Question Number 136667 by mathlove last updated on 24/Mar/21 $${if}\:\:\:\:\:\:{f}\left({x}\right)={ax}^{\mathrm{2}} +{bx}+{c}\:\:\:\:\:\:{and}\:\:\:{f}\left(\mathrm{5}\right)=−\mathrm{3}{f}\left(\mathrm{2}\right) \\ $$$${an}\:{intersiction}\:\:{point}\:\:\left(−\mathrm{4},\mathrm{0}\right) \\ $$$${an}\:{the}\:\:{X}-{axis}\:\:\:\:\:{faind}\:{another}\:{point}\: \\ $$$${the}\:{X}-{axis} \\ $$$$ \\ $$ Answered by MJS_new last…
Question Number 5591 by FilupSmith last updated on 21/May/16 $$\mathrm{For}\:{x}^{{x}^{{x}^{…} } } ={a} \\ $$$$\therefore\:{x}^{{a}} ={a}\:\:\:\Rightarrow\:\:\:{x}={a}^{\frac{\mathrm{1}}{{a}}} \\ $$$$ \\ $$$$\mathrm{Is}\:\mathrm{this}\:\mathrm{true}? \\ $$$$\mathrm{When}\:\mathrm{is}\:\mathrm{it}\:\mathrm{not}\:\mathrm{true}? \\ $$ Commented…
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Question Number 136649 by liberty last updated on 24/Mar/21 $$ \\ $$What the value of series (4/2) + (4.7/2.6) + (4.7.10/2.6.10) + (4.7.10.13/2.6.10.14) +…? Commented…
Question Number 5568 by Rasheed Soomro last updated on 20/May/16 $$\mathrm{Solve}\:\mathrm{without}\:\mathrm{using}\:\mathrm{calculator} \\ $$$$\mathrm{4}^{\mathrm{x}} −\mathrm{3}^{\mathrm{x}+\frac{\mathrm{1}}{\mathrm{2}}} =\mathrm{3}^{\mathrm{x}−\frac{\mathrm{1}}{\mathrm{2}}} −\mathrm{2}^{\mathrm{2x}−\mathrm{1}} \\ $$ Answered by Yozzii last updated on 20/May/16…
Question Number 136636 by Raxreedoroid last updated on 24/Mar/21 $${b}={a}+{c} \\ $$$${y}={x}+{c} \\ $$$${x}={a}+{z} \\ $$$${y}={b}+{z} \\ $$$${x}=?,{y}=?,{z}=? \\ $$ Commented by mr W last…
Question Number 71082 by aliesam last updated on 11/Oct/19 $${prove}\:{that}\: \\ $$$$ \\ $$$$\mid\:\sqrt{\mid{x}\mid}\:−\:\sqrt{\mid{y}\mid}\:\mid\:\leqslant\:\sqrt{\mid{x}−{y}\mid}\: \\ $$$$ \\ $$ Answered by Henri Boucatchou last updated on…
Question Number 71089 by 20190927 last updated on 11/Oct/19 $$\left(\sqrt{\sqrt{\mathrm{2}}−\mathrm{1}}\right)^{\mathrm{x}} +\left(\sqrt{\sqrt{\mathrm{2}}+\mathrm{1}}\right)^{\mathrm{x}} =\mathrm{4} \\ $$ Answered by Henri Boucatchou last updated on 11/Oct/19 $$\:\sqrt{\mathrm{2}}\:+\:\mathrm{1}\:=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}\:−\:\mathrm{1}},\:\boldsymbol{{let}}\:\:\boldsymbol{{a}}\:=\:\sqrt{\sqrt{\mathrm{2}}−\mathrm{1}} \\ $$$$\:\left(\sqrt{\sqrt{\mathrm{2}}\:−\mathrm{1}}\right)^{\boldsymbol{{x}}}…
Question Number 136614 by bemath last updated on 24/Mar/21 $${If}\:{a}+\frac{\mathrm{1}}{{a}}\:=\:\mathrm{23}\:{then}\:\sqrt[{\mathrm{4}}]{{a}}\:+\:\frac{\mathrm{1}}{\:\sqrt[{\mathrm{4}}]{{a}}}\:=? \\ $$ Answered by mr W last updated on 24/Mar/21 $${a}+\frac{\mathrm{1}}{{a}}=\left(\sqrt{{a}}+\frac{\mathrm{1}}{\:\sqrt{{a}}}\right)^{\mathrm{2}} −\mathrm{2}=\mathrm{23} \\ $$$$\sqrt{{a}}+\frac{\mathrm{1}}{\:\sqrt{{a}}}=\mathrm{5} \\…