Question Number 10012 by konen last updated on 20/Jan/17 $$\mathrm{x}−\mathrm{y}=\mathrm{4}\:\Rightarrow\frac{\mathrm{x}^{\mathrm{2}} −\mathrm{y}^{\mathrm{2}} +\mathrm{4x}−\mathrm{4y}}{\mathrm{2x}+\mathrm{2y}+\mathrm{8}}=? \\ $$ Answered by nume1114 last updated on 21/Jan/17 $$\:\:\:\:\frac{{x}^{\mathrm{2}} −{y}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{4}{y}}{\mathrm{2}{x}+\mathrm{2}{y}+\mathrm{8}} \\…
Question Number 141076 by ajfour last updated on 15/May/21 $${t}+{x}=\frac{{c}}{\mathrm{2}} \\ $$$$\:{t}^{\mathrm{2}} +{x}^{\mathrm{4}} =\frac{{c}^{\mathrm{2}} }{\mathrm{4}} \\ $$$${find}\:{x}\:{or}\:{t}\:.\:{Given}\:\mathrm{0}<{c}<\frac{\mathrm{2}}{\mathrm{3}\sqrt{\mathrm{3}}}\: \\ $$ Answered by Rasheed.Sindhi last updated on…
Question Number 9989 by konen last updated on 20/Jan/17 $$\mathrm{x}−\frac{\mathrm{1}}{\mathrm{x}}=\mathrm{3}\:\Rightarrow\mathrm{x}^{\mathrm{3}} −\mathrm{4x}^{\mathrm{2}} +\mathrm{2x}−\mathrm{3}=? \\ $$ Answered by mrW1 last updated on 20/Jan/17 $$\mathrm{x}−\frac{\mathrm{1}}{\mathrm{x}}=\mathrm{3} \\ $$$$\Rightarrow{x}^{\mathrm{2}} −\mathrm{3}{x}−\mathrm{1}=\mathrm{0}…
Question Number 9987 by konen last updated on 20/Jan/17 $$\mathrm{x}=\mathrm{199996} \\ $$$$\mathrm{x}^{\mathrm{2}} +\mathrm{8x}=\mathrm{a10}^{\mathrm{b}} −\mathrm{c} \\ $$$$\Rightarrow\:\mathrm{a}+\mathrm{b}+\mathrm{c}=? \\ $$ Answered by ridwan balatif last updated on…
Question Number 9977 by konen last updated on 20/Jan/17 Answered by sandy_suhendra last updated on 20/Jan/17 $$\mathrm{log}_{\mathrm{3}^{\mathrm{2}} } \:\left(\mathrm{x}−\mathrm{6}\right)^{\mathrm{2}} \:=\:\mathrm{log}_{\mathrm{9}} \:\left(\mathrm{x}−\mathrm{8}\right) \\ $$$$\left(\mathrm{x}−\mathrm{6}\right)^{\mathrm{2}} =\mathrm{x}−\mathrm{8} \\…
Question Number 9976 by konen last updated on 20/Jan/17 $$\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} +\mathrm{4a}+\mathrm{6b}+\mathrm{13}=\mathrm{0}\:\: \\ $$$$\Rightarrow\:\mathrm{a}+\mathrm{b}=? \\ $$ Answered by prakash jain last updated on 20/Jan/17 $${a}^{\mathrm{2}}…
Question Number 141050 by mathsuji last updated on 15/May/21 Answered by MJS_new last updated on 15/May/21 $$\sqrt{{p}}+\sqrt{{q}}=\sqrt{{r}} \\ $$$${p}+{q}+\mathrm{2}\sqrt{{pq}}={r} \\ $$$$\mathrm{2}\sqrt{{pq}}={r}−\left({p}+{q}\right) \\ $$$$\mathrm{4}{pq}=\left({r}−\left({p}+{q}\right)\right)^{\mathrm{2}} \\ $$$${p}^{\mathrm{2}}…
Question Number 9962 by konen last updated on 19/Jan/17 $$\mathrm{a},\mathrm{b}\:\in\mathrm{Z}^{+} \\ $$$$\mathrm{b}^{\mathrm{2}} −\mathrm{a}^{\mathrm{2}} =\mathrm{2b}+\mathrm{7a}+\mathrm{4} \\ $$$$\Rightarrow\:\mathrm{a}+\mathrm{b}=? \\ $$ Commented by prakash jain last updated on…
Question Number 9959 by konen last updated on 19/Jan/17 $$\mid\mathrm{x}^{\mathrm{2}} −\mathrm{25}\mid=\mathrm{4}\mid\mathrm{x}−\mathrm{5}\mid\:\:\:\Rightarrow\Sigma\mathrm{x}=? \\ $$ Answered by mrW1 last updated on 19/Jan/17 $$\mid\left({x}−\mathrm{5}\right)\left({x}+\mathrm{5}\right)\mid=\mathrm{4}\mid{x}−\mathrm{5}\mid \\ $$$${x}=\mathrm{5}\:{or} \\ $$$$\mid{x}+\mathrm{5}\mid=\mathrm{4}\:{or}…
Question Number 141030 by iloveisrael last updated on 15/May/21 $$\:\:\:\:\:\:\:\:\:\:\rightarrow\langle\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{\mathrm{9}{n}^{\mathrm{2}} +\mathrm{3}{n}}\:=?\:\rangle\leftarrow \\ $$ Commented by EDWIN88 last updated on 15/May/21 $$\:=\:\mathrm{1}−\mathrm{ln}\:\sqrt{\mathrm{3}}\:−\frac{\pi}{\mathrm{6}\sqrt{\mathrm{3}}} \\ $$$$\:\mathrm{S}=\frac{\mathrm{1}}{\mathrm{3}}\:\underset{\mathrm{n}=\mathrm{1}}…