Category: Algebra

Question Number 140669 by john_santu last updated on 11/May/21 $$x^3+1=2\sqrt[3]{2x-1}$$ Answered by bemath last updated on 11/May/21 $$\frac{{\mathrm{x}}^3+1}{2}=\sqrt[3]{2\mathrm{x}-1}$$$$\:\mathrm{set}\:\mathrm{g}\left(\mathrm{x}\right)=\:\sqrt[{\mathrm{3}\:}]{\mathrm{2x}−\mathrm{1}}\:\Rightarrow\frac{\mathrm{x}^{\mathrm{3}} +\mathrm{1}}{\mathrm{2}}\:=\:\mathrm{g}^{−\mathrm{1}}…

Question Number 9576 by j.masanja06@gmail.com last updated on 18/Dec/16 $$\mathrm{show}\mathrm{that}\mathrm{x}\mathrm{is}\mathrm{small}\mathrm{enough}\mathrm{for}\mathrm{its}\mathrm{cube}\mathrm{and}\mathrm{higher}\mathrm{power}\mathrm{to}\mathrm{be}\mathrm{neghected}$$$$\sqrt{\frac{1-\mathrm{x}}{1+\mathrm{x}}}=1-\mathrm{x}+\frac{1}{2}{\mathrm{x}}^2.$$$$\mathrm{by}\mathrm{putting}=\frac{1}{8},\mathrm{show}\mathrm{that}\sqrt{7}\approx 2\frac{83}{128}.$$ Commented by prakash jain last updated on 20/Dec/16…

Question Number 75110 by peter frank last updated on 07/Dec/19 Answered by mind is power last updated on 08/Dec/19 $$\mathrm{ax}+\mathrm{by}+\mathrm{c}=0$$$$\mathrm{x}=0\Rightarrow {\mathrm{y}}_0=-\frac{\mathrm{c}}{\mathrm{b}}\dots ..\mathrm{b}\ne 0$$$$\mathrm{y}=\mathrm{0}\Rightarrow\mathrm{x}_{\mathrm{0}}…

Question Number 140625 by bemath last updated on 10/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 9543 by Joel575 last updated on 14/Dec/16 $${(2-\sqrt{3})}^x+(7-4\sqrt{3}){(2+\sqrt{3})}^x=4(2-\sqrt{3}),x\ne 0$$$$\mathrm{What}\mathrm{is}\mathrm{the}\mathrm{value}\mathrm{of}x?$$ Answered by mrW last updated on 14/Dec/16 $$\mathrm{u}=\left(\mathrm{2}−\sqrt{\mathrm{3}}\right)^{\mathrm{x}} \…