Question Number 5807 by Rasheed Soomro last updated on 28/May/16 $$\mathcal{T}{own}\:\boldsymbol{\mathrm{A}}\:\:{is}\:\:\mathrm{36}\:{kilometers}\:{from}\: \\ $$$${town}\:\boldsymbol{\mathrm{B}}.\:\:{Two}\:{persons}\:{start}\:{to}\:{travel} \\ $$$${at}\:{the}\:{same}\:{time},\:{one}\:{from}\:\boldsymbol{\mathrm{A}}\:{to}\:\boldsymbol{\mathrm{B}} \\ $$$${and}\:{other}\:{from}\:\boldsymbol{\mathrm{B}}\:{to}\:\boldsymbol{\mathrm{A}}.\:{After}\:{meeting} \\ $$$${in}\:{a}\:{way}\:{the}\:{first}\:{person}\:{covers}\:{the} \\ $$$${remaining}\:{distance}\:{in}\:\mathrm{2}\:{hours}\:{and} \\ $$$${the}\:{second}\:\:{in}\:\mathrm{8}\:{hours}.\:{Determine}\:{their} \\ $$$${speed}.\:\:\:\:\:\left(\mathrm{From}\:\mathrm{a}\:\mathrm{book}\right)…
Question Number 5802 by sanusihammed last updated on 28/May/16 $${Solve}\:{simultaneously} \\ $$$$ \\ $$$$\mathrm{2}{x}\:+\:{y}\:−\:{z}\:=\:\mathrm{8}\:\:\:\:\:\:\:………..\:\left({i}\right) \\ $$$${x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:+\mathrm{2}{z}^{\mathrm{2}} \:=\:\mathrm{14}\:\:\:\:……….\:\left({ii}\right) \\ $$$$\mathrm{3}{x}^{\mathrm{3}} \:+\:\mathrm{4}{y}^{\mathrm{3}} \:+\:{z}^{\mathrm{3}} \:=\:\mathrm{195}\:\:………\:\left({iii}\right) \\…
Question Number 5792 by sanusihammed last updated on 28/May/16 $${Solve}\:{simultaneously}\: \\ $$$$ \\ $$$$\mathrm{2}{x}\:+\:{y}\:−\:{z}\:=\:\mathrm{8}\:\:\:\:\:\:\:\:……\:{equation}\left({i}\right) \\ $$$${x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:+\:\mathrm{2}{z}^{\mathrm{2}} \:=\:\mathrm{14}\:\:….\:{equation}\left({ii}\right) \\ $$$$\mathrm{3}{x}^{\mathrm{3}} \:+\:\mathrm{4}{x}^{\mathrm{3}} \:+\:{z}^{\mathrm{3}} \:\:=\:\mathrm{195}\:\:…..\:{equation}\left({iii}\right) \\…
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Question Number 5785 by sanusihammed last updated on 27/May/16 $${Solve}\:{simultaneously} \\ $$$$ \\ $$$$\mathrm{2}{x}\:+\:{y}\:−\:{z}\:=\:\mathrm{8}\:\:\:………..\:\left({i}\right) \\ $$$${x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:+\:\mathrm{2}{z}^{\mathrm{2}} \:=\:\mathrm{14}\:……….\:\left({ii}\right) \\ $$$$\mathrm{3}{x}^{\mathrm{3}} \:+\:\mathrm{4}{y}^{\mathrm{3}} \:+\:{z}^{\mathrm{3}} \:=\:\mathrm{195}\:\:\:………..\:\left({iii}\right) \\…
Question Number 5783 by Rasheed Soomro last updated on 27/May/16 $$ \\ $$$$\mathcal{D}{etermine}: \\ $$$${a}^{{a}} +\left({ar}\right)^{{a}+{r}} +\left({ar}^{\mathrm{2}} \right)^{{a}+\mathrm{2}{r}} +…+\left({ar}^{{n}−\mathrm{1}} \right)^{{a}+\left({n}−\mathrm{1}\right){r}} \\ $$ Terms of Service…
Question Number 5784 by Rasheed Soomro last updated on 27/May/16 $$ \\ $$$$\mathcal{D}{etermine}: \\ $$$$\mathrm{1}+\frac{{a}+{r}}{{ar}}+\frac{{a}+\mathrm{2}{r}}{{ar}^{\mathrm{2}} }+…+\frac{{a}+\left({n}−\mathrm{1}\right){r}}{{ar}^{{n}−\mathrm{1}} } \\ $$ Answered by Yozzii last updated on…
Question Number 5782 by Rasheed Soomro last updated on 27/May/16 $$\mathrm{Why}\:\mathrm{x}+\mathrm{x}=\mathrm{2x}\:\:? \\ $$$$\mathrm{Explain}\:\mathrm{by}\:\mathrm{properties}/\mathrm{laws}. \\ $$ Answered by FilupSmith last updated on 27/May/16 $$\mathrm{if}\:\mathrm{you}\:\mathrm{have}\:\mathrm{a}\:\mathrm{basket}\:\mathrm{of} \\ $$$${x}\:\mathrm{apples}\:\mathrm{and}\:\mathrm{i}\:\mathrm{have}\:\mathrm{an}\:\mathrm{identical}\:\mathrm{basket}\:…
Question Number 5777 by FilupSmith last updated on 27/May/16 $$\exists{x}\in\mathbb{Z}^{+} :{x}={p}_{\mathrm{1}} {p}_{\mathrm{2}} …{p}_{{n}} \wedge\forall{p}\neq{x},\:{p}\in\mathbb{Z}^{+} \\ $$$$ \\ $$$${x}=\left({factors}\:{of}\:{p}_{\mathrm{1}} \right)\left({fact}.\:{p}_{\mathrm{2}} \right)…\left({fact}.\:{p}_{{n}} \right) \\ $$$$\mathrm{How}\:\mathrm{could}\:\mathrm{you}\:\mathrm{formally}\:\mathrm{write}\:\mathrm{the} \\ $$$$\mathrm{number}\:\mathrm{of}\:\mathrm{ways}\:\mathrm{you}\:\mathrm{can}\:\mathrm{write}\:{x}\:\mathrm{in}\:\mathrm{terms}…