Question Number 6666 by Tawakalitu. last updated on 10/Jul/16 $${Solve}\:{the}\:{simultaneous}\:{equation}. \\ $$$$ \\ $$$${x}^{{y}} \:+\:{y}^{{x}} \:=\:\mathrm{17}\:\:\:………….\:{equation}\:\left({i}\right) \\ $$$${x}\:+\:{y}\:=\:\mathrm{5}\:\:\:………………\:{equation}\:\left({ii}\right) \\ $$$$ \\ $$$${Please}\:{help}\:!!! \\ $$ Commented…
Question Number 72190 by oyemi kemewari last updated on 26/Oct/19 $$\mathrm{3}^{\mathrm{x}} +\mathrm{4}^{\mathrm{x}} =\mathrm{5}^{\mathrm{x}} \\ $$ Commented by oyemi kemewari last updated on 26/Oct/19 find x Commented…
Question Number 72185 by aliesam last updated on 25/Oct/19 Commented by Rasheed.Sindhi last updated on 26/Oct/19 $$\left\{{a},{b},{c}\right\}\equiv\left\{\mathrm{2},\mathrm{3},\mathrm{5}\right\} \\ $$$$ \\ $$ Commented by aliesam last…
Question Number 72175 by mr W last updated on 26/Oct/19 $$\left(\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} −\mathrm{1}\right)^{\mathrm{3}} =\boldsymbol{{x}}^{\mathrm{2}} \boldsymbol{{y}}^{\mathrm{3}} \\ $$$$ \\ $$$${how}\:{large}\:\left({area}\right)\:{is}\:{your}\:{heart}\:\heartsuit\:? \\ $$ Commented by mr W…
Question Number 137700 by peter frank last updated on 05/Apr/21 Commented by mr W last updated on 05/Apr/21 $${it}'{s}\:{not}\:{true}! \\ $$$${example}: \\ $$$${b}={c}=−\mathrm{1},\:{a}=\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{2}}} \\ $$$$\frac{\mathrm{1}}{{a}^{\mathrm{3}}…
Question Number 137698 by JulioCesar last updated on 05/Apr/21 Commented by peter frank last updated on 06/Apr/21 $${you}\:{forgot}\:{to}\:{set}\:{a}\:{limt} \\ $$ Answered by peter frank last…
Question Number 6612 by Temp last updated on 05/Jul/16 $${S}=\sqrt{\mathrm{2}+\sqrt{\mathrm{4}+\sqrt{\mathrm{6}+\sqrt{…}}}} \\ $$$${S}=??? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137665 by 676597498 last updated on 05/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 6590 by Temp last updated on 04/Jul/16 $$\mathrm{Solve}\:\mathrm{for}\:{a} \\ $$$$\frac{{a}^{\mathrm{2}} +\mathrm{1}}{{a}}=\frac{{a}}{\mathrm{1}−{a}^{\mathrm{2}} } \\ $$ Commented by nburiburu last updated on 04/Jul/16 $$\mathrm{1}−{a}^{\mathrm{4}} ={a}^{\mathrm{2}}…
Question Number 72118 by psyche last updated on 24/Oct/19 Commented by psyche last updated on 24/Oct/19 $${Question}\:\mathrm{1}. \\ $$ Terms of Service Privacy Policy Contact:…