Category: Algebra

Question Number 141098 by ajfour last updated on 15/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 10012 by konen last updated on 20/Jan/17 $$\mathrm{x}-\mathrm{y}=4\Rightarrow \frac{{\mathrm{x}}^2-{\mathrm{y}}^2+4\mathrm{x}-4\mathrm{y}}{2\mathrm{x}+2\mathrm{y}+8}=?$$ Answered by nume1114 last updated on 21/Jan/17 $$\:\:\:\:\frac{{x}^{\mathrm{2}} −{y}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{4}{y}}{\mathrm{2}{x}+\mathrm{2}{y}+\mathrm{8}} \…

Question Number 9989 by konen last updated on 20/Jan/17 $$\mathrm{x}-\frac{1}{\mathrm{x}}=3\Rightarrow {\mathrm{x}}^3-{4\mathrm{x}}^2+2\mathrm{x}-3=?$$ Answered by mrW1 last updated on 20/Jan/17 $$\mathrm{x}-\frac{1}{\mathrm{x}}=3$$$$\Rightarrow{x}^{\mathrm{2}} −\mathrm{3}{x}−\mathrm{1}=\mathrm{0}…

Question Number 9977 by konen last updated on 20/Jan/17 Answered by sandy_suhendra last updated on 20/Jan/17 $${\log }_{3^2}{(\mathrm{x}-6)}^2={\log }_9(\mathrm{x}-8)$$$$\left(\mathrm{x}−\mathrm{6}\right)^{\mathrm{2}} =\mathrm{x}−\mathrm{8} \…

Question Number 141050 by mathsuji last updated on 15/May/21 Answered by MJS_new last updated on 15/May/21 $$\sqrt{p}+\sqrt{q}=\sqrt{r}$$$$p+q+2\sqrt{pq}=r$$$$2\sqrt{pq}=r-(p+q)$$$$4pq={(r-(p+q))}^2$$$${p}^{\mathrm{2}}…