Question Number 1007 by tera last updated on 13/May/15 $$\left[{x}−\mathrm{2}\right]>−\mathrm{2}\:.\:\:{x}=….. \\ $$ Answered by prakash jain last updated on 13/May/15 $$\left({x}−\mathrm{2}\right)>−\mathrm{2}\Rightarrow{x}−\mathrm{2}+\mathrm{2}>−\mathrm{2}+\mathrm{2}\Rightarrow{x}>\mathrm{0} \\ $$ Terms of…
Question Number 989 by Madan pd gupta last updated on 13/May/15 $$\mathrm{3}+\mathrm{4} \\ $$ Answered by rpatle69@gmail.com last updated on 13/May/15 $$\mathrm{7} \\ $$ Terms…
Question Number 984 by 112358 last updated on 13/May/15 $${Show}\:{that}\:\frac{{x}\left({x}+\mathrm{1}\right)}{\mathrm{3}{x}−\mathrm{1}}>\mathrm{1}\:{given}\:{that}\:{x}>\frac{\mathrm{1}}{\mathrm{3}}\:. \\ $$ Commented by prakash jain last updated on 13/May/15 $$\mathrm{For}\:{x}=\mathrm{1}\:\mathrm{LHS}=\frac{\mathrm{1}×\mathrm{2}}{\mathrm{2}}=\mathrm{1}\ngtr\mathrm{1} \\ $$$$\mathrm{So}\:\mathrm{the}\:\mathrm{inequality}\:\mathrm{should}\:\mathrm{be} \\ $$$$\frac{{x}\left({x}+\mathrm{1}\right)}{\mathrm{3}{x}−\mathrm{1}}\geqslant\mathrm{1}…
Question Number 66508 by Masumsiddiqui399@gmail.com last updated on 16/Aug/19 Commented by Prithwish sen last updated on 16/Aug/19 $$\left(\sqrt{\mathrm{7}−\mathrm{4}\sqrt{\mathrm{3}}}\right)^{\mathrm{x}+\sqrt{\mathrm{x}+\mathrm{2}}} =\left(\mathrm{2}−\sqrt{\mathrm{3}}\right)^{\mathrm{x}+^{\mathrm{3}} \sqrt{\mathrm{2x}+\mathrm{4}}} \\ $$$$\because\mathrm{7}−\mathrm{4}\sqrt{\mathrm{3}}\:=\:\left(\mathrm{2}−\sqrt{\mathrm{3}}\right)^{\mathrm{2}} \\ $$$$\therefore\:\mathrm{x}+\sqrt{\mathrm{x}+\mathrm{2}}=\mathrm{x}+^{\mathrm{3}} \sqrt{\mathrm{2x}+\mathrm{1}}\:\:\Rightarrow\mathrm{x}=\mathrm{2}…
Question Number 132031 by mathlove last updated on 10/Feb/21 Commented by kaivan.ahmadi last updated on 10/Feb/21 $${p}\left({x}\right)={f}\left({x}\right)\left({x}−\mathrm{1}\right)+\mathrm{3}={g}\left({x}\right)\left({x}+\mathrm{1}\right)+\mathrm{7} \\ $$$${p}\left(\mathrm{1}\right)=\mathrm{3},{p}\left(−\mathrm{1}\right)=\mathrm{7} \\ $$$${p}\left({x}\right)={t}\left({x}\right)\left({x}^{\mathrm{2}} −\mathrm{1}\right)+{k}\left({x}\right) \\ $$$${p}\left(\mathrm{1}\right)={k}\left(\mathrm{1}\right)\Rightarrow{k}\left(\mathrm{1}\right)=\mathrm{3}\Rightarrow\left(\mathrm{1},\mathrm{3}\right)\in{k} \\…
Question Number 893 by Karting7442 last updated on 14/Apr/15 $$\:\:\frac{−\mathrm{12}+{x}}{\mathrm{11}}=−\mathrm{3}\:\:\:\:\:\:\:\:{check} \\ $$$$ \\ $$$$\:\:\:{what}\:{is}\:{x}?\:{also}\:{check}\:{it}. \\ $$ Answered by prakash jain last updated on 14/Apr/15 $$−\mathrm{12}+{x}=−\mathrm{33}…
Question Number 892 by Karting7442 last updated on 14/Apr/15 $$\frac{−\mathrm{5}+{x}}{\mathrm{22}}=−\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:{check} \\ $$$$\:\: \\ $$$$\:\:\:{what}\:{is}\:{x}?{also}\:{check}\:{it}. \\ $$ Answered by prakash jain last updated on 14/Apr/15 $$\frac{−\mathrm{5}+{x}}{\mathrm{22}}×\mathrm{22}=−\mathrm{1}×\mathrm{22}…
Question Number 888 by Karting7442 last updated on 14/Apr/15 $$\frac{{x}+\mathrm{9}}{\mathrm{2}}=\mathrm{3} \\ $$$${what}\:{is}\:{x}? \\ $$ Answered by 123456 last updated on 14/Apr/15 $$\frac{{x}+\mathrm{9}}{\mathrm{2}}=\mathrm{3} \\ $$$$\frac{{x}+\mathrm{9}}{\mathrm{2}}×\mathrm{2}=\mathrm{3}×\mathrm{2} \\…
Question Number 880 by arnav last updated on 11/Apr/15 $${Solve} \\ $$$$\frac{{x}+\mathrm{3}}{{x}−\mathrm{3}}<\mathrm{1} \\ $$ Answered by 123456 last updated on 11/Apr/15 $$\frac{{x}+\mathrm{3}}{{x}−\mathrm{3}}−\mathrm{1}<\mathrm{0} \\ $$$$\frac{{x}+\mathrm{3}−{x}+\mathrm{3}}{{x}−\mathrm{3}}<\mathrm{0} \\…
Question Number 867 by sagarwal last updated on 03/Apr/15 $$\mathrm{Solve} \\ $$$$\mathrm{4}{x}−\mathrm{3}{y}=\mathrm{7}{xy} \\ $$$$\mathrm{3}{x}+\mathrm{2}{y}=\mathrm{18}{xy} \\ $$ Commented by 123456 last updated on 03/Apr/15 $$\begin{cases}{\mathrm{4}{x}−\mathrm{3}{y}=\mathrm{7}{xy}}\\{\mathrm{3}{x}+\mathrm{2}{y}=\mathrm{18}{xy}}\end{cases} \\…