Menu Close

Category: Algebra

If-a-2-b-2-c-2-1-a-3-1-b-3-1-c-3-a-3-b-3-c-3-than-prove-that-a-b-c-Successive-Proportional-

Question Number 70040 by Shamim last updated on 30/Sep/19 $$\mathrm{If},\:\mathrm{a}^{\mathrm{2}} \mathrm{b}^{\mathrm{2}} \mathrm{c}^{\mathrm{2}} \left(\frac{\mathrm{1}}{\mathrm{a}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{b}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{c}^{\mathrm{3}} }\right)=\mathrm{a}^{\mathrm{3}} +\mathrm{b}^{\mathrm{3}} +\mathrm{c}^{\mathrm{3}} \:\mathrm{than} \\ $$$$\mathrm{prove}\:\mathrm{that}\:\mathrm{a},\mathrm{b},\mathrm{c}\:\mathrm{Successive}\:\mathrm{Proportional}. \\ $$ Commented by…

4-x-1-2x-x-2-1-2-x-1-6-1-x-2-

Question Number 4502 by #na last updated on 02/Feb/16 $$\frac{\mathrm{4}}{{x}−\mathrm{1}}−\frac{\mathrm{2}{x}}{{x}^{\mathrm{2}} +\mathrm{1}}−\frac{\mathrm{2}}{{x}+\mathrm{1}}+\frac{\mathrm{6}}{\mathrm{1}−{x}^{\mathrm{2}} } \\ $$ Answered by Rasheed Soomro last updated on 02/Feb/16 $$\frac{\mathrm{4}}{{x}−\mathrm{1}}−\frac{\mathrm{2}{x}}{{x}^{\mathrm{2}} +\mathrm{1}}−\frac{\mathrm{2}}{{x}+\mathrm{1}}−\frac{\mathrm{6}}{\left({x}−\mathrm{1}\right)\left({x}+\mathrm{1}\right)} \\…

By-murging-three-sequences-a-1-a-2-a-n-b-1-b-2-b-n-amp-c-1-c-2-c-n-a-new-sequence-a-1-b-1-c-1-a-2-b-2-c-2-a-n-b-n-c-n-is-produced-Determine-the-single-formula-

Question Number 4492 by RasheedSindhi last updated on 01/Feb/16 $$ \\ $$$${By}\:{murging}\:{three}\:{sequences} \\ $$$$\:{a}_{\mathrm{1}} ,{a}_{\mathrm{2}} ,…{a}_{{n}} \:,\:{b}_{\mathrm{1}} ,{b}_{\mathrm{2}} ,…,{b}_{{n}} \:\&\:{c}_{\mathrm{1}} ,{c}_{\mathrm{2}} ,…,{c}_{{n}} \\ $$$${a}\:{new}\:{sequence}\: \\…

By-murging-two-sequences-a-1-a-2-a-n-and-b-1-b-2-b-n-a-new-sequence-a-1-b-1-a-2-b-2-a-n-b-n-has-been-produced-Determine-a-single-formula-general-term-of-th

Question Number 4485 by Rasheed Soomro last updated on 31/Jan/16 $${By}\:\:{murging}\:\:{two}\:{sequences} \\ $$$$\:\:\:\:{a}_{\mathrm{1}} ,{a}_{\mathrm{2}} ,…{a}_{{n}} \:\:\:{and}\:\:{b}_{\mathrm{1}} ,{b}_{\mathrm{2}} ,…,{b}_{{n}} \\ $$$${a}\:{new}\:{sequence}\: \\ $$$$\:\:\:\:{a}_{\mathrm{1}} ,{b}_{\mathrm{1}} ,{a}_{\mathrm{2}} ,{b}_{\mathrm{2}}…

1-x-2-y-2-x-2-y-2-a-x-y-x-y-b-a-b-R-2-x-y-x-y-a-x-y-x-y-b-3-x-2-y-2-a-b-xy-x-3-y-3-

Question Number 69995 by behi83417@gmail.com last updated on 29/Sep/19 $$\:\:\mathrm{1}.\begin{cases}{\sqrt{\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{y}}^{\mathrm{2}} }+\sqrt{\boldsymbol{\mathrm{x}}^{\mathrm{2}} −\boldsymbol{\mathrm{y}}^{\mathrm{2}} }=\boldsymbol{\mathrm{a}}}\\{\sqrt{\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{y}}}+\sqrt{\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{y}}}=\boldsymbol{\mathrm{b}}}\end{cases}\:\:\:\:\:\left[\boldsymbol{\mathrm{a}},\boldsymbol{\mathrm{b}}\in\boldsymbol{\mathrm{R}}^{+} \right] \\ $$$$ \\ $$$$\:\:\:\mathrm{2}.\begin{cases}{\sqrt{\sqrt{\mathrm{x}}+\mathrm{y}}+\sqrt{\mathrm{x}+\sqrt{\mathrm{y}}}=\boldsymbol{\mathrm{a}}}\\{\sqrt{\sqrt{\mathrm{x}}−\mathrm{y}}+\sqrt{\mathrm{x}−\sqrt{\mathrm{y}}}=\boldsymbol{\mathrm{b}}}\end{cases} \\ $$$$\: \\ $$$$\:\:\:\mathrm{3}.\begin{cases}{\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{y}}^{\mathrm{2}} =\left(\boldsymbol{\mathrm{a}}−\boldsymbol{\mathrm{b}}\right)\boldsymbol{\mathrm{xy}}}\\{\boldsymbol{\mathrm{x}}^{\mathrm{3}}…

Define-2-3-and-3-2-

Question Number 4446 by Rasheed Soomro last updated on 28/Jan/16 $$\mathrm{Define}\:\mathrm{2}^{\sqrt{\mathrm{3}}} \:\mathrm{and}\:\mathrm{3}^{\sqrt{\mathrm{2}}} \:. \\ $$ Commented by Yozzii last updated on 29/Jan/16 $${Dedekind}\:{cuts}\:{of}\:{the}\:{real}\:{line}\:{might} \\ $$$${define}\:{each}\:{of}\:{those}\:{numbers}.\:…

A-sequence-is-given-by-3-2-2-3-5-4-4-5-Write-down-the-general-term-of-the-sequence-and-find-its-limit-

Question Number 4445 by Rasheed Soomro last updated on 28/Jan/16 $$\mathrm{A}\:\mathrm{sequence}\:\mathrm{is}\:\mathrm{given}\:\mathrm{by} \\ $$$$\:\:\:\:\frac{\mathrm{3}}{\mathrm{2}},\frac{\mathrm{2}}{\mathrm{3}},\frac{\mathrm{5}}{\mathrm{4}},\frac{\mathrm{4}}{\mathrm{5}},…. \\ $$$$\mathrm{Write}\:\mathrm{down}\:\mathrm{the}\:\mathrm{general}\:\mathrm{term}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{sequence}\:\mathrm{and}\:\mathrm{find}\:\mathrm{its}\:\mathrm{limit}. \\ $$ Commented by 123456 last updated on…