Category: Algebra

Question Number 204756 by York12 last updated on 27/Feb/24 $$$$ Commented by Rasheed.Sindhi last updated on 27/Feb/24 $$\mathrm{Wrong}!$$$$Givenconditionsatisfiedby:$$$$\:\:{a}=\mathrm{0},{b}=\mathrm{0},{c}=\mathrm{1} \…

Question Number 204805 by York12 last updated on 27/Feb/24 $$\mathrm{Why}\underset{n\to \mathrm{\infty }}{\lim }\left(x^n{u}_n\right)=0,\mathrm{When}{u}_n\mathrm{is}\mathrm{bounded}$$ Commented by mr W last updated on 27/Feb/24 $${only}\:{true}\:{if}\:\mid{x}\mid<\mathrm{1}.…

Question Number 204712 by cortano12 last updated on 26/Feb/24 $$\mathrm{Find}\mathrm{all}\mathrm{real}\mathrm{solution}$$$$\sqrt{{3\mathrm{x}}^2+\mathrm{x}-1}+\sqrt{{\mathrm{x}}^2-2\mathrm{x}-3}=$$$$\sqrt{{3\mathrm{x}}^2+3\mathrm{x}+5}+\sqrt{{\mathrm{x}}^2+3}$$ Commented by Rasheed.Sindhi last updated…

Question Number 204739 by hardmath last updated on 26/Feb/24 Answered by mr W last updated on 26/Feb/24 $$x^4+2x=-4$$$$\Rightarrow x^3+2=-\frac{4}{x}$$$$\Rightarrow\frac{{x}^{\mathrm{2}} }{{x}^{\mathrm{3}}…

Question Number 204701 by Abdullahrussell last updated on 25/Feb/24 Answered by A5T last updated on 25/Feb/24 $${x}^{\mathrm{3}} ={x}−\mathrm{2}\Rightarrow{x}^{\mathrm{4}} ={x}^{\mathrm{2}} −\mathrm{2}{x}\Rightarrow{x}^{\mathrm{5}} ={x}^{\mathrm{3}} −\mathrm{2}{x}^{\mathrm{2}} =−\mathrm{2}{x}^{\mathrm{2}} +{x}−\mathrm{2} \…