Question Number 76586 by Master last updated on 28/Dec/19 Commented by Master last updated on 28/Dec/19 $$\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{please}} \\ $$ Commented by Tony Lin last updated…
Question Number 76587 by Master last updated on 28/Dec/19 Commented by Master last updated on 28/Dec/19 $$\mathrm{sir}\:\mathrm{mind}\:\mathrm{is}\:\mathrm{power} \\ $$ Commented by Master last updated on…
Question Number 11049 by Joel576 last updated on 09/Mar/17 $$\mathrm{If}\:\:{n}^{\mathrm{2}} \:+\:\mathrm{3}{n}\:+\:\mathrm{1}\:\:\mathrm{is}\:\mathrm{divisible}\:\mathrm{by}\:\mathrm{3}{n}\:+\:\mathrm{10} \\ $$$$\mathrm{Find}\:\mathrm{out}\:\mathrm{all}\:\mathrm{possible}\:\mathrm{solution}\:\mathrm{for}\:{n}\: \\ $$ Commented by ajfour last updated on 09/Mar/17 $${cant}\:{figure}\:{any}\:{other}\:{than}\:\pm\mathrm{3}\:. \\ $$…
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Question Number 11023 by ABD last updated on 07/Mar/17 $$\left({x}^{\mathrm{3}} +\mathrm{6}\right)×{P}\left({x}\right)+\mathrm{6}{x}={ax}^{\mathrm{3}} +\mathrm{2}{ax}+{b}+\mathrm{3} \\ $$$$\Rightarrow{b}=? \\ $$ Answered by mrW1 last updated on 07/Mar/17 $$\left({x}^{\mathrm{3}} +\mathrm{6}\right)×{P}\left({x}\right)+\mathrm{6}{x}={ax}^{\mathrm{3}}…
Question Number 11024 by ABD last updated on 07/Mar/17 $${P}\left({x}+\mathrm{1}\right)×{P}\left({x}−\mathrm{1}\right)=\mathrm{4}{x}^{\mathrm{2}} +\mathrm{8}{x}+{a}−\mathrm{5} \\ $$$${a}=? \\ $$ Answered by ajfour last updated on 07/Mar/17 $${let}\:{P}\left({x}\right)\:=\:{bx}+{c} \\ $$$${Then}\:{P}\left({x}+\mathrm{1}\right)×{P}\left({x}−\mathrm{1}\right)…
Question Number 142085 by Rexzie last updated on 30/May/21 $${Proof}\:{that}\:\mathrm{1}+\mathrm{3}{n}<{n}^{\mathrm{2}} \:{for}\:{every}\:{positive}\:{integer}\:{n}\geqslant\mathrm{4} \\ $$ Answered by MJS_new last updated on 26/May/21 $$\mathrm{it}'\mathrm{s}\:\mathrm{wrong}\:\mathrm{for}\:\frac{\mathrm{3}−\sqrt{\mathrm{13}}}{\mathrm{2}}\leqslant{n}\leqslant\frac{\mathrm{3}+\sqrt{\mathrm{13}}}{\mathrm{2}} \\ $$ Answered by…
Question Number 11009 by Joel576 last updated on 06/Mar/17 $$\mathrm{If}\:\:{x}^{\mathrm{3}} \:=\:{y}^{\mathrm{3}} \\ $$$$\mathrm{Is}\:\mathrm{it}\:\mathrm{always}\:\mathrm{true}\:\mathrm{that}\:{x}\:=\:{y}\:? \\ $$ Answered by mrW1 last updated on 06/Mar/17 $${yes}.\:{function}\:{f}\left({x}\right)={x}^{\mathrm{3}} \:{is}\:{unique}. \\…
Question Number 142061 by iloveisrael last updated on 26/May/21 $$\sqrt{\mathrm{5}{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{2}+\mathrm{2}{xy}−\mathrm{4}{xz}+\mathrm{10}}\:+ \\ $$$$\mid\mathrm{2}{x}−{y}−\mathrm{13}\mid\:=\:\mathrm{3}\: \\ $$ Commented by MJS_new last updated on 26/May/21 $$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{question}?…
Question Number 76531 by benjo 1/2 santuyy last updated on 28/Dec/19 $${what}\:{is}\:{a}\:{and}\:{b}\:{such}\:{that}\:{a}+{b}\:=\:{a}×{b}\: \\ $$$${and}\:{a}+{b}\:={a}/{b}\:? \\ $$ Commented by MJS last updated on 28/Dec/19 $$\left(\mathrm{1}\right)\:{a}+{b}={ab}\:\Rightarrow\:{a}=\frac{{b}}{{b}−\mathrm{1}}\:\Rightarrow\:{b}\neq\mathrm{1} \\…