Question Number 141658 by bramlexs22 last updated on 22/May/21 Answered by lyubita last updated on 22/May/21 $$−\:\frac{\mathrm{8}}{\mathrm{729}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 76122 by benjo last updated on 24/Dec/19 Answered by john santuy last updated on 24/Dec/19 $${i}\:{think}\:{this}\:{problem}\:{not}\:{difficult} \\ $$ Commented by $@ty@m123 last updated…
Question Number 141651 by mathsuji last updated on 21/May/21 Commented by MJS_new last updated on 22/May/21 $$\mathrm{it}'\mathrm{s}\:\mathrm{wrong}. \\ $$$${a}={b}={c}=\mathrm{0}\:\Rightarrow\:\mathrm{6}\sqrt{\mathrm{2}}>\mathrm{0} \\ $$$${a}={b}={c}=−\sqrt{\mathrm{3}}\:\Rightarrow\:\mathrm{6}\sqrt{\mathrm{2}}>−\mathrm{6}\sqrt{\mathrm{3}}>−\mathrm{9}\sqrt{\mathrm{3}} \\ $$ Commented by…
Question Number 141654 by mathsuji last updated on 21/May/21 $${Solve}\:{for}\:{real}\:{numbers} \\ $$$$\mathrm{5}\centerdot\left(\sqrt[{\mathrm{5}}]{\mathrm{1}−{z}}\:+\:\sqrt[{\mathrm{5}}]{\mathrm{1}+{z}}\:=\:\mathrm{2}+\mathrm{4}\centerdot\left(\sqrt[{\mathrm{4}}]{\mathrm{1}−{z}}\:+\:\sqrt[{\mathrm{4}}]{\mathrm{1}+{z}}\right)\right. \\ $$ Commented by MJS_new last updated on 22/May/21 $$\mathrm{only}\:\mathrm{solution}\:\mathrm{is}\:{z}=\mathrm{0} \\ $$ Commented…
Question Number 10572 by j.masanja06@gmail.com last updated on 18/Feb/17 $$\mathrm{factorise} \\ $$$$\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{1} \\ $$ Answered by sandy_suhendra last updated on 18/Feb/17 $$=\left(\mathrm{x}+\mathrm{1}\right)\left(\mathrm{x}^{\mathrm{2}} −\mathrm{x}+\mathrm{1}\right) \\…
Question Number 10570 by ABD last updated on 18/Feb/17 $${n}\left({A}\right)=\mathrm{12} \\ $$$${n}\left({B}\right)=\mathrm{10} \\ $$$$\Rightarrow{min}\left({n}\left({A}−{B}−{B}^{'} \right)\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10564 by FilupS last updated on 18/Feb/17 $$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\underset{\epsilon\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{−\mathrm{1}+{x}^{\epsilon} }{\epsilon}\:=\:\mathrm{ln}\left({x}\right) \\ $$ Answered by lee last updated on 21/Feb/17 $$ \\…
Question Number 10563 by FilupS last updated on 18/Feb/17 $$\mathrm{can}\:\mathrm{someone}\:\mathrm{explain}\:\mathrm{to}\:\mathrm{me} \\ $$$$\mathrm{big}\:\mathrm{K}\:\mathrm{notation}?\:\left(\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{know}\:\mathrm{the}\:\mathrm{name}\right) \\ $$$$\mathrm{It}\:\mathrm{is}\:\mathrm{related}\:\mathrm{to}\:\mathrm{continuous}\:\mathrm{fractions}. \\ $$$$\mathrm{e}.\mathrm{g}.\:\:\:{x}={b}_{\mathrm{0}} +\underset{{i}=\mathrm{1}} {\overset{\infty} {\boldsymbol{\mathrm{K}}}}\frac{{a}_{{i}} }{{b}_{{i}} } \\ $$$$\: \\ $$$${e}^{{x}}…
Question Number 141628 by mathdanisur last updated on 21/May/21 Commented by MJS_new last updated on 21/May/21 $$\mathrm{what}\:\mathrm{are}\:{r},\:{r}_{{a}} ,\:…? \\ $$$${rr}_{{a}} \:\mathrm{means}\:{r}×{r}_{{a}} ? \\ $$ Commented…
Question Number 10542 by FilupS last updated on 17/Feb/17 $$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\mathrm{tan}\left(\mathrm{sec}^{−\mathrm{1}} \left(\sqrt{\mathrm{tan}\left(\theta\right)}\right)\right)=\sqrt{\mathrm{tan}\left(\theta\right)}\sqrt{\mathrm{1}−\mathrm{cot}\left(\theta\right)} \\ $$ Answered by mrW1 last updated on 17/Feb/17 $${let}\:\alpha=\mathrm{sec}^{−\mathrm{1}} \left(\sqrt{\mathrm{tan}\:\left(\theta\right)}\right) \\…