Question Number 134331 by Mikael_786 last updated on 02/Mar/21 $$\mathrm{cos}^{\mathrm{2}} \left(\frac{\mathrm{3}\pi}{\mathrm{2}}−\mathrm{x}\right)=\mathrm{cos}^{\mathrm{2}} \left(\mathrm{x}+\pi\right) \\ $$$$\mathrm{0}\leqslant\mathrm{x}\leqslant\pi \\ $$$$\mathrm{x}=? \\ $$ Answered by EDWIN88 last updated on 02/Mar/21…
Question Number 68768 by aliesam last updated on 15/Sep/19 $$\sqrt[{\mathrm{3}}]{\mathrm{2}{x}−\mathrm{1}}\:+\sqrt[{\mathrm{3}}]{{x}−\mathrm{1}}\:=\:\mathrm{1} \\ $$ Commented by kaivan.ahmadi last updated on 15/Sep/19 $${t}={x}−\mathrm{1}\Rightarrow{x}={t}+\mathrm{1}\Rightarrow \\ $$$$\sqrt[{\mathrm{3}}]{\mathrm{2}{t}+\mathrm{1}}+\sqrt[{\mathrm{3}}]{{t}}=\mathrm{1}\Rightarrow\sqrt[{\mathrm{3}}]{\mathrm{2}{t}+\mathrm{1}}=\mathrm{1}−\sqrt[{\mathrm{3}}]{{t}}\Rightarrow \\ $$$$\mathrm{2}{t}+\mathrm{1}=\mathrm{1}−\mathrm{3}\sqrt[{\mathrm{3}}]{{t}}+\mathrm{3}\sqrt[{\mathrm{3}}]{{t}^{\mathrm{2}} }−{t}\Rightarrow\mathrm{3}{t}=\mathrm{3}\sqrt[{\mathrm{3}}]{{t}}\left(\sqrt[{\mathrm{3}}]{{t}}−\mathrm{1}\right)\Rightarrow…
Question Number 134297 by mathlove last updated on 02/Mar/21 Answered by Ñï= last updated on 02/Mar/21 $$\frac{{d}}{{dx}}{ln}\left({x}^{{x}} +\mathrm{2}^{{x}^{{x}} } \right)=\frac{\mathrm{1}}{{x}^{{x}} +\mathrm{2}^{{x}^{{x}} } }\left[{x}^{{x}} \left({lnx}+\mathrm{1}\right)+\left({ln}\mathrm{2}\right)\mathrm{2}^{{x}^{{x}} }…
Question Number 3215 by prakash jain last updated on 07/Dec/15 $$\mathrm{Prove}\:\mathrm{that}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{circles}\:\mathrm{perimeter}\:\mathrm{to} \\ $$$$\mathrm{its}\:\mathrm{radius}\:\mathrm{is}\:\mathrm{constant}. \\ $$$$\mathrm{Proof}\:\mathrm{should}\:\mathrm{not}\:\mathrm{utilize}\:\mathrm{a}\:\mathrm{result}\:\mathrm{based} \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{above}\:\mathrm{fact}. \\ $$ Answered by Yozzi last updated on…
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Question Number 68740 by ahmadshah last updated on 15/Sep/19 Commented by Prithwish sen last updated on 15/Sep/19 $$\sqrt{\mathrm{30}\sqrt{\mathrm{30}\sqrt{\mathrm{30}\sqrt{\mathrm{30}}\sqrt{\mathrm{30}\left(\mathrm{30}^{\mathrm{2}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} }}}} \\ $$$$=\sqrt{\mathrm{30}\sqrt{\mathrm{30}\sqrt{\mathrm{30}\sqrt{\mathrm{30}}\sqrt{\left(\mathrm{30}\right)^{\mathrm{2}} }}}} \\ $$$$=\sqrt{\mathrm{30}\sqrt{\mathrm{30}\sqrt{\left(\mathrm{30}\right)^{\frac{\mathrm{5}}{\mathrm{2}}}…
Question Number 134278 by biswa162 last updated on 01/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 134269 by I want to learn more last updated on 01/Mar/21 $$\underset{\mathrm{k}\:\:\:=\:\:\:\:\mathrm{2}} {\overset{\mathrm{99}} {\sum}}\:\:\:\frac{\mathrm{k}^{\mathrm{2}} \:\:+\:\:\mathrm{1}}{\mathrm{k}^{\mathrm{2}} \:\:−\:\:\mathrm{1}} \\ $$ Answered by mr W last…
Question Number 68721 by ahmadshah last updated on 15/Sep/19 Commented by Prithwish sen last updated on 15/Sep/19 $$\mathrm{3} \\ $$ Answered by $@ty@m123 last updated…
Question Number 134255 by shaker last updated on 01/Mar/21 Commented by Dwaipayan Shikari last updated on 01/Mar/21 $${C}_{{m}} ^{{n}} \:\:\:\:\:\left({n}<{m}\right)\:{is}\:{not}\:{defined} \\ $$ Commented by mr…