Question Number 1497 by Rasheed Soomro last updated on 14/Aug/15 $$\mathrm{Find}\:\mathrm{complex}\:\mathrm{numbers}\:\alpha\:\mathrm{and}\:\beta\:\mathrm{such}\:\mathrm{that} \\ $$$$\alpha^{\mathrm{2}} =\beta^{\mathrm{3}} \:\:\mathrm{and}\:\:\beta^{\mathrm{2}} =\alpha^{\mathrm{3}} \\ $$ Commented by 123456 last updated on 14/Aug/15…
Question Number 67025 by Masumsiddiqui399@gmail.com last updated on 21/Aug/19 Commented by Rasheed.Sindhi last updated on 22/Aug/19 $${x}^{{x}^{{x}+\mathrm{5}} } =\:^{\mathrm{3}} \sqrt{\mathrm{3}} \\ $$$$\left({x}^{{x}^{{x}+\mathrm{5}} } \right)^{\mathrm{3}} =\left(\:^{\mathrm{3}}…
Question Number 1483 by Rasheed Ahmad last updated on 13/Aug/15 $$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\mathrm{a}+\left(\mathrm{b}+\mathrm{c}\right)+\mathrm{d}=\left(\mathrm{a}+\mathrm{c}\right)+\left(\mathrm{d}+\mathrm{b}\right) \\ $$ Commented by prakash jain last updated on 13/Aug/15 $$\mathrm{Basic}\:\mathrm{properties}\:\mathrm{of}\:+\:\mathrm{operator}.\:\mathrm{Or}\:\mathrm{is}\:\mathrm{it} \\…
Question Number 1466 by Rasheed Soomro last updated on 10/Aug/15 $${Without}\:{using}\:{calculus}\:{find}\:{stepwise}\:{solution}: \\ $$$$\underset{{x}\rightarrow−\propto} {{lim}}\:\frac{{a}^{{x}} −\mathrm{1}}{{x}}\:{where}\:{a}>\mathrm{1} \\ $$ Answered by 123456 last updated on 11/Aug/15 $${a}>\mathrm{1},{x}<\mathrm{0}\Rightarrow{a}^{{x}}…
Question Number 132535 by oooooooo last updated on 15/Feb/21 Answered by guyyy last updated on 15/Feb/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 66995 by Sayantan chakraborty last updated on 21/Aug/19 Commented by Sayantan chakraborty last updated on 21/Aug/19 $$\mathrm{Can}\:\mathrm{anybody}\:\mathrm{help}\:\mathrm{me}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{this}??? \\ $$ Commented by Prithwish sen…
Question Number 1439 by Rasheed Ahmad last updated on 04/Aug/15 $${Are}\:{there}\:{two}\:{complex}\:{numbers} \\ $$$${which}\:{are}\:{cube}\:{of}\:{one}\:{another}? \\ $$$${If}\:{yes}\:{what}\:{are}\:{they}? \\ $$ Answered by 123456 last updated on 04/Aug/15 $$\begin{cases}{{x}={y}^{\mathrm{3}}…
Question Number 66969 by mr W last updated on 21/Aug/19 Commented by mr W last updated on 21/Aug/19 $${Question}\:{from}\:{B}.{E}.{H}.{I}.\:{sir}\:{reposted}. \\ $$ Answered by mr W…
Question Number 132494 by mnjuly1970 last updated on 14/Feb/21 Commented by MJS_new last updated on 14/Feb/21 $$\mathrm{sharing}\:\mathrm{these}\:\mathrm{transformations} \\ $$$$\mathrm{we}\:\mathrm{have}\:\mathrm{to}\:\mathrm{check}\:\mathrm{all}\:\mathrm{solutions}!!! \\ $$$$ \\ $$$${a}^{\mathrm{1}/\mathrm{2}} +{b}^{\mathrm{1}/\mathrm{2}} ={c}^{\mathrm{1}/\mathrm{2}}…
Question Number 1418 by Rasheed Ahmad last updated on 04/Aug/15 $${Solve}\:{the}\:{following}\:{compound} \\ $$$${inequation}\:{in}\:{interval}\:\left(\mathrm{0},\:\mathrm{2}\pi\right), \\ $$$${tan}\frac{{x}}{\mathrm{2}}\:\leqslant\:−\mathrm{1}\:\:{and}\:\:{tan}\frac{{x}}{\mathrm{2}}\:<\:\mathrm{0}\:. \\ $$ Commented by 123456 last updated on 31/Jul/15 $$\mathrm{tan}\:\frac{\pi}{\mathrm{4}}=−\mathrm{tan}\:\frac{\mathrm{3}\pi}{\mathrm{4}}=\mathrm{tan}\:\frac{\mathrm{5}\pi}{\mathrm{4}}=−\mathrm{tan}\:\frac{\mathrm{7}\pi}{\mathrm{4}}=\mathrm{1}…