{1}=\mathrm{8}^{\mathrm{2}} =\mathrm{64} \\ $$$$\mathrm{squares}\:\mathrm{2}×\mathrm{2}=\mathrm{7}^{\mathrm{2}} =\mathrm{49} \\ $$$$\mathrm{squares}\:\mathrm{3}×\mathrm{3}=\mathrm{6}^{\mathrm{2}} =\mathrm{36} \\…
Question Number 76003 by mivheal last updated on 22/Dec/19 $$\mathrm{22}+\mathrm{2} \\ $$ Answered by 21042004 last updated on 22/Dec/19 $$\mathrm{So}\:\mathrm{simple}: \\ $$$$\mathrm{22}+\mathrm{2}=\mathrm{24} \\ $$ Terms…
Question Number 10464 by ABD last updated on 10/Feb/17 Answered by mrW1 last updated on 10/Feb/17 $${for}\:\mid{x}−\mathrm{2}\mid=\mathrm{0}\:\Rightarrow{x}=\mathrm{2},\:\mid\mathrm{3}{x}−\mathrm{8}\mid=\mathrm{2} \\ $$$${for}\:\mid\mathrm{3}{x}−\mathrm{8}\mid=\mathrm{0}\:\Rightarrow{x}=\frac{\mathrm{8}}{\mathrm{3}},\:\mid{x}−\mathrm{2}\mid=\frac{\mathrm{2}}{\mathrm{3}}<\mathrm{2} \\ $$$${A}_{{max}} =\frac{\mathrm{24}}{\frac{\mathrm{2}}{\mathrm{3}}+\mathrm{0}}=\mathrm{36} \\ $$ Terms…
Question Number 10463 by ABD last updated on 10/Feb/17 $${x}\in{Z} \\ $$$$−\mathrm{1}\leqslant\mid{x}−\mathrm{3}\mid<\mathrm{5}\:\Rightarrow\Sigma=? \\ $$ Answered by mrW1 last updated on 10/Feb/17 $$−\mathrm{1}\leqslant\mid{x}−\mathrm{3}\mid\:{is}\:{always}\:{true} \\ $$$$ \\…
Question Number 10455 by amir last updated on 10/Feb/17 Commented by mrW1 last updated on 10/Feb/17 $${circle}\:{C}\mathrm{1}\:{with}\:{radius}\:{r}_{\mathrm{1}} \:{and}\:{centre} \\ $$$${point}\:{M}_{\mathrm{1}} \left({r}_{\mathrm{1}} ,{h}_{\mathrm{1}} \right){with}\:{h}_{\mathrm{1}} ={r}_{\mathrm{1}} \:{has}\:{two}…
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Question Number 75985 by Ajao yinka last updated on 21/Dec/19 Answered by MJS last updated on 21/Dec/19 $$\mathrm{1}+\frac{\mathrm{1}}{{n}^{\mathrm{2}} }+\frac{\mathrm{1}}{\left({n}+\mathrm{1}\right)^{\mathrm{2}} }=\left(\frac{{n}^{\mathrm{2}} +{n}+\mathrm{1}}{{n}\left({n}+\mathrm{1}\right)}\right)^{\mathrm{2}} \\ $$$${S}_{{k}} =\underset{{n}=\mathrm{1}} {\overset{{k}}…
Question Number 141513 by mathdanisur last updated on 19/May/21 $$\mathrm{1}.\:\:\mathrm{27}^{\frac{\mathrm{1}}{{log}_{\mathrm{2}} \mathrm{3}}\:+\:{log}_{\mathrm{125}} \mathrm{0},\mathrm{2}} =? \\ $$$$\mathrm{2}.\:\:{if},\:\:\alpha\:=\:\frac{\pi}{\mathrm{12}} \\ $$$${find},\:\:{cos}^{\mathrm{2}} \alpha\:+\:\mathrm{2}{sin}\alpha{cos}\alpha\:−\:{sin}^{\mathrm{2}} \alpha=? \\ $$ Terms of Service Privacy…
Question Number 141489 by mathsuji last updated on 19/May/21 Answered by qaz last updated on 19/May/21 $${someone}\:{may}\:{be}\:{able}\:{to}\:{deal}\:{with}\: \\ $$$${this}\:\frac{\mathrm{2}}{\:\sqrt{\pi}}\int_{\mathrm{0}} ^{\pi/\mathrm{2}} \Sigma\frac{\mathrm{cos}\:^{\mathrm{2}{n}} {x}}{{n}^{\mathrm{2}} +\mathrm{1}}{dx}….. \\ $$…