Question Number 9029 by rzagung last updated on 15/Nov/16 $$ \\ $$$$\mathrm{2}{cos}\left({x}+\Pi/\mathrm{4}\right)={cos}\left({x}−\Pi/\mathrm{4}\right) \\ $$ Answered by Rasheed Soomro last updated on 15/Nov/16 $$\mathrm{2}{cos}\left({x}+\pi/\mathrm{4}\right)={cos}\left({x}−\pi/\mathrm{4}\right) \\ $$$$\mathrm{cos}\left(\mathrm{x}+\pi/\mathrm{4}\right)+\mathrm{cos}\left(\mathrm{x}+\pi/\mathrm{4}\right)−\mathrm{cos}\left(\mathrm{x}−\pi/\mathrm{4}\right)=\mathrm{0}…
Question Number 9020 by tawakalitu last updated on 14/Nov/16 Commented by RasheedSoomro last updated on 20/Nov/16 $$\mathrm{By}\:\left[\frac{\mathrm{ax}^{\mathrm{2}} +\mathrm{bx}+\mathrm{c}}{\mathrm{2x}+\mathrm{b}}\right]\:\mathrm{do}\:\mathrm{you}\:\mathrm{mean}\:\mathrm{bracket}\:\mathrm{function}? \\ $$ Answered by Rasheed Soomro last…
Question Number 74554 by shubham90412@gmail.com last updated on 26/Nov/19 $$\boldsymbol{{Find}}\:\boldsymbol{{the}}\:\boldsymbol{{superimum}}\:\boldsymbol{{of}}\:\boldsymbol{{the}}\:\boldsymbol{{set}}\:\left\{\frac{\boldsymbol{{n}}^{\mathrm{2}} }{\mathrm{2}^{\boldsymbol{{n}}} }\right\} \\ $$ Answered by MJS last updated on 26/Nov/19 $$\mathrm{trying} \\ $$$${S}=\left\{\mathrm{0},\:\frac{\mathrm{1}}{\mathrm{2}},\:\mathrm{1},\:\frac{\mathrm{9}}{\mathrm{8}},\:\mathrm{1},\:\frac{\mathrm{25}}{\mathrm{32}},\:\frac{\mathrm{9}}{\mathrm{16}},\:…\right\} \\…
Question Number 140090 by mathdanisur last updated on 04/May/21 $$\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{1}} }+\frac{\mathrm{3}}{\mathrm{2}^{\mathrm{3}} }+\frac{\mathrm{5}}{\mathrm{2}^{\mathrm{5}} }+\frac{\mathrm{7}}{\mathrm{2}^{\mathrm{7}} }+..=? \\ $$ Answered by qaz last updated on 04/May/21 $${S}=\underset{{n}=\mathrm{0}} {\overset{\infty}…
Question Number 9015 by tawakalitu last updated on 13/Nov/16 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9009 by tawakalitu last updated on 13/Nov/16 $$\mathrm{If}\::\:\:\mathrm{x}\:=\:\frac{\mathrm{3y}\:+\:\mathrm{6z}}{\mathrm{7z}\:−\:\mathrm{2}}\:\:\mathrm{and}\:\:\mathrm{y}\:=\:\frac{\frac{\mathrm{1}}{\mathrm{2}}\mathrm{z}\:+\:\mathrm{6y}}{\frac{\mathrm{3}}{\mathrm{2}}\mathrm{z}\:+\:\mathrm{6y}} \\ $$$$\mathrm{Find}\::\:\:\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{y}^{\mathrm{3}} \\ $$ Answered by Rasheed Soomro last updated on 14/Nov/16 $$\mathrm{If}\::\:\:\mathrm{x}\:=\:\frac{\mathrm{3y}\:+\:\mathrm{6z}}{\mathrm{7z}\:−\:\mathrm{2}}\:\:\mathrm{and}\:\:\mathrm{y}\:=\:\frac{\frac{\mathrm{1}}{\mathrm{2}}\mathrm{z}\:+\:\mathrm{6y}}{\frac{\mathrm{3}}{\mathrm{2}}\mathrm{z}\:+\:\mathrm{6y}}=\frac{\mathrm{z}+\mathrm{12y}}{\mathrm{3z}+\mathrm{12y}} \\…
Question Number 9004 by mrW last updated on 12/Nov/16 $$\mathrm{prove} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\centerdot\frac{\mathrm{3}}{\mathrm{4}}\centerdot\frac{\mathrm{5}}{\mathrm{6}}\centerdot\centerdot\centerdot\centerdot\centerdot\frac{\mathrm{2n}−\mathrm{1}}{\mathrm{2n}}\leqslant\frac{\mathrm{1}}{\:\sqrt{\mathrm{3n}+\mathrm{1}}} \\ $$ Answered by mrW last updated on 15/Nov/16 $$\mathrm{Using}\:\mathrm{mathematical}\:\mathrm{induction} \\ $$$$\mathrm{prove}\:{P}\left(\mathrm{n}\right)=\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}}…
Question Number 8998 by tawakalitu last updated on 11/Nov/16 $$\mathrm{If}\:\:\mathrm{2}^{\mathrm{x}} \:=\:\mathrm{3}^{\mathrm{y}} \:=\:\mathrm{6}^{−\mathrm{z}} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\::\:\:\frac{\mathrm{1}}{\mathrm{x}}\:+\:\frac{\mathrm{1}}{\mathrm{y}}\:+\:\frac{\mathrm{1}}{\mathrm{z}} \\ $$ Answered by Rasheed Soomro last updated on 12/Nov/16 $$\mathrm{If}\:\:\mathrm{2}^{\mathrm{x}}…
Question Number 8985 by j.masanja06@gmail.com last updated on 10/Nov/16 $$\mathrm{solve}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x} \\ $$$$\mathrm{log}_{\mathrm{x}} \mathrm{3}=\mathrm{81} \\ $$ Answered by Rasheed Soomro last updated on 10/Nov/16 $$\mathrm{log}_{\mathrm{x}} \mathrm{3}=\mathrm{81}…
Question Number 140042 by denzel last updated on 03/May/21 Answered by MJS_new last updated on 03/May/21 $$\mathrm{254}=\frac{\mathrm{1269}}{\mathrm{4}+\mathrm{46e}^{−.\mathrm{3}{t}} } \\ $$$$\mathrm{just}\:\mathrm{transform}\:\mathrm{it} \\ $$$$\mathrm{e}^{−.\mathrm{3}{t}} =\frac{\frac{\mathrm{1269}}{\mathrm{254}}−\mathrm{4}}{\mathrm{46}}=\frac{\mathrm{11}}{\mathrm{508}} \\ $$$$−.\mathrm{3}{t}=\mathrm{ln}\:\frac{\mathrm{11}}{\mathrm{508}}…