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Category: Algebra

x-and-y-are-reals-or-complex-let-put-x-0-1-x-1-x-x-2-x-x-1-x-n-x-x-1-x-2-x-n-1-prove-that-x-y-n-k-0-n-C-n-k-x-n-k-y-k-

Question Number 73027 by mathmax by abdo last updated on 05/Nov/19 $${x}\:{and}\:{y}\:{are}\:{reals}\left({or}\:{complex}\right)\:{let}\:{put}\:{x}^{\left(\mathrm{0}\right)} =\mathrm{1}\:,{x}^{\left(\mathrm{1}\right)} ={x} \\ $$$${x}^{\left(\mathrm{2}\right)} ={x}\left({x}−\mathrm{1}\right)…..{x}^{\left({n}\right)} ={x}\left({x}−\mathrm{1}\right)\left({x}−\mathrm{2}\right)…\left({x}−{n}+\mathrm{1}\right){prove}\:{that} \\ $$$$\left({x}+{y}\right)^{\left({n}\right)} =\sum_{{k}=\mathrm{0}} ^{{n}} \:{C}_{{n}} ^{{k}} \:\:{x}^{\left({n}−{k}\right)}…

Find-the-value-of-x-3-x-3-18-if-x-x-3-1-

Question Number 7478 by Yozzia last updated on 31/Aug/16 $${Find}\:{the}\:{value}\:{of}\:\:{x}^{\mathrm{3}} \left({x}^{\mathrm{3}} −\mathrm{18}\right)\:\:{if}\:\:{x}\left({x}−\mathrm{3}\right)=−\mathrm{1}. \\ $$ Answered by Rasheed Soomro last updated on 31/Aug/16 $$\:\:\:{x}^{\mathrm{3}} \left({x}^{\mathrm{3}} −\mathrm{18}\right)\:\:{if}\:\:{x}\left({x}−\mathrm{3}\right)=−\mathrm{1}…

Show-why-lim-x-x-x-0-

Question Number 7472 by FilupSmith last updated on 31/Aug/16 $$\mathrm{Show}\:\mathrm{why}: \\ $$$$\underset{{x}\rightarrow−\infty} {\mathrm{lim}}\:{x}^{{x}} \:=\:\mathrm{0} \\ $$ Commented by FilupSmith last updated on 31/Aug/16 $$=\underset{{x}\rightarrow−\infty} {\mathrm{lim}}\:{e}^{{x}\mathrm{ln}\left({x}\right)}…

Question-138546

Question Number 138546 by mnjuly1970 last updated on 14/Apr/21 Answered by ajfour last updated on 14/Apr/21 $$\left({i}\right)\:\:{a}^{\mathrm{3}} ={p},\:{b}^{\mathrm{3}} ={q},\:{c}^{\mathrm{3}} ={r} \\ $$$$\:{a}+{b}+{c}=\:\boldsymbol{{v}}\:=\sqrt[{\mathrm{3}}]{{p}}+\sqrt[{\mathrm{3}}]{{q}}+\sqrt[{\mathrm{3}}]{{r}} \\ $$$$\left({a}+{b}+{c}\right)^{\mathrm{3}} ={v}^{\mathrm{3}}…

x-y-7-x-y-11-faind-x-and-y-

Question Number 138532 by mathlove last updated on 14/Apr/21 $${x}+\sqrt{{y}}=\mathrm{7} \\ $$$$\sqrt{{x}}+{y}=\mathrm{11} \\ $$$${faind}\:\:{x}=?\:\:{and}\:\:{y}=? \\ $$ Answered by henderson last updated on 14/Apr/21 $$\begin{cases}{{x}\:+\:\sqrt{{y}\:}\:=\:\mathrm{7}}\\{\sqrt{{x}}\:+\:{y}\:=\:\mathrm{11}}\end{cases}\:\Leftrightarrow\:\begin{cases}{{x}\:=\:\mathrm{7}\:−\:\sqrt{{y}}}\\{\sqrt{\mathrm{7}−\sqrt{{y}}}\:+\:{y}\:=\:\mathrm{11}}\end{cases}\:\Leftrightarrow\:\begin{cases}{{x}\:=\:\mathrm{7}−\sqrt{{y}}}\\{\sqrt{\mathrm{7}−\sqrt{{y}}}\:=\:\mathrm{11}−{y}}\end{cases}\Leftrightarrow \\…