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Question Number 5902 by Ashis last updated on 04/Jun/16 $${solve}\:{x} \\ $$$$\mathrm{6}^{\mathrm{2}{x}+\mathrm{4}} \:\:=\mathrm{3}^{\mathrm{3}{x}} \:\mathrm{2}^{{x}+\mathrm{8}} \\ $$ Commented by prakash jain last updated on 04/Jun/16 $$\mathrm{6}^{\mathrm{2}{x}}…
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Question Number 71406 by mind is power last updated on 15/Oct/19 $$\mathrm{Hello}\: \\ $$$$\mathrm{Solve}\:\sqrt[{\mathrm{3}}]{\mathrm{x}^{\mathrm{2}} }−\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{x}\left(\mathrm{x}−\mathrm{1}\right)}+\mathrm{2}\sqrt[{\mathrm{3}}]{\mathrm{x}−\mathrm{1}}=\mathrm{0} \\ $$ Commented by Prithwish sen last updated on 15/Oct/19…
Question Number 136907 by leena12345 last updated on 27/Mar/21 $$\int\sqrt{\frac{\mathrm{2}+{x}}{\mathrm{2}−{x}}}{dx} \\ $$ Answered by Mathspace last updated on 27/Mar/21 $${let}\:{I}=\int\sqrt{\frac{\mathrm{2}+{x}}{\mathrm{2}−{x}}}{dx}\:\:{changement} \\ $$$$\sqrt{\frac{\mathrm{2}+{x}}{\mathrm{2}−{x}}}={t}\:{give}\:\frac{\mathrm{2}+{x}}{\mathrm{2}−{x}}={t}^{\mathrm{2}\:} \:\Rightarrow \\ $$$$\mathrm{2}+{x}=\mathrm{2}{t}^{\mathrm{2}}…
Question Number 5807 by Rasheed Soomro last updated on 28/May/16 $$\mathcal{T}{own}\:\boldsymbol{\mathrm{A}}\:\:{is}\:\:\mathrm{36}\:{kilometers}\:{from}\: \\ $$$${town}\:\boldsymbol{\mathrm{B}}.\:\:{Two}\:{persons}\:{start}\:{to}\:{travel} \\ $$$${at}\:{the}\:{same}\:{time},\:{one}\:{from}\:\boldsymbol{\mathrm{A}}\:{to}\:\boldsymbol{\mathrm{B}} \\ $$$${and}\:{other}\:{from}\:\boldsymbol{\mathrm{B}}\:{to}\:\boldsymbol{\mathrm{A}}.\:{After}\:{meeting} \\ $$$${in}\:{a}\:{way}\:{the}\:{first}\:{person}\:{covers}\:{the} \\ $$$${remaining}\:{distance}\:{in}\:\mathrm{2}\:{hours}\:{and} \\ $$$${the}\:{second}\:\:{in}\:\mathrm{8}\:{hours}.\:{Determine}\:{their} \\ $$$${speed}.\:\:\:\:\:\left(\mathrm{From}\:\mathrm{a}\:\mathrm{book}\right)…
Question Number 5802 by sanusihammed last updated on 28/May/16 $${Solve}\:{simultaneously} \\ $$$$ \\ $$$$\mathrm{2}{x}\:+\:{y}\:−\:{z}\:=\:\mathrm{8}\:\:\:\:\:\:\:………..\:\left({i}\right) \\ $$$${x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:+\mathrm{2}{z}^{\mathrm{2}} \:=\:\mathrm{14}\:\:\:\:……….\:\left({ii}\right) \\ $$$$\mathrm{3}{x}^{\mathrm{3}} \:+\:\mathrm{4}{y}^{\mathrm{3}} \:+\:{z}^{\mathrm{3}} \:=\:\mathrm{195}\:\:………\:\left({iii}\right) \\…
Question Number 5792 by sanusihammed last updated on 28/May/16 $${Solve}\:{simultaneously}\: \\ $$$$ \\ $$$$\mathrm{2}{x}\:+\:{y}\:−\:{z}\:=\:\mathrm{8}\:\:\:\:\:\:\:\:……\:{equation}\left({i}\right) \\ $$$${x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:+\:\mathrm{2}{z}^{\mathrm{2}} \:=\:\mathrm{14}\:\:….\:{equation}\left({ii}\right) \\ $$$$\mathrm{3}{x}^{\mathrm{3}} \:+\:\mathrm{4}{x}^{\mathrm{3}} \:+\:{z}^{\mathrm{3}} \:\:=\:\mathrm{195}\:\:…..\:{equation}\left({iii}\right) \\…
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