Question Number 5685 by sanusihammed last updated on 24/May/16 $${Find}\:{the}\:{value}\:{of}\:{x}\:. \\ $$$$ \\ $$$$\mathrm{9}^{{x}} \:=\:\mathrm{6}^{{x}} \:+\:\mathrm{4}^{{x}} \\ $$$$ \\ $$$${Please}\:{help}. \\ $$ Answered by prakash…
Question Number 5684 by sanusihammed last updated on 24/May/16 $${Find}\:{the}\:{value}\:{of}\:{x}\:.\: \\ $$$$ \\ $$$${x}^{\left({x}\:+\:\mathrm{2}\right)} \:=\:\left({x}\:+\:\mathrm{2}\right)^{{x}} \\ $$$$ \\ $$$${Thanks}\:{for}\:{your}\:{help}. \\ $$ Commented by prakash jain…
Question Number 136749 by EDWIN88 last updated on 25/Mar/21 $$\mathrm{Given}\:\mathrm{system}\:\mathrm{equation}\: \\ $$$$\:\begin{cases}{\mathrm{x}^{\mathrm{2}} +\mathrm{3xy}+\mathrm{y}^{\mathrm{2}} +\mathrm{1}=\mathrm{0}}\\{\mathrm{x}^{\mathrm{3}} +\mathrm{y}^{\mathrm{3}} −\mathrm{7}=\mathrm{0}}\end{cases}\:\mathrm{has}\:\mathrm{solution}\: \\ $$$$\left(\mathrm{x}_{\mathrm{1}} ,\mathrm{y}_{\mathrm{1}} \right)\:\&\left(\mathrm{x}_{\mathrm{2}} ,\mathrm{y}_{\mathrm{2}} \right)\:\mathrm{for}\:\mathrm{x},\mathrm{y}\in\mathbb{R}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{value} \\ $$$$\mathrm{of}\:\mathrm{x}_{\mathrm{1}} ^{\mathrm{2}}…
Question Number 5674 by sanusihammed last updated on 23/May/16 $${Find}\:{the}\:{value}\:{of}\:{x}\: \\ $$$$ \\ $$$${x}^{\left({x}\:+\:\mathrm{2}\right)} \:=\:\left({x}\:+\:\mathrm{2}\right)^{{x}} \\ $$$$ \\ $$$${Please}\:{help}. \\ $$ Terms of Service Privacy…
Question Number 136741 by JulioCesar last updated on 25/Mar/21 Answered by Dwaipayan Shikari last updated on 25/Mar/21 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}!−\mathrm{1}}{{x}}=\frac{\Gamma\left({x}+\mathrm{1}\right)−\mathrm{1}}{{x}}=\frac{\Gamma'\left({x}+\mathrm{1}\right)}{\mathrm{1}}=\Gamma'\left(\mathrm{1}\right)=−\gamma \\ $$ Terms of Service Privacy…
Question Number 5673 by sanusihammed last updated on 23/May/16 $${Using}\:{inductive}\:{method}.\:{prove}\:{that}\:.. \\ $$$$ \\ $$$$\mathrm{7}^{\mathrm{2}{n}} \:+\:\mathrm{16}{n}\:−\:\mathrm{1}\:{is}\:{divisible}\:{by}\:\mathrm{4} \\ $$$$ \\ $$$${please}\:{help}. \\ $$ Commented by Rasheed Soomro…
Question Number 71196 by Rio Michael last updated on 12/Oct/19 $${the}\:{curve}\:{y}\:=\:{f}\left({x}\right),\:{when}\:{f}\left({x}\right)\:{is}\:{a}\:{quadratic}\:{expression}\:{has}\: \\ $$$${a}\:{maximum}\:{value}\:{point}\:{at}\:\left(\mathrm{1},\mathrm{4}\right).\:{The}\:{curve}\:{touches}\:{the}\:{line} \\ $$$$\mathrm{6}{x}\:+\:{y}\:=\:\mathrm{13}.\:{Find}\:{the}\:{value}\:{of}\:{x}\:{for}\:{which}\:{y}\:=\:\mathrm{8} \\ $$ Answered by MJS last updated on 12/Oct/19 $${f}\left({x}\right)\:\mathrm{is}\:\mathrm{quadratic}\:\Leftrightarrow\:{y}={ax}^{\mathrm{2}}…
Question Number 71172 by aliesam last updated on 12/Oct/19 $${find}\:{fhe}\:{range} \\ $$$$ \\ $$$${f}\left({x}\right)=\frac{\mathrm{4}}{\mathrm{1}+\sqrt{{x}}} \\ $$ Commented by kaivan.ahmadi last updated on 12/Oct/19 $$\sqrt{{x}}\geqslant\mathrm{0}\Rightarrow\mathrm{1}+\sqrt{{x}}\geqslant\mathrm{1}\Rightarrow\frac{\mathrm{4}}{\mathrm{1}+\sqrt{{x}}}\leqslant\mathrm{4} \\…
Question Number 136703 by mathlove last updated on 25/Mar/21 $$\sqrt{\sqrt{{x}}\:^{\mathrm{log}\:{x}} }={x}\:\:\:\:\:\:\:{faind}\:\:{x} \\ $$ Commented by yutytfjh67ihd last updated on 25/Mar/21 Commented by MJS_new last updated…
Question Number 5627 by Rasheed Soomro last updated on 23/May/16 $$\mathrm{Determine}\:\mathrm{interval}\:\mathrm{in}\:\mathrm{which} \\ $$$$\mathrm{2}^{\mathrm{x}} \geqslant\mathrm{x}^{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com