Question Number 135298 by Ahmed1hamouda last updated on 12/Mar/21 Answered by mr W last updated on 12/Mar/21 $$\mathrm{1} \\ $$$${z}={x}+{yi} \\ $$$$\frac{\mathrm{1}}{{z}}=\frac{\mathrm{1}}{{x}+{yi}}=\frac{{x}−{yi}}{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} } \\…
Question Number 135285 by mnjuly1970 last updated on 11/Mar/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:{pre}−{calculus} \\ $$$$\:\:{if}\:\:\:\:\:\:\:{log}_{\mathrm{48}} ^{\mathrm{72}} +{log}_{\mathrm{54}} ^{\mathrm{12}} \:={k}\: \\ $$$$\:\:\:\:\:\:{then}\:\:{log}_{\:\mathrm{12}} ^{\:\mathrm{27}} \:\:=??? \\ $$$$\:\:\:\:\:\:\:\: \\ $$ Answered…
Question Number 69738 by Therealsincro last updated on 27/Sep/19 $${Sarah}\:{dances}\:{everyday}\:{of}\:{the}\:{week}, \\ $$$${including}\:{saturdays}\:{and}\:{sundays}. \\ $$$${In}\:{november}\:\mathrm{2018},\:{Sarah}\:{had}\:{to}\:{miss} \\ $$$${a}\:{few}\:{days}.\:{To}\:{control}\:{her}\:{absences} \\ $$$${she}\:{marks}\:{the}\:{day}\:{she}\:{missed}\:{class} \\ $$$${with}\:{a}\:\boldsymbol{{x}}\:{on}\:{the}\:{calendar}. \\ $$$${She}\:{marked}\:{the}\:\mathrm{5}{th},\:\mathrm{21}{st}\:{and}\:\mathrm{27}{th} \\ $$$${of}\:{november}. \\…
Question Number 69741 by ajfour last updated on 27/Sep/19 Commented by mr W last updated on 27/Sep/19 Commented by mr W last updated on 27/Sep/19…
Question Number 4176 by Yozzii last updated on 31/Dec/15 Commented by Yozzii last updated on 31/Dec/15 $${If}\:{it}'{s}\:{hard}\:{to}\:{read},\:{the}\:{info} \\ $$$${reads}\:{x}\geqslant{b}>\mathrm{0}. \\ $$ Commented by prakash jain…
Question Number 135230 by benjo_mathlover last updated on 11/Mar/21 $${A}\:{hockey}\:{team}\:{plays}\:{in}\:{an}\:{arena}\:{that} \\ $$$${has}\:{a}\:{seating}\:{capacity}\:{of}\:\mathrm{15},\mathrm{000} \\ $$$${spectators}.\:{With}\:{the}\:{ticket}\:{price} \\ $$$${seat}\:{at}\:\$\mathrm{14},\:{average}\:{attendance} \\ $$$${at}\:{recent}\:{games}\:{has}\:{been}\:\mathrm{9500}. \\ $$$${A}\:{market}\:{survey}\:{indicates}\:{that} \\ $$$${for}\:{each}\:{dollar}\:{the}\:{ticket}\:{price} \\ $$$${is}\:{lowered}\:,{the}\:{average}\:{attendance} \\…
Question Number 69681 by ajfour last updated on 26/Sep/19 Commented by ajfour last updated on 26/Sep/19 $${Q}.\mathrm{69496}\:\:\:\left({A}\:{try}..\right) \\ $$ Commented by ajfour last updated on…
Question Number 69662 by aliesam last updated on 26/Sep/19 $${prove}\:{that} \\ $$$$ \\ $$$$\frac{\mathrm{2}{x}^{\mathrm{3}} −{x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{1}}{{x}^{\mathrm{3}} +\mathrm{1}}\:+\:\frac{{x}^{\mathrm{3}} +\mathrm{1}}{{x}^{\mathrm{4}} −\mathrm{2}{x}^{\mathrm{3}} +\mathrm{3}{x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{1}}\:=\:\mathrm{2} \\ $$ Answered by…
Question Number 69665 by ozodbek last updated on 26/Sep/19 Commented by ozodbek last updated on 26/Sep/19 $$\mathrm{solve} \\ $$ Answered by mr W last updated…
Question Number 135191 by liberty last updated on 11/Mar/21 $$\begin{cases}{\mathrm{x}^{\mathrm{2}} −\mathrm{yz}\:=\:\mathrm{3}}\\{\mathrm{y}^{\mathrm{2}} −\:\mathrm{zx}\:=\:\mathrm{5}}\\{\mathrm{z}^{\mathrm{2}} −\mathrm{xy}\:=\:−\mathrm{1}}\end{cases} \\ $$$$\mathrm{solve}\:\mathrm{for}\:\mathrm{x}\:,\mathrm{y}\:\mathrm{and}\:\mathrm{z}. \\ $$ Answered by MJS_new last updated on 11/Mar/21 $${y}={px}\wedge{z}={qx}…