Category: Algebra

Question Number 4075 by Yozzii last updated on 27/Dec/15 Answered by prakash jain last updated on 28/Dec/15 $$\:^{\mathrm{2}{r}} {C}_{{r}} =\frac{\mathrm{2}{r}!}{{r}!{r}!} \\ $$$$\mathrm{2}^{{r}} \centerdot{r}!=\mathrm{2}\centerdot\mathrm{4}\centerdot\mathrm{6}\centerdot…\centerdot\mathrm{2}{r} \\ $$$$\mathrm{2}{r}!=\mathrm{1}\centerdot\mathrm{2}\centerdot\mathrm{3}\centerdot\mathrm{4}\centerdot…\centerdot\left(\mathrm{2}{r}−\mathrm{1}\right)\centerdot\mathrm{2}{r}…

Question Number 69594 by ahmadshahhimat775@gmail.com last updated on 25/Sep/19 Answered by MJS last updated on 25/Sep/19 $$\mathrm{2}\leqslant{n}\leqslant\mathrm{4}:\:\mathrm{2}^{{n}!} <\mathrm{2}^{{n}} ! \\ $$$$\mathrm{5}\leqslant{n}:\:\mathrm{2}^{{n}!} >\mathrm{2}^{{n}} ! \\ $$$$\mathrm{ln}\:\mathrm{2}^{{n}!}…

Question Number 135121 by oooooooo last updated on 10/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 135120 by oooooooo last updated on 10/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 135117 by oooooooo last updated on 10/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com