Question Number 6105 by sanusihammed last updated on 13/Jun/16 $${Solve}\:{the}\:{system}\:{of}\:{equation}\: \\ $$$$ \\ $$$${x}^{\mathrm{2}} \:−\:{yz}\:=\:−\:\mathrm{52}\:\:\:…………..\:\left({i}\right) \\ $$$${y}^{\mathrm{2}} \:−\:{xz}\:=\:−\:\mathrm{6}\:…………….\:\left({ii}\right) \\ $$$${z}^{\mathrm{2}} \:−\:{xy}\:=\:\mathrm{86}\:\:\:…………..\:\left({iii}\right) \\ $$ Commented by…
Question Number 71633 by mind is power last updated on 18/Oct/19 $$\mathrm{let}\:\mathrm{a},\mathrm{b},\mathrm{c}\:\in\mathrm{IR}_{+} \\ $$$$\mathrm{show}\:\mathrm{that}\:\left(\mathrm{a}+\mathrm{b}\right)\left(\mathrm{a}+\mathrm{c}\right)\geqslant\mathrm{2}\sqrt{\mathrm{abc}\left(\mathrm{a}+\mathrm{b}+\mathrm{c}\right)} \\ $$$$ \\ $$ Answered by MJS last updated on 18/Oct/19…
Question Number 137117 by MathZa last updated on 29/Mar/21 Answered by mathmax by abdo last updated on 30/Mar/21 $$\mathrm{is}\:\mathrm{z}+\mathrm{i}\sqrt{\mathrm{2}}=\mathrm{0}? \\ $$$$\mathrm{z}+\mathrm{i}\sqrt{\mathrm{2}}=\frac{\mathrm{2}−\sqrt{\mathrm{2}}+\sqrt{\mathrm{2}}\mathrm{i}}{\mathrm{1}+\sqrt{\mathrm{2}}\mathrm{i}−\mathrm{i}}\:+\sqrt{\mathrm{2}}\mathrm{i}\:=\frac{\mathrm{2}−\sqrt{\mathrm{2}}+\sqrt{\mathrm{2}}\mathrm{i}+\sqrt{\mathrm{2}}\mathrm{i}−\mathrm{2}+\sqrt{\mathrm{2}}}{\mathrm{1}+\sqrt{\mathrm{2}}\mathrm{i}\:−\mathrm{i}} \\ $$$$=\frac{\mathrm{2}\sqrt{\mathrm{2}}\mathrm{i}}{\mathrm{1}+\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)\mathrm{i}}\:=\frac{\mathrm{2}\sqrt{\mathrm{2}}\mathrm{i}\left(\mathrm{1}−\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)\mathrm{i}\right.}{\mathrm{1}+\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)^{\mathrm{2}} }\:=\frac{\mathrm{2}\sqrt{\mathrm{2}}\mathrm{i}+\mathrm{2}\sqrt{\mathrm{2}}\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)}{\mathrm{1}+\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)^{\mathrm{2}} }…
Question Number 6045 by sanusihammed last updated on 10/Jun/16 $$\mathrm{4}^{{x}} \:=\:\mathrm{2}{x} \\ $$$$ \\ $$$${find}\:{x} \\ $$ Commented by Yozzii last updated on 10/Jun/16 $$\mathrm{4}^{{x}}…
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Question Number 6028 by FilupSmith last updated on 10/Jun/16 $$\mathrm{Can}\:\mathrm{you}\:\mathrm{please}\:\mathrm{show}\:\mathrm{me}\:\mathrm{how}\:\mathrm{to}\:\mathrm{solve}: \\ $$$${L}=\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\frac{{x}^{{n}} }{{n}!} \\ $$ Commented by Yozzii last updated on 10/Jun/16 $${Assume}\:{x}>\mathrm{0}. \\…
Question Number 6021 by sanusihammed last updated on 10/Jun/16 $$\mathrm{2}^{{x}} \:+\:\mathrm{2}{x}\:=\:\mathrm{8}\: \\ $$$$ \\ $$$${find}\:{the}\:{value}\:{of}\:{x} \\ $$ Commented by Yozzii last updated on 10/Jun/16 $${x}=\mathrm{2}…
Question Number 6009 by FilupSmith last updated on 09/Jun/16 $$\mathrm{Is}\:\mathrm{there}\:\mathrm{a}\:\mathrm{general}\:\mathrm{solution}\:\mathrm{to}: \\ $$$${S}=\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}{i}^{{k}} ,\:\:\:\:\:{k}\in\mathbb{Z},\:{k}\geqslant\mathrm{1} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 71533 by pete last updated on 16/Oct/19 $$\mathrm{Three}\:\mathrm{interior}\:\mathrm{angles}\:\mathrm{of}\:\mathrm{a}\:\mathrm{nonagon}\:\mathrm{are} \\ $$$$\mathrm{equal}\:\mathrm{and}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{other}\:\mathrm{six}\:\mathrm{is}\:\mathrm{1050}° \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{size}\:\mathrm{of}\:\mathrm{one}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equal}\:\mathrm{angles}. \\ $$ Answered by MJS last updated on 17/Oct/19 $$\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{interior}\:\mathrm{angles}\:\mathrm{is}\:\mathrm{1260}° \\…
Question Number 71534 by mr W last updated on 16/Oct/19 $${a}\:{number}\:{consists}\:{of}\:{digits}\:\mathrm{1}\:{and}\:\mathrm{2}. \\ $$$${the}\:{sum}\:{of}\:{its}\:{digits}\:{is}\:\mathrm{2018}. \\ $$$${if}\:{the}\:{number}\:{is}\:{multiplied}\:{with}\:\mathrm{5},\: \\ $$$${the}\:{sum}\:{of}\:{the}\:{digits}\:{will}\:{be}\:\mathrm{10000}. \\ $$$${find}\:{how}\:{many}\:{digits}\:{this}\:{number} \\ $$$${has}. \\ $$ Answered by…