Category: Algebra

Question Number 140346 by mathsuji last updated on 06/May/21 $$if,x>4;5!\cdot x!=z!;find:x+z=?$$ Answered by hknkrc46 last updated on 06/May/21 $$5!=\frac{\mathit{z}!}{\mathit{x}!}\Rightarrow \{\begin{array}{l}\mathit{x}=5!-1\Rightarrow \mathit{z}=120\\ \mathit{x}+\mathit{z}=119+120=239\end{array}$$ Commented by mathsuji…

Question Number 74786 by chess1 last updated on 30/Nov/19 Commented by abdomathmax last updated on 30/Nov/19 $$S=\sum _{k=1}^{2019}k{\left(\frac{1}{2020}\right)}^k=w\left(\frac{1}{2020}\right)with$$$${w}\left({x}\right)=\sum_{{k}=\mathrm{1}} ^{\mathrm{2019}} \:{kx}^{{k}} \:\:\:{we}\:{have}\:{for}\:{x}\neq\mathrm{1}…

Question Number 9229 by tawakalitu last updated on 24/Nov/16 $$2^{3\mathrm{x}+1}-3.2^{2\mathrm{x}}+2^{\mathrm{x}+1}=2\mathrm{x}$$$$\mathrm{Find}\mathrm{x}$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 140291 by ajfour last updated on 06/May/21 Commented by ajfour last updated on 06/May/21 $$S=a+\frac{a}{2}+\frac{a}{4}+\frac{a}{8}+\dots \dots .$$$$=2a.$$ Commented by Dwaipayan Shikari…

Question Number 140273 by liberty last updated on 06/May/21 $$2\sqrt{\mathrm{x}-1}+5\mathrm{x}=\sqrt{({\mathrm{x}}^2+4)(\mathrm{x}+24)}$$ Answered by MJS_new last updated on 06/May/21 $$x=5$$$$\mathrm{I}\:\mathrm{saw}\:\mathrm{that}\:\left(\mathrm{5}^{\mathrm{2}} +\mathrm{4}\right)\left(\mathrm{5}+\mathrm{24}\right)=\mathrm{29}^{\mathrm{2}} \…