Question Number 142604 by Engr_Jidda last updated on 02/Jun/21 Answered by mr W last updated on 02/Jun/21 $${a}=\mathrm{14} \\ $$$${r}_{\mathrm{1}} ={b}=\mathrm{10}.\mathrm{5} \\ $$$${r}_{\mathrm{2}} =\sqrt{{a}^{\mathrm{2}} +{b}^{\mathrm{2}}…
Question Number 77067 by Boyka last updated on 03/Jan/20 Commented by Boyka last updated on 03/Jan/20 $$\left[\mathrm{x}\right]−\mathrm{whole}\:\mathrm{part}\:\: \\ $$$$\boldsymbol{\mathrm{x}}=\left[\boldsymbol{\mathrm{x}}\right]+\left\{\boldsymbol{\mathrm{x}}\right\} \\ $$ Commented by mr W…
Question Number 77066 by Boyka last updated on 03/Jan/20 Commented by mr W last updated on 03/Jan/20 $${the}\:{question}\:{is}\:{non}−{sense}! \\ $$$${or}\:{can}\:{you}\:{even} \\ $$$$“{find}\:{the}\:{sum}\:{of}\:\mathrm{2}\:{numbers}?'' \\ $$ Commented…
Question Number 142607 by mathdanisur last updated on 02/Jun/21 Answered by mr W last updated on 03/Jun/21 $${A}_{{max}} =\mathrm{10}^{\mathrm{3}} +\mathrm{5}^{\mathrm{3}} +\mathrm{10}×\mathrm{5}=\mathrm{1175} \\ $$$${A}_{{min}} =−\mathrm{10}^{\mathrm{3}} −\mathrm{5}^{\mathrm{3}}…
Question Number 77046 by ajfour last updated on 02/Jan/20 $${x}={R}^{\mathrm{2}} \sqrt{\mathrm{1}−\frac{{t}^{\mathrm{2}} }{{R}^{\mathrm{2}} }}\: \\ $$ Answered by ajfour last updated on 02/Jan/20 Commented by necxxx…
Question Number 11515 by @ANTARES_VY last updated on 27/Mar/17 $$\sqrt[{\mathrm{5}}]{\frac{\mathrm{4}+\boldsymbol{\mathrm{x}}}{\boldsymbol{\mathrm{x}}}}−\sqrt[{\mathrm{5}}]{\frac{\mathrm{4}−\mathrm{6}\boldsymbol{\mathrm{x}}}{\boldsymbol{\mathrm{x}}}}=\mathrm{1}. \\ $$$$\boldsymbol{\mathrm{x}}_{\mathrm{1}} +\boldsymbol{\mathrm{x}}_{\mathrm{2}} =? \\ $$ Answered by ajfour last updated on 27/Mar/17 $$\mathrm{x}=\frac{\mathrm{4}}{\mathrm{15}} \\…
Question Number 142577 by loveineq last updated on 02/Jun/21 $$\mathrm{Let}\:{a},{b},{c}\:\geqslant\:\mathrm{0}\:\mathrm{and}\:{a}+{b}+{c}\:=\:\mathrm{1}.\mathrm{Prove}\:\mathrm{that}\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{\mathrm{1}}{{a}^{\mathrm{2}} +\mathrm{1}}+\frac{\mathrm{1}}{{b}^{\mathrm{2}} +\mathrm{1}}+\frac{\mathrm{1}}{{c}^{\mathrm{2}} +\mathrm{1}}\:\geqslant\:\frac{\mathrm{5}}{\mathrm{2}} \\ $$$$ \\ $$ Answered by ajfour last updated on…
Question Number 142582 by mathdanisur last updated on 02/Jun/21 $$\boldsymbol{{z}}^{\mathrm{4}} \:+\:\mathrm{12}\boldsymbol{{z}}\:+\:\mathrm{3}\:=\:\mathrm{0}\:\left(\boldsymbol{{z}}=?\right) \\ $$ Answered by ajfour last updated on 02/Jun/21 $$\left({z}^{\mathrm{2}} +{pz}+{q}\right)\left({z}^{\mathrm{2}} −{pz}+\frac{\mathrm{3}}{{q}}\right)=\mathrm{0} \\ $$$$\Rightarrow…
Question Number 11500 by @ANTARES_VY last updated on 27/Mar/17 $$\left(\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{x}}−\mathrm{4}\right)\left(\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{x}}+\mathrm{4}\right)=\mathrm{9} \\ $$$$\boldsymbol{\mathrm{find}}\:\:\boldsymbol{\mathrm{the}}\:\:\boldsymbol{\mathrm{equation}}\:\:\boldsymbol{\mathrm{has}}\:\:\boldsymbol{\mathrm{multiple}}\:\:\boldsymbol{\mathrm{roots}}. \\ $$ Answered by ridwan balatif last updated on 27/Mar/17 $$\left(\left(\mathrm{x}^{\mathrm{2}}…
Question Number 11501 by @ANTARES_VY last updated on 27/Mar/17 $$\left(\mathrm{4}\boldsymbol{\mathrm{x}}^{\mathrm{2}} −\mathrm{7}\boldsymbol{\mathrm{x}}−\mathrm{5}\right)\left(\mathrm{5}\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{13}\boldsymbol{\mathrm{x}}+\mathrm{3}\right)\left(\mathrm{3}\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{x}}^{\mathrm{2}} −\mathrm{8}\right)=\mathrm{0}. \\ $$$$\boldsymbol{\mathrm{find}}\:\:\boldsymbol{\mathrm{all}}\:\:\boldsymbol{\mathrm{the}}\:\:\boldsymbol{\mathrm{multiples}}\:\:\boldsymbol{\mathrm{of}}\:\:\boldsymbol{\mathrm{the}} \\ $$$$\boldsymbol{\mathrm{real}}\:\:\boldsymbol{\mathrm{roots}}\:\:\boldsymbol{\mathrm{of}}\:\:\boldsymbol{\mathrm{the}}\:\:\boldsymbol{\mathrm{equation}}. \\ $$ Commented by mrW1 last updated on…