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Category: Algebra

x-2-x-x-x-0-x-

Question Number 7000 by FilupSmith last updated on 05/Aug/16 $${x}^{\mathrm{2}} ={x}+\sqrt{{x}} \\ $$$${x}=\mathrm{0}\:\vee\:{x}=?? \\ $$ Commented by Yozzii last updated on 05/Aug/16 $${Let}\:{u}=\sqrt{{x}}\Rightarrow{u}^{\mathrm{2}} ={x}\Rightarrow{u}^{\mathrm{4}} ={x}^{\mathrm{2}}…